beta--> theta

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Morten Hjorth-Jensen
2025-09-14 20:26:06 +02:00
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@@ -391,7 +391,7 @@ document.write(`
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#linking-the-regression-analysis-with-a-statistical-interpretation">Linking the regression analysis with a statistical interpretation</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#assumptions-made">Assumptions made</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#expectation-value-and-variance">Expectation value and variance</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#expectation-value-and-variance-for-boldsymbol-beta">Expectation value and variance for <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span></a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#expectation-value-and-variance-for-boldsymbol-theta">Expectation value and variance for <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span></a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#deriving-ols-from-a-probability-distribution">Deriving OLS from a probability distribution</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#independent-and-identically-distributed-iid">Independent and Identically Distributed (iid)</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#maximum-likelihood-estimation-mle">Maximum Likelihood Estimation (MLE)</a></li>
@@ -474,7 +474,7 @@ move from a linear algebra analysis to a statistical analysis. In
particular, we will focus on what the regularization terms can result
in. We will amongst other things show that the regularization
parameter can reduce considerably the variance of the parameters
<span class="math notranslate nohighlight">\(\beta\)</span>.</p>
<span class="math notranslate nohighlight">\(\theta\)</span>.</p>
<p>On of the advantages of doing linear regression is that we actually end up with
analytical expressions for several statistical quantities.<br />
Standard least squares and Ridge regression allow us to
@@ -494,7 +494,7 @@ independent, i.e.:</p>
<p>The randomness of <span class="math notranslate nohighlight">\(\varepsilon_i\)</span> implies that
<span class="math notranslate nohighlight">\(\mathbf{y}_i\)</span> is also a random variable. In particular,
<span class="math notranslate nohighlight">\(\mathbf{y}_i\)</span> is normally distributed, because <span class="math notranslate nohighlight">\(\varepsilon_i \sim
\mathcal{N}(0, \sigma^2)\)</span> and <span class="math notranslate nohighlight">\(\mathbf{X}_{i,\ast} \, \boldsymbol{\beta}\)</span> is a
\mathcal{N}(0, \sigma^2)\)</span> and <span class="math notranslate nohighlight">\(\mathbf{X}_{i,\ast} \, \boldsymbol{\theta}\)</span> is a
non-random scalar. To specify the parameters of the distribution of
<span class="math notranslate nohighlight">\(\mathbf{y}_i\)</span> we need to calculate its first two moments.</p>
<p>Recall that <span class="math notranslate nohighlight">\(\boldsymbol{X}\)</span> is a matrix of dimensionality <span class="math notranslate nohighlight">\(n\times p\)</span>. The
@@ -514,7 +514,7 @@ which describe our data</p>
function <span class="math notranslate nohighlight">\(f\)</span> is approximated by <span class="math notranslate nohighlight">\(\boldsymbol{\tilde{y}}\)</span> where we want to minimize <span class="math notranslate nohighlight">\((\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\)</span>, our MSE, with</p>
<div class="math notranslate nohighlight">
\[
\boldsymbol{\tilde{y}} = \boldsymbol{X}\boldsymbol{\beta}.
\boldsymbol{\tilde{y}} = \boldsymbol{X}\boldsymbol{\theta}.
\]</div>
</section>
<section id="expectation-value-and-variance">
@@ -524,8 +524,8 @@ function <span class="math notranslate nohighlight">\(f\)</span> is approximated
\[
\begin{align*}
\mathbb{E}(y_i) &amp; =
\mathbb{E}(\mathbf{X}_{i, \ast} \, \boldsymbol{\beta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \beta,
\mathbb{E}(\mathbf{X}_{i, \ast} \, \boldsymbol{\theta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \theta,
\end{align*}
\]</div>
<p>while
@@ -535,83 +535,83 @@ its variance is</p>
\begin{align*} \mbox{Var}(y_i) &amp; = \mathbb{E} \{ [y_i
- \mathbb{E}(y_i)]^2 \} \, \, \, = \, \, \, \mathbb{E} ( y_i^2 ) -
[\mathbb{E}(y_i)]^2 \\ &amp; = \mathbb{E} [ ( \mathbf{X}_{i, \ast} \,
\beta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 \\ &amp;
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \boldsymbol{\beta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \beta)^2 \\ &amp; = ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \boldsymbol{\beta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2
\theta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 \\ &amp;
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \boldsymbol{\theta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \theta)^2 \\ &amp; = ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \boldsymbol{\theta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2
\\ &amp; = \mathbb{E}(\varepsilon_i^2 ) \, \, \, = \, \, \,
\mbox{Var}(\varepsilon_i) \, \, \, = \, \, \, \sigma^2.
\end{align*}
\end{split}\]</div>
<p>Hence, <span class="math notranslate nohighlight">\(y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta}, \sigma^2)\)</span>, that is <span class="math notranslate nohighlight">\(\boldsymbol{y}\)</span> follows a normal distribution with
mean value <span class="math notranslate nohighlight">\(\boldsymbol{X}\boldsymbol{\beta}\)</span> and variance <span class="math notranslate nohighlight">\(\sigma^2\)</span> (not be confused with the singular values of the SVD).</p>
<p>Hence, <span class="math notranslate nohighlight">\(y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta}, \sigma^2)\)</span>, that is <span class="math notranslate nohighlight">\(\boldsymbol{y}\)</span> follows a normal distribution with
mean value <span class="math notranslate nohighlight">\(\boldsymbol{X}\boldsymbol{\theta}\)</span> and variance <span class="math notranslate nohighlight">\(\sigma^2\)</span> (not be confused with the singular values of the SVD).</p>
</section>
<section id="expectation-value-and-variance-for-boldsymbol-beta">
<h2>Expectation value and variance for <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span><a class="headerlink" href="#expectation-value-and-variance-for-boldsymbol-beta" title="Link to this heading">#</a></h2>
<p>With the OLS expressions for the optimal parameters <span class="math notranslate nohighlight">\(\boldsymbol{\hat{\beta}}\)</span> we can evaluate the expectation value</p>
<section id="expectation-value-and-variance-for-boldsymbol-theta">
<h2>Expectation value and variance for <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span><a class="headerlink" href="#expectation-value-and-variance-for-boldsymbol-theta" title="Link to this heading">#</a></h2>
<p>With the OLS expressions for the optimal parameters <span class="math notranslate nohighlight">\(\boldsymbol{\hat{\theta}}\)</span> we can evaluate the expectation value</p>
<div class="math notranslate nohighlight">
\[
\mathbb{E}(\boldsymbol{\hat{\beta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\beta}=\boldsymbol{\beta}.
\mathbb{E}(\boldsymbol{\hat{\theta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\theta}=\boldsymbol{\theta}.
\]</div>
<p>This means that the estimator of the regression parameters is unbiased.</p>
<p>We can also calculate the variance</p>
<p>The variance of the optimal value <span class="math notranslate nohighlight">\(\boldsymbol{\hat{\beta}}\)</span> is</p>
<p>The variance of the optimal value <span class="math notranslate nohighlight">\(\boldsymbol{\hat{\theta}}\)</span> is</p>
<div class="math notranslate nohighlight">
\[\begin{split}
\begin{eqnarray*}
\mbox{Var}(\boldsymbol{\hat{\beta}}) &amp; = &amp; \mathbb{E} \{ [\boldsymbol{\beta} - \mathbb{E}(\boldsymbol{\beta})] [\boldsymbol{\beta} - \mathbb{E}(\boldsymbol{\beta})]^{T} \}
\mbox{Var}(\boldsymbol{\hat{\theta}}) &amp; = &amp; \mathbb{E} \{ [\boldsymbol{\theta} - \mathbb{E}(\boldsymbol{\theta})] [\boldsymbol{\theta} - \mathbb{E}(\boldsymbol{\theta})]^{T} \}
\\
&amp; = &amp; \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\beta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\beta}]^{T} \}
&amp; = &amp; \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\theta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\theta}]^{T} \}
\\
% &amp; = &amp; \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
% &amp; = &amp; \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
% &amp; = &amp; \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
% &amp; = &amp; \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
&amp; = &amp; (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
&amp; = &amp; (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
\\
&amp; = &amp; (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
&amp; = &amp; (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
% &amp; = &amp; (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% &amp; = &amp; (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% \\
% &amp; &amp; + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \boldsymbol{\beta} \boldsymbol{\beta}^T
% &amp; &amp; + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \boldsymbol{\theta} \boldsymbol{\theta}^T
\\
&amp; = &amp; \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
&amp; = &amp; \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
\, \, \, = \, \, \, \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1},
\end{eqnarray*}
\end{split}\]</div>
<p>where we have used that <span class="math notranslate nohighlight">\(\mathbb{E} (\mathbf{Y} \mathbf{Y}^{T}) =
\mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn}\)</span>. From <span class="math notranslate nohighlight">\(\mbox{Var}(\boldsymbol{\beta}) = \sigma^2
\mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn}\)</span>. From <span class="math notranslate nohighlight">\(\mbox{Var}(\boldsymbol{\theta}) = \sigma^2
\, (\mathbf{X}^{T} \mathbf{X})^{-1}\)</span>, one obtains an estimate of the
variance of the estimate of the <span class="math notranslate nohighlight">\(j\)</span>-th regression coefficient:
<span class="math notranslate nohighlight">\(\boldsymbol{\sigma}^2 (\boldsymbol{\beta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \)</span>. This may be used to
<span class="math notranslate nohighlight">\(\boldsymbol{\sigma}^2 (\boldsymbol{\theta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \)</span>. This may be used to
construct a confidence interval for the estimates.</p>
<p>In a similar way, we can obtain analytical expressions for say the
expectation values of the parameters <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span> and their variance
expectation values of the parameters <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span> and their variance
when we employ Ridge regression, allowing us again to define a confidence interval.</p>
<p>It is rather straightforward to show that</p>
<div class="math notranslate nohighlight">
\[
\mathbb{E} \big[ \boldsymbol{\beta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\boldsymbol{\beta}^{\mathrm{OLS}}.
\mathbb{E} \big[ \boldsymbol{\theta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\boldsymbol{\theta}^{\mathrm{OLS}}.
\]</div>
<p>We see clearly that
<span class="math notranslate nohighlight">\(\mathbb{E} \big[ \boldsymbol{\beta}^{\mathrm{Ridge}} \big] \not= \boldsymbol{\beta}^{\mathrm{OLS}}\)</span> for any <span class="math notranslate nohighlight">\(\lambda &gt; 0\)</span>. We say then that the ridge estimator is biased.</p>
<span class="math notranslate nohighlight">\(\mathbb{E} \big[ \boldsymbol{\theta}^{\mathrm{Ridge}} \big] \not= \boldsymbol{\theta}^{\mathrm{OLS}}\)</span> for any <span class="math notranslate nohighlight">\(\lambda &gt; 0\)</span>. We say then that the ridge estimator is biased.</p>
<p>We can also compute the variance as</p>
<div class="math notranslate nohighlight">
\[
\mbox{Var}[\boldsymbol{\beta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
\mbox{Var}[\boldsymbol{\theta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
\]</div>
<p>and it is easy to see that if the parameter <span class="math notranslate nohighlight">\(\lambda\)</span> goes to infinity then the variance of Ridge parameters <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span> goes to zero.</p>
<p>and it is easy to see that if the parameter <span class="math notranslate nohighlight">\(\lambda\)</span> goes to infinity then the variance of Ridge parameters <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span> goes to zero.</p>
<p>With this, we can compute the difference</p>
<div class="math notranslate nohighlight">
\[
\mbox{Var}[\boldsymbol{\beta}^{\mathrm{OLS}}]-\mbox{Var}(\boldsymbol{\beta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
\mbox{Var}[\boldsymbol{\theta}^{\mathrm{OLS}}]-\mbox{Var}(\boldsymbol{\theta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
\]</div>
<p>The difference is non-negative definite since each component of the
matrix product is non-negative definite.
This means the variance we obtain with the standard OLS will always for <span class="math notranslate nohighlight">\(\lambda &gt; 0\)</span> be larger than the variance of <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span> obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.</p>
This means the variance we obtain with the standard OLS will always for <span class="math notranslate nohighlight">\(\lambda &gt; 0\)</span> be larger than the variance of <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span> obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.</p>
</section>
<section id="deriving-ols-from-a-probability-distribution">
<h2>Deriving OLS from a probability distribution<a class="headerlink" href="#deriving-ols-from-a-probability-distribution" title="Link to this heading">#</a></h2>
@@ -621,14 +621,14 @@ that our output is determined by a given continuous function
distribution with zero mean value and an undetermined variance
<span class="math notranslate nohighlight">\(\sigma^2\)</span>.</p>
<p>We found above that the outputs <span class="math notranslate nohighlight">\(\boldsymbol{y}\)</span> have a mean value given by
<span class="math notranslate nohighlight">\(\boldsymbol{X}\hat{\boldsymbol{\beta}}\)</span> and variance <span class="math notranslate nohighlight">\(\sigma^2\)</span>. Since the entries to
<span class="math notranslate nohighlight">\(\boldsymbol{X}\hat{\boldsymbol{\theta}}\)</span> and variance <span class="math notranslate nohighlight">\(\sigma^2\)</span>. Since the entries to
the design matrix are not stochastic variables, we can assume that the
probability distribution of our targets is also a normal distribution
but now with mean value <span class="math notranslate nohighlight">\(\boldsymbol{X}\hat{\boldsymbol{\beta}}\)</span>. This means that a
but now with mean value <span class="math notranslate nohighlight">\(\boldsymbol{X}\hat{\boldsymbol{\theta}}\)</span>. This means that a
single output <span class="math notranslate nohighlight">\(y_i\)</span> is given by the Gaussian distribution</p>
<div class="math notranslate nohighlight">
\[
y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\beta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}.
y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\theta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}.
\]</div>
</section>
<section id="independent-and-identically-distributed-iid">
@@ -637,13 +637,13 @@ y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\beta}, \sigma^2)=\frac{1}{\
We define this distribution as</p>
<div class="math notranslate nohighlight">
\[
p(y_i, \boldsymbol{X}\vert\boldsymbol{\beta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]},
p(y_i, \boldsymbol{X}\vert\boldsymbol{\theta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]},
\]</div>
<p>which reads as finding the likelihood of an event <span class="math notranslate nohighlight">\(y_i\)</span> with the input variables <span class="math notranslate nohighlight">\(\boldsymbol{X}\)</span> given the parameters (to be determined) <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span>.</p>
<p>which reads as finding the likelihood of an event <span class="math notranslate nohighlight">\(y_i\)</span> with the input variables <span class="math notranslate nohighlight">\(\boldsymbol{X}\)</span> given the parameters (to be determined) <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span>.</p>
<p>Since these events are assumed to be independent and identicall distributed we can build the probability distribution function (PDF) for all possible event <span class="math notranslate nohighlight">\(\boldsymbol{y}\)</span> as the product of the single events, that is we have</p>
<div class="math notranslate nohighlight">
\[
p(\boldsymbol{y},\boldsymbol{X}\vert\boldsymbol{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta}).
p(\boldsymbol{y},\boldsymbol{X}\vert\boldsymbol{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta}).
\]</div>
<p>We will write this in a more compact form reserving <span class="math notranslate nohighlight">\(\boldsymbol{D}\)</span> for the domain of events, including the ouputs (targets) and the inputs. That is
in case we have a simple one-dimensional input and output case</p>
@@ -655,9 +655,9 @@ in case we have a simple one-dimensional input and output case</p>
We can now rewrite the above probability as</p>
<div class="math notranslate nohighlight">
\[
p(\boldsymbol{D}\vert\boldsymbol{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}.
p(\boldsymbol{D}\vert\boldsymbol{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}.
\]</div>
<p>It is a conditional probability (see below) and reads as the likelihood of a domain of events <span class="math notranslate nohighlight">\(\boldsymbol{D}\)</span> given a set of parameters <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span>.</p>
<p>It is a conditional probability (see below) and reads as the likelihood of a domain of events <span class="math notranslate nohighlight">\(\boldsymbol{D}\)</span> given a set of parameters <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span>.</p>
</section>
<section id="maximum-likelihood-estimation-mle">
<h2>Maximum Likelihood Estimation (MLE)<a class="headerlink" href="#maximum-likelihood-estimation-mle" title="Link to this heading">#</a></h2>
@@ -667,7 +667,7 @@ given some observed data. This is achieved by maximizing a likelihood
function so that, under the assumed statistical model, the observed
data is the most probable.</p>
<p>We will assume here that our events are given by the above Gaussian
distribution and we will determine the optimal parameters <span class="math notranslate nohighlight">\(\beta\)</span> by
distribution and we will determine the optimal parameters <span class="math notranslate nohighlight">\(\theta\)</span> by
maximizing the above PDF. However, computing the derivatives of a
product function is cumbersome and can easily lead to overflow and/or
underflowproblems, with potentials for loss of numerical precision.</p>
@@ -684,22 +684,22 @@ is equivalent to the maximization/minimization of the function itself.</p>
<p>We could now define a new cost function to minimize, namely the negative logarithm of the above PDF</p>
<div class="math notranslate nohighlight">
\[
C(\boldsymbol{\beta}=-\log{\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta})},
C(\boldsymbol{\theta}=-\log{\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta})},
\]</div>
<p>which becomes</p>
<div class="math notranslate nohighlight">
\[
C(\boldsymbol{\beta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\beta})\vert\vert_2^2}{2\sigma^2}.
C(\boldsymbol{\theta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\theta})\vert\vert_2^2}{2\sigma^2}.
\]</div>
<p>Taking the derivative of the <em>new</em> cost function with respect to the parameters <span class="math notranslate nohighlight">\(\beta\)</span> we recognize our familiar OLS equation, namely</p>
<p>Taking the derivative of the <em>new</em> cost function with respect to the parameters <span class="math notranslate nohighlight">\(\theta\)</span> we recognize our familiar OLS equation, namely</p>
<div class="math notranslate nohighlight">
\[
\boldsymbol{X}^T\left(\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\beta}\right) =0,
\boldsymbol{X}^T\left(\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\theta}\right) =0,
\]</div>
<p>which leads to the well-known OLS equation for the optimal paramters <span class="math notranslate nohighlight">\(\beta\)</span></p>
<p>which leads to the well-known OLS equation for the optimal paramters <span class="math notranslate nohighlight">\(\theta\)</span></p>
<div class="math notranslate nohighlight">
\[
\hat{\boldsymbol{\beta}}^{\mathrm{OLS}}=\left(\boldsymbol{X}^T\boldsymbol{X}\right)^{-1}\boldsymbol{X}^T\boldsymbol{y}!
\hat{\boldsymbol{\theta}}^{\mathrm{OLS}}=\left(\boldsymbol{X}^T\boldsymbol{X}\right)^{-1}\boldsymbol{X}^T\boldsymbol{y}!
\]</div>
<p>Next week we will make a similar analysis for Ridge and Lasso regression</p>
</section>
@@ -926,23 +926,23 @@ finite <span class="math notranslate nohighlight">\(m\)</span>, it is not always
<h2>Confidence Intervals<a class="headerlink" href="#confidence-intervals" title="Link to this heading">#</a></h2>
<p>Confidence intervals are used in statistics and represent a type of estimate
computed from the observed data. This gives a range of values for an
unknown parameter such as the parameters <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span> from linear regression.</p>
<p>With the OLS expressions for the parameters <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span> we found
<span class="math notranslate nohighlight">\(\mathbb{E}(\boldsymbol{\beta}) = \boldsymbol{\beta}\)</span>, which means that the estimator of the regression parameters is unbiased.</p>
unknown parameter such as the parameters <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span> from linear regression.</p>
<p>With the OLS expressions for the parameters <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span> we found
<span class="math notranslate nohighlight">\(\mathbb{E}(\boldsymbol{\theta}) = \boldsymbol{\theta}\)</span>, which means that the estimator of the regression parameters is unbiased.</p>
<p>In the exercises this week we show that the variance of the estimate of the <span class="math notranslate nohighlight">\(j\)</span>-th regression coefficient is
<span class="math notranslate nohighlight">\(\boldsymbol{\sigma}^2 (\boldsymbol{\beta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \)</span>.</p>
<span class="math notranslate nohighlight">\(\boldsymbol{\sigma}^2 (\boldsymbol{\theta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \)</span>.</p>
<p>This quantity can be used to
construct a confidence interval for the estimates.</p>
</section>
<section id="standard-approach-based-on-the-normal-distribution">
<h2>Standard Approach based on the Normal Distribution<a class="headerlink" href="#standard-approach-based-on-the-normal-distribution" title="Link to this heading">#</a></h2>
<p>We will assume that the parameters <span class="math notranslate nohighlight">\(\beta\)</span> follow a normal
<p>We will assume that the parameters <span class="math notranslate nohighlight">\(\theta\)</span> follow a normal
distribution. We can then define the confidence interval. Here we will be using as
shorthands <span class="math notranslate nohighlight">\(\mu_{\beta}\)</span> for the above mean value and <span class="math notranslate nohighlight">\(\sigma_{\beta}\)</span>
shorthands <span class="math notranslate nohighlight">\(\mu_{\theta}\)</span> for the above mean value and <span class="math notranslate nohighlight">\(\sigma_{\theta}\)</span>
for the standard deviation. We have then a confidence interval</p>
<div class="math notranslate nohighlight">
\[
\left(\mu_{\beta}\pm \frac{z\sigma_{\beta}}{\sqrt{n}}\right),
\left(\mu_{\theta}\pm \frac{z\sigma_{\theta}}{\sqrt{n}}\right),
\]</div>
<p>where <span class="math notranslate nohighlight">\(z\)</span> defines the level of certainty (or confidence). For a normal
distribution typical parameters are <span class="math notranslate nohighlight">\(z=2.576\)</span> which corresponds to a
@@ -956,11 +956,11 @@ Bootstrap method, why it works and various theorems related to it.</p>
</section>
<section id="resampling-methods-bootstrap-background">
<h2>Resampling methods: Bootstrap background<a class="headerlink" href="#resampling-methods-bootstrap-background" title="Link to this heading">#</a></h2>
<p>Since <span class="math notranslate nohighlight">\(\widehat{\beta} = \widehat{\beta}(\boldsymbol{X})\)</span> is a function of random variables,
<span class="math notranslate nohighlight">\(\widehat{\beta}\)</span> itself must be a random variable. Thus it has
<p>Since <span class="math notranslate nohighlight">\(\widehat{\theta} = \widehat{\theta}(\boldsymbol{X})\)</span> is a function of random variables,
<span class="math notranslate nohighlight">\(\widehat{\theta}\)</span> itself must be a random variable. Thus it has
a pdf, call this function <span class="math notranslate nohighlight">\(p(\boldsymbol{t})\)</span>. The aim of the bootstrap is to
estimate <span class="math notranslate nohighlight">\(p(\boldsymbol{t})\)</span> by the relative frequency of
<span class="math notranslate nohighlight">\(\widehat{\beta}\)</span>. You can think of this as using a histogram
<span class="math notranslate nohighlight">\(\widehat{\theta}\)</span>. You can think of this as using a histogram
in the place of <span class="math notranslate nohighlight">\(p(\boldsymbol{t})\)</span>. If the relative frequency closely
resembles <span class="math notranslate nohighlight">\(p(\vec{t})\)</span>, then using numerics, it is straight forward to
estimate all the interesting parameters of <span class="math notranslate nohighlight">\(p(\boldsymbol{t})\)</span> using point
@@ -968,18 +968,18 @@ estimators.</p>
</section>
<section id="resampling-methods-more-bootstrap-background">
<h2>Resampling methods: More Bootstrap background<a class="headerlink" href="#resampling-methods-more-bootstrap-background" title="Link to this heading">#</a></h2>
<p>In the case that <span class="math notranslate nohighlight">\(\widehat{\beta}\)</span> has
<p>In the case that <span class="math notranslate nohighlight">\(\widehat{\theta}\)</span> has
more than one component, and the components are independent, we use the
same estimator on each component separately. If the probability
density function of <span class="math notranslate nohighlight">\(X_i\)</span>, <span class="math notranslate nohighlight">\(p(x)\)</span>, had been known, then it would have
been straightforward to do this by:</p>
<ol class="arabic simple">
<li><p>Drawing lots of numbers from <span class="math notranslate nohighlight">\(p(x)\)</span>, suppose we call one such set of numbers <span class="math notranslate nohighlight">\((X_1^*, X_2^*, \cdots, X_n^*)\)</span>.</p></li>
<li><p>Then using these numbers, we could compute a replica of <span class="math notranslate nohighlight">\(\widehat{\beta}\)</span> called <span class="math notranslate nohighlight">\(\widehat{\beta}^*\)</span>.</p></li>
<li><p>Then using these numbers, we could compute a replica of <span class="math notranslate nohighlight">\(\widehat{\theta}\)</span> called <span class="math notranslate nohighlight">\(\widehat{\theta}^*\)</span>.</p></li>
</ol>
<p>By repeated use of the above two points, many
estimates of <span class="math notranslate nohighlight">\(\widehat{\beta}\)</span> can be obtained. The
idea is to use the relative frequency of <span class="math notranslate nohighlight">\(\widehat{\beta}^*\)</span>
estimates of <span class="math notranslate nohighlight">\(\widehat{\theta}\)</span> can be obtained. The
idea is to use the relative frequency of <span class="math notranslate nohighlight">\(\widehat{\theta}^*\)</span>
(think of a histogram) as an estimate of <span class="math notranslate nohighlight">\(p(\boldsymbol{t})\)</span>.</p>
</section>
<section id="resampling-methods-bootstrap-approach">
@@ -1000,18 +1000,18 @@ result in some asymptotic sense? The answer is yes.</p>
<ol class="arabic simple">
<li><p>Draw with replacement <span class="math notranslate nohighlight">\(n\)</span> numbers for the observed variables <span class="math notranslate nohighlight">\(\boldsymbol{x} = (x_1,x_2,\cdots,x_n)\)</span>.</p></li>
<li><p>Define a vector <span class="math notranslate nohighlight">\(\boldsymbol{x}^*\)</span> containing the values which were drawn from <span class="math notranslate nohighlight">\(\boldsymbol{x}\)</span>.</p></li>
<li><p>Using the vector <span class="math notranslate nohighlight">\(\boldsymbol{x}^*\)</span> compute <span class="math notranslate nohighlight">\(\widehat{\beta}^*\)</span> by evaluating <span class="math notranslate nohighlight">\(\widehat \beta\)</span> under the observations <span class="math notranslate nohighlight">\(\boldsymbol{x}^*\)</span>.</p></li>
<li><p>Using the vector <span class="math notranslate nohighlight">\(\boldsymbol{x}^*\)</span> compute <span class="math notranslate nohighlight">\(\widehat{\theta}^*\)</span> by evaluating <span class="math notranslate nohighlight">\(\widehat \theta\)</span> under the observations <span class="math notranslate nohighlight">\(\boldsymbol{x}^*\)</span>.</p></li>
<li><p>Repeat this process <span class="math notranslate nohighlight">\(k\)</span> times.</p></li>
</ol>
<p>When you are done, you can draw a histogram of the relative frequency
of <span class="math notranslate nohighlight">\(\widehat \beta^*\)</span>. This is your estimate of the probability
of <span class="math notranslate nohighlight">\(\widehat \theta^*\)</span>. This is your estimate of the probability
distribution <span class="math notranslate nohighlight">\(p(t)\)</span>. Using this probability distribution you can
estimate any statistics thereof. In principle you never draw the
histogram of the relative frequency of <span class="math notranslate nohighlight">\(\widehat{\beta}^*\)</span>. Instead
histogram of the relative frequency of <span class="math notranslate nohighlight">\(\widehat{\theta}^*\)</span>. Instead
you use the estimators corresponding to the statistic of interest. For
example, if you are interested in estimating the variance of <span class="math notranslate nohighlight">\(\widehat
\beta\)</span>, apply the etsimator <span class="math notranslate nohighlight">\(\widehat \sigma^2\)</span> to the values
<span class="math notranslate nohighlight">\(\widehat \beta^*\)</span>.</p>
\theta\)</span>, apply the etsimator <span class="math notranslate nohighlight">\(\widehat \sigma^2\)</span> to the values
<span class="math notranslate nohighlight">\(\widehat \theta^*\)</span>.</p>
</section>
<section id="code-example-for-the-bootstrap-method">
<h2>Code example for the Bootstrap method<a class="headerlink" href="#code-example-for-the-bootstrap-method" title="Link to this heading">#</a></h2>
@@ -1096,12 +1096,12 @@ tasks. Consider a dataset <span class="math notranslate nohighlight">\(\mathcal{
<p>where <span class="math notranslate nohighlight">\(\epsilon\)</span> is normally distributed with mean zero and standard deviation <span class="math notranslate nohighlight">\(\sigma^2\)</span>.</p>
<p>In our derivation of the ordinary least squares method we defined then
an approximation to the function <span class="math notranslate nohighlight">\(f\)</span> in terms of the parameters
<span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span> and the design matrix <span class="math notranslate nohighlight">\(\boldsymbol{X}\)</span> which embody our model,
that is <span class="math notranslate nohighlight">\(\boldsymbol{\tilde{y}}=\boldsymbol{X}\boldsymbol{\beta}\)</span>.</p>
<p>Thereafter we found the parameters <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span> by optimizing the means squared error via the so-called cost function</p>
<span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span> and the design matrix <span class="math notranslate nohighlight">\(\boldsymbol{X}\)</span> which embody our model,
that is <span class="math notranslate nohighlight">\(\boldsymbol{\tilde{y}}=\boldsymbol{X}\boldsymbol{\theta}\)</span>.</p>
<p>Thereafter we found the parameters <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span> by optimizing the means squared error via the so-called cost function</p>
<div class="math notranslate nohighlight">
\[
C(\boldsymbol{X},\boldsymbol{\beta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right].
C(\boldsymbol{X},\boldsymbol{\theta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right].
\]</div>
<p>We can rewrite this as</p>
<div class="math notranslate nohighlight">
@@ -1734,7 +1734,7 @@ the jupyter-notebook from week 37 (September 12-16).</p>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#linking-the-regression-analysis-with-a-statistical-interpretation">Linking the regression analysis with a statistical interpretation</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#assumptions-made">Assumptions made</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#expectation-value-and-variance">Expectation value and variance</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#expectation-value-and-variance-for-boldsymbol-beta">Expectation value and variance for <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span></a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#expectation-value-and-variance-for-boldsymbol-theta">Expectation value and variance for <span class="math notranslate nohighlight">\(\boldsymbol{\theta}\)</span></a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#deriving-ols-from-a-probability-distribution">Deriving OLS from a probability distribution</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#independent-and-identically-distributed-iid">Independent and Identically Distributed (iid)</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#maximum-likelihood-estimation-mle">Maximum Likelihood Estimation (MLE)</a></li>
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+3 -3
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+5 -5
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -259,7 +259,7 @@ move from a linear algebra analysis to a statistical analysis. In
particular, we will focus on what the regularization terms can result
in. We will amongst other things show that the regularization
parameter can reduce considerably the variance of the parameters
\( \beta \).
\( \theta \).
</p>
<p>On of the advantages of doing linear regression is that we actually end up with
@@ -284,7 +284,7 @@ $$
<p>The randomness of \( \varepsilon_i \) implies that
\( \mathbf{y}_i \) is also a random variable. In particular,
\( \mathbf{y}_i \) is normally distributed, because \( \varepsilon_i \sim
\mathcal{N}(0, \sigma^2) \) and \( \mathbf{X}_{i,\ast} \, \boldsymbol{\beta} \) is a
\mathcal{N}(0, \sigma^2) \) and \( \mathbf{X}_{i,\ast} \, \boldsymbol{\theta} \) is a
non-random scalar. To specify the parameters of the distribution of
\( \mathbf{y}_i \) we need to calculate its first two moments.
</p>
+4 -4
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
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'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -265,7 +265,7 @@ $$
function \( f \) is approximated by \( \boldsymbol{\tilde{y}} \) where we want to minimize \( (\boldsymbol{y}-\boldsymbol{\tilde{y}})^2 \), our MSE, with
</p>
$$
\boldsymbol{\tilde{y}} = \boldsymbol{X}\boldsymbol{\beta}.
\boldsymbol{\tilde{y}} = \boldsymbol{X}\boldsymbol{\theta}.
$$
+13 -13
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -257,8 +257,8 @@ MathJax.Hub.Config({
$$
\begin{align*}
\mathbb{E}(y_i) & =
\mathbb{E}(\mathbf{X}_{i, \ast} \, \boldsymbol{\beta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \beta,
\mathbb{E}(\mathbf{X}_{i, \ast} \, \boldsymbol{\theta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \theta,
\end{align*}
$$
@@ -269,19 +269,19 @@ $$
\begin{align*} \mbox{Var}(y_i) & = \mathbb{E} \{ [y_i
- \mathbb{E}(y_i)]^2 \} \, \, \, = \, \, \, \mathbb{E} ( y_i^2 ) -
[\mathbb{E}(y_i)]^2 \\ & = \mathbb{E} [ ( \mathbf{X}_{i, \ast} \,
\beta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 \\ &
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \boldsymbol{\beta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \beta)^2 \\ & = ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \boldsymbol{\beta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2
\theta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 \\ &
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \boldsymbol{\theta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \theta)^2 \\ & = ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \boldsymbol{\theta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2
\\ & = \mathbb{E}(\varepsilon_i^2 ) \, \, \, = \, \, \,
\mbox{Var}(\varepsilon_i) \, \, \, = \, \, \, \sigma^2.
\end{align*}
$$
<p>Hence, \( y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta}, \sigma^2) \), that is \( \boldsymbol{y} \) follows a normal distribution with
mean value \( \boldsymbol{X}\boldsymbol{\beta} \) and variance \( \sigma^2 \) (not be confused with the singular values of the SVD).
<p>Hence, \( y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta}, \sigma^2) \), that is \( \boldsymbol{y} \) follows a normal distribution with
mean value \( \boldsymbol{X}\boldsymbol{\theta} \) and variance \( \sigma^2 \) (not be confused with the singular values of the SVD).
</p>
<p>
+26 -26
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -251,81 +251,81 @@ MathJax.Hub.Config({
<p>&nbsp;</p><p>&nbsp;</p><p>&nbsp;</p> <!-- add vertical space -->
<a name="part0006"></a>
<!-- !split -->
<h2 id="expectation-value-and-variance-for-boldsymbol-beta" class="anchor">Expectation value and variance for \( \boldsymbol{\beta} \) </h2>
<h2 id="expectation-value-and-variance-for-boldsymbol-theta" class="anchor">Expectation value and variance for \( \boldsymbol{\theta} \) </h2>
<p>With the OLS expressions for the optimal parameters \( \boldsymbol{\hat{\beta}} \) we can evaluate the expectation value</p>
<p>With the OLS expressions for the optimal parameters \( \boldsymbol{\hat{\theta}} \) we can evaluate the expectation value</p>
$$
\mathbb{E}(\boldsymbol{\hat{\beta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\beta}=\boldsymbol{\beta}.
\mathbb{E}(\boldsymbol{\hat{\theta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\theta}=\boldsymbol{\theta}.
$$
<p>This means that the estimator of the regression parameters is unbiased.</p>
<p>We can also calculate the variance</p>
<p>The variance of the optimal value \( \boldsymbol{\hat{\beta}} \) is</p>
<p>The variance of the optimal value \( \boldsymbol{\hat{\theta}} \) is</p>
$$
\begin{eqnarray*}
\mbox{Var}(\boldsymbol{\hat{\beta}}) & = & \mathbb{E} \{ [\boldsymbol{\beta} - \mathbb{E}(\boldsymbol{\beta})] [\boldsymbol{\beta} - \mathbb{E}(\boldsymbol{\beta})]^{T} \}
\mbox{Var}(\boldsymbol{\hat{\theta}}) & = & \mathbb{E} \{ [\boldsymbol{\theta} - \mathbb{E}(\boldsymbol{\theta})] [\boldsymbol{\theta} - \mathbb{E}(\boldsymbol{\theta})]^{T} \}
\\
& = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\beta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\beta}]^{T} \}
& = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\theta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\theta}]^{T} \}
\\
% & = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
% & = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
% & = & \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
% & = & \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
\\
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
% & = & (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% & = & (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% \\
% & & + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \boldsymbol{\beta} \boldsymbol{\beta}^T
% & & + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \boldsymbol{\theta} \boldsymbol{\theta}^T
\\
& = & \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
\, \, \, = \, \, \, \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1},
\end{eqnarray*}
$$
<p>where we have used that \( \mathbb{E} (\mathbf{Y} \mathbf{Y}^{T}) =
\mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn} \). From \( \mbox{Var}(\boldsymbol{\beta}) = \sigma^2
\mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn} \). From \( \mbox{Var}(\boldsymbol{\theta}) = \sigma^2
\, (\mathbf{X}^{T} \mathbf{X})^{-1} \), one obtains an estimate of the
variance of the estimate of the \( j \)-th regression coefficient:
\( \boldsymbol{\sigma}^2 (\boldsymbol{\beta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \). This may be used to
\( \boldsymbol{\sigma}^2 (\boldsymbol{\theta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \). This may be used to
construct a confidence interval for the estimates.
</p>
<p>In a similar way, we can obtain analytical expressions for say the
expectation values of the parameters \( \boldsymbol{\beta} \) and their variance
expectation values of the parameters \( \boldsymbol{\theta} \) and their variance
when we employ Ridge regression, allowing us again to define a confidence interval.
</p>
<p>It is rather straightforward to show that</p>
$$
\mathbb{E} \big[ \boldsymbol{\beta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\boldsymbol{\beta}^{\mathrm{OLS}}.
\mathbb{E} \big[ \boldsymbol{\theta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\boldsymbol{\theta}^{\mathrm{OLS}}.
$$
<p>We see clearly that
\( \mathbb{E} \big[ \boldsymbol{\beta}^{\mathrm{Ridge}} \big] \not= \boldsymbol{\beta}^{\mathrm{OLS}} \) for any \( \lambda > 0 \). We say then that the ridge estimator is biased.
\( \mathbb{E} \big[ \boldsymbol{\theta}^{\mathrm{Ridge}} \big] \not= \boldsymbol{\theta}^{\mathrm{OLS}} \) for any \( \lambda > 0 \). We say then that the ridge estimator is biased.
</p>
<p>We can also compute the variance as </p>
$$
\mbox{Var}[\boldsymbol{\beta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
\mbox{Var}[\boldsymbol{\theta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
$$
<p>and it is easy to see that if the parameter \( \lambda \) goes to infinity then the variance of Ridge parameters \( \boldsymbol{\beta} \) goes to zero. </p>
<p>and it is easy to see that if the parameter \( \lambda \) goes to infinity then the variance of Ridge parameters \( \boldsymbol{\theta} \) goes to zero. </p>
<p>With this, we can compute the difference </p>
$$
\mbox{Var}[\boldsymbol{\beta}^{\mathrm{OLS}}]-\mbox{Var}(\boldsymbol{\beta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
\mbox{Var}[\boldsymbol{\theta}^{\mathrm{OLS}}]-\mbox{Var}(\boldsymbol{\theta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
$$
<p>The difference is non-negative definite since each component of the
matrix product is non-negative definite.
This means the variance we obtain with the standard OLS will always for \( \lambda > 0 \) be larger than the variance of \( \boldsymbol{\beta} \) obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.
This means the variance we obtain with the standard OLS will always for \( \lambda > 0 \) be larger than the variance of \( \boldsymbol{\theta} \) obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.
</p>
<p>
+6 -6
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -261,15 +261,15 @@ distribution with zero mean value and an undetermined variance
</p>
<p>We found above that the outputs \( \boldsymbol{y} \) have a mean value given by
\( \boldsymbol{X}\hat{\boldsymbol{\beta}} \) and variance \( \sigma^2 \). Since the entries to
\( \boldsymbol{X}\hat{\boldsymbol{\theta}} \) and variance \( \sigma^2 \). Since the entries to
the design matrix are not stochastic variables, we can assume that the
probability distribution of our targets is also a normal distribution
but now with mean value \( \boldsymbol{X}\hat{\boldsymbol{\beta}} \). This means that a
but now with mean value \( \boldsymbol{X}\hat{\boldsymbol{\theta}} \). This means that a
single output \( y_i \) is given by the Gaussian distribution
</p>
$$
y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\beta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}.
y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\theta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}.
$$
+8 -8
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -257,15 +257,15 @@ MathJax.Hub.Config({
We define this distribution as
</p>
$$
p(y_i, \boldsymbol{X}\vert\boldsymbol{\beta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]},
p(y_i, \boldsymbol{X}\vert\boldsymbol{\theta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]},
$$
<p>which reads as finding the likelihood of an event \( y_i \) with the input variables \( \boldsymbol{X} \) given the parameters (to be determined) \( \boldsymbol{\beta} \).</p>
<p>which reads as finding the likelihood of an event \( y_i \) with the input variables \( \boldsymbol{X} \) given the parameters (to be determined) \( \boldsymbol{\theta} \).</p>
<p>Since these events are assumed to be independent and identicall distributed we can build the probability distribution function (PDF) for all possible event \( \boldsymbol{y} \) as the product of the single events, that is we have</p>
$$
p(\boldsymbol{y},\boldsymbol{X}\vert\boldsymbol{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta}).
p(\boldsymbol{y},\boldsymbol{X}\vert\boldsymbol{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta}).
$$
<p>We will write this in a more compact form reserving \( \boldsymbol{D} \) for the domain of events, including the ouputs (targets) and the inputs. That is
@@ -279,10 +279,10 @@ $$
We can now rewrite the above probability as
</p>
$$
p(\boldsymbol{D}\vert\boldsymbol{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}.
p(\boldsymbol{D}\vert\boldsymbol{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}.
$$
<p>It is a conditional probability (see below) and reads as the likelihood of a domain of events \( \boldsymbol{D} \) given a set of parameters \( \boldsymbol{\beta} \).</p>
<p>It is a conditional probability (see below) and reads as the likelihood of a domain of events \( \boldsymbol{D} \) given a set of parameters \( \boldsymbol{\theta} \).</p>
<p>
<!-- navigation buttons at the bottom of the page -->
+4 -4
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
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'expectation-value-and-variance-for-boldsymbol-theta'),
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2,
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -261,7 +261,7 @@ data is the most probable.
</p>
<p>We will assume here that our events are given by the above Gaussian
distribution and we will determine the optimal parameters \( \beta \) by
distribution and we will determine the optimal parameters \( \theta \) by
maximizing the above PDF. However, computing the derivatives of a
product function is cumbersome and can easily lead to overflow and/or
underflowproblems, with potentials for loss of numerical precision.
+9 -9
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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'expectation-value-and-variance-for-boldsymbol-theta'),
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -256,23 +256,23 @@ MathJax.Hub.Config({
<p>We could now define a new cost function to minimize, namely the negative logarithm of the above PDF</p>
$$
C(\boldsymbol{\beta}=-\log{\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta})},
C(\boldsymbol{\theta}=-\log{\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta})},
$$
<p>which becomes</p>
$$
C(\boldsymbol{\beta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\beta})\vert\vert_2^2}{2\sigma^2}.
C(\boldsymbol{\theta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\theta})\vert\vert_2^2}{2\sigma^2}.
$$
<p>Taking the derivative of the <em>new</em> cost function with respect to the parameters \( \beta \) we recognize our familiar OLS equation, namely</p>
<p>Taking the derivative of the <em>new</em> cost function with respect to the parameters \( \theta \) we recognize our familiar OLS equation, namely</p>
$$
\boldsymbol{X}^T\left(\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\beta}\right) =0,
\boldsymbol{X}^T\left(\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\theta}\right) =0,
$$
<p>which leads to the well-known OLS equation for the optimal paramters \( \beta \)</p>
<p>which leads to the well-known OLS equation for the optimal paramters \( \theta \)</p>
$$
\hat{\boldsymbol{\beta}}^{\mathrm{OLS}}=\left(\boldsymbol{X}^T\boldsymbol{X}\right)^{-1}\boldsymbol{X}^T\boldsymbol{y}!
\hat{\boldsymbol{\theta}}^{\mathrm{OLS}}=\left(\boldsymbol{X}^T\boldsymbol{X}\right)^{-1}\boldsymbol{X}^T\boldsymbol{y}!
$$
<p>Next week we will make a similar analysis for Ridge and Lasso regression</p>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
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<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
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<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
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<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
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'expectation-value-and-variance-for-boldsymbol-theta'),
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
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'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
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'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+7 -7
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -255,15 +255,15 @@ MathJax.Hub.Config({
<p>Confidence intervals are used in statistics and represent a type of estimate
computed from the observed data. This gives a range of values for an
unknown parameter such as the parameters \( \boldsymbol{\beta} \) from linear regression.
unknown parameter such as the parameters \( \boldsymbol{\theta} \) from linear regression.
</p>
<p>With the OLS expressions for the parameters \( \boldsymbol{\beta} \) we found
\( \mathbb{E}(\boldsymbol{\beta}) = \boldsymbol{\beta} \), which means that the estimator of the regression parameters is unbiased.
<p>With the OLS expressions for the parameters \( \boldsymbol{\theta} \) we found
\( \mathbb{E}(\boldsymbol{\theta}) = \boldsymbol{\theta} \), which means that the estimator of the regression parameters is unbiased.
</p>
<p>In the exercises this week we show that the variance of the estimate of the \( j \)-th regression coefficient is
\( \boldsymbol{\sigma}^2 (\boldsymbol{\beta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \).
\( \boldsymbol{\sigma}^2 (\boldsymbol{\theta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \).
</p>
<p>This quantity can be used to
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -253,14 +253,14 @@ MathJax.Hub.Config({
<!-- !split -->
<h2 id="standard-approach-based-on-the-normal-distribution" class="anchor">Standard Approach based on the Normal Distribution </h2>
<p>We will assume that the parameters \( \beta \) follow a normal
<p>We will assume that the parameters \( \theta \) follow a normal
distribution. We can then define the confidence interval. Here we will be using as
shorthands \( \mu_{\beta} \) for the above mean value and \( \sigma_{\beta} \)
shorthands \( \mu_{\theta} \) for the above mean value and \( \sigma_{\theta} \)
for the standard deviation. We have then a confidence interval
</p>
$$
\left(\mu_{\beta}\pm \frac{z\sigma_{\beta}}{\sqrt{n}}\right),
\left(\mu_{\theta}\pm \frac{z\sigma_{\theta}}{\sqrt{n}}\right),
$$
<p>where \( z \) defines the level of certainty (or confidence). For a normal
+6 -6
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -253,11 +253,11 @@ MathJax.Hub.Config({
<!-- !split -->
<h2 id="resampling-methods-bootstrap-background" class="anchor">Resampling methods: Bootstrap background </h2>
<p>Since \( \widehat{\beta} = \widehat{\beta}(\boldsymbol{X}) \) is a function of random variables,
\( \widehat{\beta} \) itself must be a random variable. Thus it has
<p>Since \( \widehat{\theta} = \widehat{\theta}(\boldsymbol{X}) \) is a function of random variables,
\( \widehat{\theta} \) itself must be a random variable. Thus it has
a pdf, call this function \( p(\boldsymbol{t}) \). The aim of the bootstrap is to
estimate \( p(\boldsymbol{t}) \) by the relative frequency of
\( \widehat{\beta} \). You can think of this as using a histogram
\( \widehat{\theta} \). You can think of this as using a histogram
in the place of \( p(\boldsymbol{t}) \). If the relative frequency closely
resembles \( p(\vec{t}) \), then using numerics, it is straight forward to
estimate all the interesting parameters of \( p(\boldsymbol{t}) \) using point
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -253,7 +253,7 @@ MathJax.Hub.Config({
<!-- !split -->
<h2 id="resampling-methods-more-bootstrap-background" class="anchor">Resampling methods: More Bootstrap background </h2>
<p>In the case that \( \widehat{\beta} \) has
<p>In the case that \( \widehat{\theta} \) has
more than one component, and the components are independent, we use the
same estimator on each component separately. If the probability
density function of \( X_i \), \( p(x) \), had been known, then it would have
@@ -261,11 +261,11 @@ been straightforward to do this by:
</p>
<ol>
<li> Drawing lots of numbers from \( p(x) \), suppose we call one such set of numbers \( (X_1^*, X_2^*, \cdots, X_n^*) \).</li>
<li> Then using these numbers, we could compute a replica of \( \widehat{\beta} \) called \( \widehat{\beta}^* \).</li>
<li> Then using these numbers, we could compute a replica of \( \widehat{\theta} \) called \( \widehat{\theta}^* \).</li>
</ol>
<p>By repeated use of the above two points, many
estimates of \( \widehat{\beta} \) can be obtained. The
idea is to use the relative frequency of \( \widehat{\beta}^* \)
estimates of \( \widehat{\theta} \) can be obtained. The
idea is to use the relative frequency of \( \widehat{\theta}^* \)
(think of a histogram) as an estimate of \( p(\boldsymbol{t}) \).
</p>
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+8 -8
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -258,18 +258,18 @@ MathJax.Hub.Config({
<ol>
<li> Draw with replacement \( n \) numbers for the observed variables \( \boldsymbol{x} = (x_1,x_2,\cdots,x_n) \).</li>
<li> Define a vector \( \boldsymbol{x}^* \) containing the values which were drawn from \( \boldsymbol{x} \).</li>
<li> Using the vector \( \boldsymbol{x}^* \) compute \( \widehat{\beta}^* \) by evaluating \( \widehat \beta \) under the observations \( \boldsymbol{x}^* \).</li>
<li> Using the vector \( \boldsymbol{x}^* \) compute \( \widehat{\theta}^* \) by evaluating \( \widehat \theta \) under the observations \( \boldsymbol{x}^* \).</li>
<li> Repeat this process \( k \) times.</li>
</ol>
<p>When you are done, you can draw a histogram of the relative frequency
of \( \widehat \beta^* \). This is your estimate of the probability
of \( \widehat \theta^* \). This is your estimate of the probability
distribution \( p(t) \). Using this probability distribution you can
estimate any statistics thereof. In principle you never draw the
histogram of the relative frequency of \( \widehat{\beta}^* \). Instead
histogram of the relative frequency of \( \widehat{\theta}^* \). Instead
you use the estimators corresponding to the statistic of interest. For
example, if you are interested in estimating the variance of \( \widehat
\beta \), apply the etsimator \( \widehat \sigma^2 \) to the values
\( \widehat \beta^* \).
\theta \), apply the etsimator \( \widehat \sigma^2 \) to the values
\( \widehat \theta^* \).
</p>
<p>
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
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None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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'expectation-value-and-variance-for-boldsymbol-theta'),
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<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+7 -7
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
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'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
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'expectation-value-and-variance-for-boldsymbol-theta'),
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
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<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
@@ -270,13 +270,13 @@ $$
<p>In our derivation of the ordinary least squares method we defined then
an approximation to the function \( f \) in terms of the parameters
\( \boldsymbol{\beta} \) and the design matrix \( \boldsymbol{X} \) which embody our model,
that is \( \boldsymbol{\tilde{y}}=\boldsymbol{X}\boldsymbol{\beta} \).
\( \boldsymbol{\theta} \) and the design matrix \( \boldsymbol{X} \) which embody our model,
that is \( \boldsymbol{\tilde{y}}=\boldsymbol{X}\boldsymbol{\theta} \).
</p>
<p>Thereafter we found the parameters \( \boldsymbol{\beta} \) by optimizing the means squared error via the so-called cost function</p>
<p>Thereafter we found the parameters \( \boldsymbol{\theta} \) by optimizing the means squared error via the so-called cost function</p>
$$
C(\boldsymbol{X},\boldsymbol{\beta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right].
C(\boldsymbol{X},\boldsymbol{\theta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right].
$$
<p>We can rewrite this as </p>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
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<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
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<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
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@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
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<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+3 -3
View File
@@ -51,10 +51,10 @@ doconce format html week38.do.txt --html_style=bootstrap --pygments_html_style=d
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
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'expectation-value-and-variance-for-boldsymbol-theta'),
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2,
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@@ -203,7 +203,7 @@ MathJax.Hub.Config({
<!-- navigation toc: --> <li><a href="._week38-bs003.html#linking-the-regression-analysis-with-a-statistical-interpretation" style="font-size: 80%;">Linking the regression analysis with a statistical interpretation</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs004.html#assumptions-made" style="font-size: 80%;">Assumptions made</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs005.html#expectation-value-and-variance" style="font-size: 80%;">Expectation value and variance</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-beta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\beta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs006.html#expectation-value-and-variance-for-boldsymbol-theta" style="font-size: 80%;">Expectation value and variance for \( \boldsymbol{\theta} \)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs007.html#deriving-ols-from-a-probability-distribution" style="font-size: 80%;">Deriving OLS from a probability distribution</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs008.html#independent-and-identically-distributed-iid" style="font-size: 80%;">Independent and Identically Distributed (iid)</a></li>
<!-- navigation toc: --> <li><a href="._week38-bs009.html#maximum-likelihood-estimation-mle" style="font-size: 80%;">Maximum Likelihood Estimation (MLE)</a></li>
+74 -74
View File
@@ -233,7 +233,7 @@ move from a linear algebra analysis to a statistical analysis. In
particular, we will focus on what the regularization terms can result
in. We will amongst other things show that the regularization
parameter can reduce considerably the variance of the parameters
\( \beta \).
\( \theta \).
</p>
<p>On of the advantages of doing linear regression is that we actually end up with
@@ -260,7 +260,7 @@ $$
<p>The randomness of \( \varepsilon_i \) implies that
\( \mathbf{y}_i \) is also a random variable. In particular,
\( \mathbf{y}_i \) is normally distributed, because \( \varepsilon_i \sim
\mathcal{N}(0, \sigma^2) \) and \( \mathbf{X}_{i,\ast} \, \boldsymbol{\beta} \) is a
\mathcal{N}(0, \sigma^2) \) and \( \mathbf{X}_{i,\ast} \, \boldsymbol{\theta} \) is a
non-random scalar. To specify the parameters of the distribution of
\( \mathbf{y}_i \) we need to calculate its first two moments.
</p>
@@ -289,7 +289,7 @@ function \( f \) is approximated by \( \boldsymbol{\tilde{y}} \) where we want t
</p>
<p>&nbsp;<br>
$$
\boldsymbol{\tilde{y}} = \boldsymbol{X}\boldsymbol{\beta}.
\boldsymbol{\tilde{y}} = \boldsymbol{X}\boldsymbol{\theta}.
$$
<p>&nbsp;<br>
</section>
@@ -302,8 +302,8 @@ $$
$$
\begin{align*}
\mathbb{E}(y_i) & =
\mathbb{E}(\mathbf{X}_{i, \ast} \, \boldsymbol{\beta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \beta,
\mathbb{E}(\mathbf{X}_{i, \ast} \, \boldsymbol{\theta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \theta,
\end{align*}
$$
<p>&nbsp;<br>
@@ -316,30 +316,30 @@ $$
\begin{align*} \mbox{Var}(y_i) & = \mathbb{E} \{ [y_i
- \mathbb{E}(y_i)]^2 \} \, \, \, = \, \, \, \mathbb{E} ( y_i^2 ) -
[\mathbb{E}(y_i)]^2 \\ & = \mathbb{E} [ ( \mathbf{X}_{i, \ast} \,
\beta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 \\ &
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \boldsymbol{\beta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \beta)^2 \\ & = ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \boldsymbol{\beta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2
\theta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 \\ &
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \boldsymbol{\theta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \theta)^2 \\ & = ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \boldsymbol{\theta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2
\\ & = \mathbb{E}(\varepsilon_i^2 ) \, \, \, = \, \, \,
\mbox{Var}(\varepsilon_i) \, \, \, = \, \, \, \sigma^2.
\end{align*}
$$
<p>&nbsp;<br>
<p>Hence, \( y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta}, \sigma^2) \), that is \( \boldsymbol{y} \) follows a normal distribution with
mean value \( \boldsymbol{X}\boldsymbol{\beta} \) and variance \( \sigma^2 \) (not be confused with the singular values of the SVD).
<p>Hence, \( y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta}, \sigma^2) \), that is \( \boldsymbol{y} \) follows a normal distribution with
mean value \( \boldsymbol{X}\boldsymbol{\theta} \) and variance \( \sigma^2 \) (not be confused with the singular values of the SVD).
</p>
</section>
<section>
<h2 id="expectation-value-and-variance-for-boldsymbol-beta">Expectation value and variance for \( \boldsymbol{\beta} \) </h2>
<h2 id="expectation-value-and-variance-for-boldsymbol-theta">Expectation value and variance for \( \boldsymbol{\theta} \) </h2>
<p>With the OLS expressions for the optimal parameters \( \boldsymbol{\hat{\beta}} \) we can evaluate the expectation value</p>
<p>With the OLS expressions for the optimal parameters \( \boldsymbol{\hat{\theta}} \) we can evaluate the expectation value</p>
<p>&nbsp;<br>
$$
\mathbb{E}(\boldsymbol{\hat{\beta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\beta}=\boldsymbol{\beta}.
\mathbb{E}(\boldsymbol{\hat{\theta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\theta}=\boldsymbol{\theta}.
$$
<p>&nbsp;<br>
@@ -347,78 +347,78 @@ $$
<p>We can also calculate the variance</p>
<p>The variance of the optimal value \( \boldsymbol{\hat{\beta}} \) is</p>
<p>The variance of the optimal value \( \boldsymbol{\hat{\theta}} \) is</p>
<p>&nbsp;<br>
$$
\begin{eqnarray*}
\mbox{Var}(\boldsymbol{\hat{\beta}}) & = & \mathbb{E} \{ [\boldsymbol{\beta} - \mathbb{E}(\boldsymbol{\beta})] [\boldsymbol{\beta} - \mathbb{E}(\boldsymbol{\beta})]^{T} \}
\mbox{Var}(\boldsymbol{\hat{\theta}}) & = & \mathbb{E} \{ [\boldsymbol{\theta} - \mathbb{E}(\boldsymbol{\theta})] [\boldsymbol{\theta} - \mathbb{E}(\boldsymbol{\theta})]^{T} \}
\\
& = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\beta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\beta}]^{T} \}
& = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\theta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\theta}]^{T} \}
\\
% & = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
% & = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
% & = & \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
% & = & \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
\\
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
% & = & (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% & = & (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% \\
% & & + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \boldsymbol{\beta} \boldsymbol{\beta}^T
% & & + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \boldsymbol{\theta} \boldsymbol{\theta}^T
\\
& = & \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
\, \, \, = \, \, \, \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1},
\end{eqnarray*}
$$
<p>&nbsp;<br>
<p>where we have used that \( \mathbb{E} (\mathbf{Y} \mathbf{Y}^{T}) =
\mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn} \). From \( \mbox{Var}(\boldsymbol{\beta}) = \sigma^2
\mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn} \). From \( \mbox{Var}(\boldsymbol{\theta}) = \sigma^2
\, (\mathbf{X}^{T} \mathbf{X})^{-1} \), one obtains an estimate of the
variance of the estimate of the \( j \)-th regression coefficient:
\( \boldsymbol{\sigma}^2 (\boldsymbol{\beta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \). This may be used to
\( \boldsymbol{\sigma}^2 (\boldsymbol{\theta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \). This may be used to
construct a confidence interval for the estimates.
</p>
<p>In a similar way, we can obtain analytical expressions for say the
expectation values of the parameters \( \boldsymbol{\beta} \) and their variance
expectation values of the parameters \( \boldsymbol{\theta} \) and their variance
when we employ Ridge regression, allowing us again to define a confidence interval.
</p>
<p>It is rather straightforward to show that</p>
<p>&nbsp;<br>
$$
\mathbb{E} \big[ \boldsymbol{\beta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\boldsymbol{\beta}^{\mathrm{OLS}}.
\mathbb{E} \big[ \boldsymbol{\theta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\boldsymbol{\theta}^{\mathrm{OLS}}.
$$
<p>&nbsp;<br>
<p>We see clearly that
\( \mathbb{E} \big[ \boldsymbol{\beta}^{\mathrm{Ridge}} \big] \not= \boldsymbol{\beta}^{\mathrm{OLS}} \) for any \( \lambda > 0 \). We say then that the ridge estimator is biased.
\( \mathbb{E} \big[ \boldsymbol{\theta}^{\mathrm{Ridge}} \big] \not= \boldsymbol{\theta}^{\mathrm{OLS}} \) for any \( \lambda > 0 \). We say then that the ridge estimator is biased.
</p>
<p>We can also compute the variance as </p>
<p>&nbsp;<br>
$$
\mbox{Var}[\boldsymbol{\beta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
\mbox{Var}[\boldsymbol{\theta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
$$
<p>&nbsp;<br>
<p>and it is easy to see that if the parameter \( \lambda \) goes to infinity then the variance of Ridge parameters \( \boldsymbol{\beta} \) goes to zero. </p>
<p>and it is easy to see that if the parameter \( \lambda \) goes to infinity then the variance of Ridge parameters \( \boldsymbol{\theta} \) goes to zero. </p>
<p>With this, we can compute the difference </p>
<p>&nbsp;<br>
$$
\mbox{Var}[\boldsymbol{\beta}^{\mathrm{OLS}}]-\mbox{Var}(\boldsymbol{\beta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
\mbox{Var}[\boldsymbol{\theta}^{\mathrm{OLS}}]-\mbox{Var}(\boldsymbol{\theta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
$$
<p>&nbsp;<br>
<p>The difference is non-negative definite since each component of the
matrix product is non-negative definite.
This means the variance we obtain with the standard OLS will always for \( \lambda > 0 \) be larger than the variance of \( \boldsymbol{\beta} \) obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.
This means the variance we obtain with the standard OLS will always for \( \lambda > 0 \) be larger than the variance of \( \boldsymbol{\theta} \) obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.
</p>
</section>
@@ -433,16 +433,16 @@ distribution with zero mean value and an undetermined variance
</p>
<p>We found above that the outputs \( \boldsymbol{y} \) have a mean value given by
\( \boldsymbol{X}\hat{\boldsymbol{\beta}} \) and variance \( \sigma^2 \). Since the entries to
\( \boldsymbol{X}\hat{\boldsymbol{\theta}} \) and variance \( \sigma^2 \). Since the entries to
the design matrix are not stochastic variables, we can assume that the
probability distribution of our targets is also a normal distribution
but now with mean value \( \boldsymbol{X}\hat{\boldsymbol{\beta}} \). This means that a
but now with mean value \( \boldsymbol{X}\hat{\boldsymbol{\theta}} \). This means that a
single output \( y_i \) is given by the Gaussian distribution
</p>
<p>&nbsp;<br>
$$
y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\beta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}.
y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\theta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}.
$$
<p>&nbsp;<br>
</section>
@@ -455,17 +455,17 @@ We define this distribution as
</p>
<p>&nbsp;<br>
$$
p(y_i, \boldsymbol{X}\vert\boldsymbol{\beta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]},
p(y_i, \boldsymbol{X}\vert\boldsymbol{\theta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]},
$$
<p>&nbsp;<br>
<p>which reads as finding the likelihood of an event \( y_i \) with the input variables \( \boldsymbol{X} \) given the parameters (to be determined) \( \boldsymbol{\beta} \).</p>
<p>which reads as finding the likelihood of an event \( y_i \) with the input variables \( \boldsymbol{X} \) given the parameters (to be determined) \( \boldsymbol{\theta} \).</p>
<p>Since these events are assumed to be independent and identicall distributed we can build the probability distribution function (PDF) for all possible event \( \boldsymbol{y} \) as the product of the single events, that is we have</p>
<p>&nbsp;<br>
$$
p(\boldsymbol{y},\boldsymbol{X}\vert\boldsymbol{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta}).
p(\boldsymbol{y},\boldsymbol{X}\vert\boldsymbol{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta}).
$$
<p>&nbsp;<br>
@@ -483,11 +483,11 @@ We can now rewrite the above probability as
</p>
<p>&nbsp;<br>
$$
p(\boldsymbol{D}\vert\boldsymbol{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}.
p(\boldsymbol{D}\vert\boldsymbol{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}.
$$
<p>&nbsp;<br>
<p>It is a conditional probability (see below) and reads as the likelihood of a domain of events \( \boldsymbol{D} \) given a set of parameters \( \boldsymbol{\beta} \).</p>
<p>It is a conditional probability (see below) and reads as the likelihood of a domain of events \( \boldsymbol{D} \) given a set of parameters \( \boldsymbol{\theta} \).</p>
</section>
<section>
@@ -501,7 +501,7 @@ data is the most probable.
</p>
<p>We will assume here that our events are given by the above Gaussian
distribution and we will determine the optimal parameters \( \beta \) by
distribution and we will determine the optimal parameters \( \theta \) by
maximizing the above PDF. However, computing the derivatives of a
product function is cumbersome and can easily lead to overflow and/or
underflowproblems, with potentials for loss of numerical precision.
@@ -526,29 +526,29 @@ is equivalent to the maximization/minimization of the function itself.
<p>&nbsp;<br>
$$
C(\boldsymbol{\beta}=-\log{\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta})},
C(\boldsymbol{\theta}=-\log{\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta})},
$$
<p>&nbsp;<br>
<p>which becomes</p>
<p>&nbsp;<br>
$$
C(\boldsymbol{\beta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\beta})\vert\vert_2^2}{2\sigma^2}.
C(\boldsymbol{\theta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\theta})\vert\vert_2^2}{2\sigma^2}.
$$
<p>&nbsp;<br>
<p>Taking the derivative of the <em>new</em> cost function with respect to the parameters \( \beta \) we recognize our familiar OLS equation, namely</p>
<p>Taking the derivative of the <em>new</em> cost function with respect to the parameters \( \theta \) we recognize our familiar OLS equation, namely</p>
<p>&nbsp;<br>
$$
\boldsymbol{X}^T\left(\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\beta}\right) =0,
\boldsymbol{X}^T\left(\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\theta}\right) =0,
$$
<p>&nbsp;<br>
<p>which leads to the well-known OLS equation for the optimal paramters \( \beta \)</p>
<p>which leads to the well-known OLS equation for the optimal paramters \( \theta \)</p>
<p>&nbsp;<br>
$$
\hat{\boldsymbol{\beta}}^{\mathrm{OLS}}=\left(\boldsymbol{X}^T\boldsymbol{X}\right)^{-1}\boldsymbol{X}^T\boldsymbol{y}!
\hat{\boldsymbol{\theta}}^{\mathrm{OLS}}=\left(\boldsymbol{X}^T\boldsymbol{X}\right)^{-1}\boldsymbol{X}^T\boldsymbol{y}!
$$
<p>&nbsp;<br>
@@ -879,15 +879,15 @@ finite \( m \), it is not always possible to find a closed form /analytic expres
<p>Confidence intervals are used in statistics and represent a type of estimate
computed from the observed data. This gives a range of values for an
unknown parameter such as the parameters \( \boldsymbol{\beta} \) from linear regression.
unknown parameter such as the parameters \( \boldsymbol{\theta} \) from linear regression.
</p>
<p>With the OLS expressions for the parameters \( \boldsymbol{\beta} \) we found
\( \mathbb{E}(\boldsymbol{\beta}) = \boldsymbol{\beta} \), which means that the estimator of the regression parameters is unbiased.
<p>With the OLS expressions for the parameters \( \boldsymbol{\theta} \) we found
\( \mathbb{E}(\boldsymbol{\theta}) = \boldsymbol{\theta} \), which means that the estimator of the regression parameters is unbiased.
</p>
<p>In the exercises this week we show that the variance of the estimate of the \( j \)-th regression coefficient is
\( \boldsymbol{\sigma}^2 (\boldsymbol{\beta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \).
\( \boldsymbol{\sigma}^2 (\boldsymbol{\theta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \).
</p>
<p>This quantity can be used to
@@ -898,15 +898,15 @@ construct a confidence interval for the estimates.
<section>
<h2 id="standard-approach-based-on-the-normal-distribution">Standard Approach based on the Normal Distribution </h2>
<p>We will assume that the parameters \( \beta \) follow a normal
<p>We will assume that the parameters \( \theta \) follow a normal
distribution. We can then define the confidence interval. Here we will be using as
shorthands \( \mu_{\beta} \) for the above mean value and \( \sigma_{\beta} \)
shorthands \( \mu_{\theta} \) for the above mean value and \( \sigma_{\theta} \)
for the standard deviation. We have then a confidence interval
</p>
<p>&nbsp;<br>
$$
\left(\mu_{\beta}\pm \frac{z\sigma_{\beta}}{\sqrt{n}}\right),
\left(\mu_{\theta}\pm \frac{z\sigma_{\theta}}{\sqrt{n}}\right),
$$
<p>&nbsp;<br>
@@ -928,11 +928,11 @@ Bootstrap method, why it works and various theorems related to it.
<section>
<h2 id="resampling-methods-bootstrap-background">Resampling methods: Bootstrap background </h2>
<p>Since \( \widehat{\beta} = \widehat{\beta}(\boldsymbol{X}) \) is a function of random variables,
\( \widehat{\beta} \) itself must be a random variable. Thus it has
<p>Since \( \widehat{\theta} = \widehat{\theta}(\boldsymbol{X}) \) is a function of random variables,
\( \widehat{\theta} \) itself must be a random variable. Thus it has
a pdf, call this function \( p(\boldsymbol{t}) \). The aim of the bootstrap is to
estimate \( p(\boldsymbol{t}) \) by the relative frequency of
\( \widehat{\beta} \). You can think of this as using a histogram
\( \widehat{\theta} \). You can think of this as using a histogram
in the place of \( p(\boldsymbol{t}) \). If the relative frequency closely
resembles \( p(\vec{t}) \), then using numerics, it is straight forward to
estimate all the interesting parameters of \( p(\boldsymbol{t}) \) using point
@@ -943,7 +943,7 @@ estimators.
<section>
<h2 id="resampling-methods-more-bootstrap-background">Resampling methods: More Bootstrap background </h2>
<p>In the case that \( \widehat{\beta} \) has
<p>In the case that \( \widehat{\theta} \) has
more than one component, and the components are independent, we use the
same estimator on each component separately. If the probability
density function of \( X_i \), \( p(x) \), had been known, then it would have
@@ -951,12 +951,12 @@ been straightforward to do this by:
</p>
<ol>
<p><li> Drawing lots of numbers from \( p(x) \), suppose we call one such set of numbers \( (X_1^*, X_2^*, \cdots, X_n^*) \).</li>
<p><li> Then using these numbers, we could compute a replica of \( \widehat{\beta} \) called \( \widehat{\beta}^* \).</li>
<p><li> Then using these numbers, we could compute a replica of \( \widehat{\theta} \) called \( \widehat{\theta}^* \).</li>
</ol>
<p>
<p>By repeated use of the above two points, many
estimates of \( \widehat{\beta} \) can be obtained. The
idea is to use the relative frequency of \( \widehat{\beta}^* \)
estimates of \( \widehat{\theta} \) can be obtained. The
idea is to use the relative frequency of \( \widehat{\theta}^* \)
(think of a histogram) as an estimate of \( p(\boldsymbol{t}) \).
</p>
</section>
@@ -986,19 +986,19 @@ result in some asymptotic sense? The answer is yes.
<ol>
<p><li> Draw with replacement \( n \) numbers for the observed variables \( \boldsymbol{x} = (x_1,x_2,\cdots,x_n) \).</li>
<p><li> Define a vector \( \boldsymbol{x}^* \) containing the values which were drawn from \( \boldsymbol{x} \).</li>
<p><li> Using the vector \( \boldsymbol{x}^* \) compute \( \widehat{\beta}^* \) by evaluating \( \widehat \beta \) under the observations \( \boldsymbol{x}^* \).</li>
<p><li> Using the vector \( \boldsymbol{x}^* \) compute \( \widehat{\theta}^* \) by evaluating \( \widehat \theta \) under the observations \( \boldsymbol{x}^* \).</li>
<p><li> Repeat this process \( k \) times.</li>
</ol>
<p>
<p>When you are done, you can draw a histogram of the relative frequency
of \( \widehat \beta^* \). This is your estimate of the probability
of \( \widehat \theta^* \). This is your estimate of the probability
distribution \( p(t) \). Using this probability distribution you can
estimate any statistics thereof. In principle you never draw the
histogram of the relative frequency of \( \widehat{\beta}^* \). Instead
histogram of the relative frequency of \( \widehat{\theta}^* \). Instead
you use the estimators corresponding to the statistic of interest. For
example, if you are interested in estimating the variance of \( \widehat
\beta \), apply the etsimator \( \widehat \sigma^2 \) to the values
\( \widehat \beta^* \).
\theta \), apply the etsimator \( \widehat \sigma^2 \) to the values
\( \widehat \theta^* \).
</p>
</section>
@@ -1126,14 +1126,14 @@ $$
<p>In our derivation of the ordinary least squares method we defined then
an approximation to the function \( f \) in terms of the parameters
\( \boldsymbol{\beta} \) and the design matrix \( \boldsymbol{X} \) which embody our model,
that is \( \boldsymbol{\tilde{y}}=\boldsymbol{X}\boldsymbol{\beta} \).
\( \boldsymbol{\theta} \) and the design matrix \( \boldsymbol{X} \) which embody our model,
that is \( \boldsymbol{\tilde{y}}=\boldsymbol{X}\boldsymbol{\theta} \).
</p>
<p>Thereafter we found the parameters \( \boldsymbol{\beta} \) by optimizing the means squared error via the so-called cost function</p>
<p>Thereafter we found the parameters \( \boldsymbol{\theta} \) by optimizing the means squared error via the so-called cost function</p>
<p>&nbsp;<br>
$$
C(\boldsymbol{X},\boldsymbol{\beta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right].
C(\boldsymbol{X},\boldsymbol{\theta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right].
$$
<p>&nbsp;<br>
+76 -76
View File
@@ -78,10 +78,10 @@ div.toc p,a {
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -270,7 +270,7 @@ move from a linear algebra analysis to a statistical analysis. In
particular, we will focus on what the regularization terms can result
in. We will amongst other things show that the regularization
parameter can reduce considerably the variance of the parameters
\( \beta \).
\( \theta \).
</p>
<p>On of the advantages of doing linear regression is that we actually end up with
@@ -295,7 +295,7 @@ $$
<p>The randomness of \( \varepsilon_i \) implies that
\( \mathbf{y}_i \) is also a random variable. In particular,
\( \mathbf{y}_i \) is normally distributed, because \( \varepsilon_i \sim
\mathcal{N}(0, \sigma^2) \) and \( \mathbf{X}_{i,\ast} \, \boldsymbol{\beta} \) is a
\mathcal{N}(0, \sigma^2) \) and \( \mathbf{X}_{i,\ast} \, \boldsymbol{\theta} \) is a
non-random scalar. To specify the parameters of the distribution of
\( \mathbf{y}_i \) we need to calculate its first two moments.
</p>
@@ -320,7 +320,7 @@ $$
function \( f \) is approximated by \( \boldsymbol{\tilde{y}} \) where we want to minimize \( (\boldsymbol{y}-\boldsymbol{\tilde{y}})^2 \), our MSE, with
</p>
$$
\boldsymbol{\tilde{y}} = \boldsymbol{X}\boldsymbol{\beta}.
\boldsymbol{\tilde{y}} = \boldsymbol{X}\boldsymbol{\theta}.
$$
@@ -331,8 +331,8 @@ $$
$$
\begin{align*}
\mathbb{E}(y_i) & =
\mathbb{E}(\mathbf{X}_{i, \ast} \, \boldsymbol{\beta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \beta,
\mathbb{E}(\mathbf{X}_{i, \ast} \, \boldsymbol{\theta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \theta,
\end{align*}
$$
@@ -343,97 +343,97 @@ $$
\begin{align*} \mbox{Var}(y_i) & = \mathbb{E} \{ [y_i
- \mathbb{E}(y_i)]^2 \} \, \, \, = \, \, \, \mathbb{E} ( y_i^2 ) -
[\mathbb{E}(y_i)]^2 \\ & = \mathbb{E} [ ( \mathbf{X}_{i, \ast} \,
\beta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 \\ &
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \boldsymbol{\beta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \beta)^2 \\ & = ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \boldsymbol{\beta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2
\theta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 \\ &
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \boldsymbol{\theta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \theta)^2 \\ & = ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \boldsymbol{\theta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2
\\ & = \mathbb{E}(\varepsilon_i^2 ) \, \, \, = \, \, \,
\mbox{Var}(\varepsilon_i) \, \, \, = \, \, \, \sigma^2.
\end{align*}
$$
<p>Hence, \( y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta}, \sigma^2) \), that is \( \boldsymbol{y} \) follows a normal distribution with
mean value \( \boldsymbol{X}\boldsymbol{\beta} \) and variance \( \sigma^2 \) (not be confused with the singular values of the SVD).
<p>Hence, \( y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta}, \sigma^2) \), that is \( \boldsymbol{y} \) follows a normal distribution with
mean value \( \boldsymbol{X}\boldsymbol{\theta} \) and variance \( \sigma^2 \) (not be confused with the singular values of the SVD).
</p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="expectation-value-and-variance-for-boldsymbol-beta">Expectation value and variance for \( \boldsymbol{\beta} \) </h2>
<h2 id="expectation-value-and-variance-for-boldsymbol-theta">Expectation value and variance for \( \boldsymbol{\theta} \) </h2>
<p>With the OLS expressions for the optimal parameters \( \boldsymbol{\hat{\beta}} \) we can evaluate the expectation value</p>
<p>With the OLS expressions for the optimal parameters \( \boldsymbol{\hat{\theta}} \) we can evaluate the expectation value</p>
$$
\mathbb{E}(\boldsymbol{\hat{\beta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\beta}=\boldsymbol{\beta}.
\mathbb{E}(\boldsymbol{\hat{\theta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\theta}=\boldsymbol{\theta}.
$$
<p>This means that the estimator of the regression parameters is unbiased.</p>
<p>We can also calculate the variance</p>
<p>The variance of the optimal value \( \boldsymbol{\hat{\beta}} \) is</p>
<p>The variance of the optimal value \( \boldsymbol{\hat{\theta}} \) is</p>
$$
\begin{eqnarray*}
\mbox{Var}(\boldsymbol{\hat{\beta}}) & = & \mathbb{E} \{ [\boldsymbol{\beta} - \mathbb{E}(\boldsymbol{\beta})] [\boldsymbol{\beta} - \mathbb{E}(\boldsymbol{\beta})]^{T} \}
\mbox{Var}(\boldsymbol{\hat{\theta}}) & = & \mathbb{E} \{ [\boldsymbol{\theta} - \mathbb{E}(\boldsymbol{\theta})] [\boldsymbol{\theta} - \mathbb{E}(\boldsymbol{\theta})]^{T} \}
\\
& = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\beta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\beta}]^{T} \}
& = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\theta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\theta}]^{T} \}
\\
% & = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
% & = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
% & = & \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
% & = & \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
\\
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
% & = & (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% & = & (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% \\
% & & + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \boldsymbol{\beta} \boldsymbol{\beta}^T
% & & + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \boldsymbol{\theta} \boldsymbol{\theta}^T
\\
& = & \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
\, \, \, = \, \, \, \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1},
\end{eqnarray*}
$$
<p>where we have used that \( \mathbb{E} (\mathbf{Y} \mathbf{Y}^{T}) =
\mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn} \). From \( \mbox{Var}(\boldsymbol{\beta}) = \sigma^2
\mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn} \). From \( \mbox{Var}(\boldsymbol{\theta}) = \sigma^2
\, (\mathbf{X}^{T} \mathbf{X})^{-1} \), one obtains an estimate of the
variance of the estimate of the \( j \)-th regression coefficient:
\( \boldsymbol{\sigma}^2 (\boldsymbol{\beta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \). This may be used to
\( \boldsymbol{\sigma}^2 (\boldsymbol{\theta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \). This may be used to
construct a confidence interval for the estimates.
</p>
<p>In a similar way, we can obtain analytical expressions for say the
expectation values of the parameters \( \boldsymbol{\beta} \) and their variance
expectation values of the parameters \( \boldsymbol{\theta} \) and their variance
when we employ Ridge regression, allowing us again to define a confidence interval.
</p>
<p>It is rather straightforward to show that</p>
$$
\mathbb{E} \big[ \boldsymbol{\beta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\boldsymbol{\beta}^{\mathrm{OLS}}.
\mathbb{E} \big[ \boldsymbol{\theta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\boldsymbol{\theta}^{\mathrm{OLS}}.
$$
<p>We see clearly that
\( \mathbb{E} \big[ \boldsymbol{\beta}^{\mathrm{Ridge}} \big] \not= \boldsymbol{\beta}^{\mathrm{OLS}} \) for any \( \lambda > 0 \). We say then that the ridge estimator is biased.
\( \mathbb{E} \big[ \boldsymbol{\theta}^{\mathrm{Ridge}} \big] \not= \boldsymbol{\theta}^{\mathrm{OLS}} \) for any \( \lambda > 0 \). We say then that the ridge estimator is biased.
</p>
<p>We can also compute the variance as </p>
$$
\mbox{Var}[\boldsymbol{\beta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
\mbox{Var}[\boldsymbol{\theta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
$$
<p>and it is easy to see that if the parameter \( \lambda \) goes to infinity then the variance of Ridge parameters \( \boldsymbol{\beta} \) goes to zero. </p>
<p>and it is easy to see that if the parameter \( \lambda \) goes to infinity then the variance of Ridge parameters \( \boldsymbol{\theta} \) goes to zero. </p>
<p>With this, we can compute the difference </p>
$$
\mbox{Var}[\boldsymbol{\beta}^{\mathrm{OLS}}]-\mbox{Var}(\boldsymbol{\beta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
\mbox{Var}[\boldsymbol{\theta}^{\mathrm{OLS}}]-\mbox{Var}(\boldsymbol{\theta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
$$
<p>The difference is non-negative definite since each component of the
matrix product is non-negative definite.
This means the variance we obtain with the standard OLS will always for \( \lambda > 0 \) be larger than the variance of \( \boldsymbol{\beta} \) obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.
This means the variance we obtain with the standard OLS will always for \( \lambda > 0 \) be larger than the variance of \( \boldsymbol{\theta} \) obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.
</p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
@@ -447,15 +447,15 @@ distribution with zero mean value and an undetermined variance
</p>
<p>We found above that the outputs \( \boldsymbol{y} \) have a mean value given by
\( \boldsymbol{X}\hat{\boldsymbol{\beta}} \) and variance \( \sigma^2 \). Since the entries to
\( \boldsymbol{X}\hat{\boldsymbol{\theta}} \) and variance \( \sigma^2 \). Since the entries to
the design matrix are not stochastic variables, we can assume that the
probability distribution of our targets is also a normal distribution
but now with mean value \( \boldsymbol{X}\hat{\boldsymbol{\beta}} \). This means that a
but now with mean value \( \boldsymbol{X}\hat{\boldsymbol{\theta}} \). This means that a
single output \( y_i \) is given by the Gaussian distribution
</p>
$$
y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\beta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}.
y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\theta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}.
$$
@@ -466,15 +466,15 @@ $$
We define this distribution as
</p>
$$
p(y_i, \boldsymbol{X}\vert\boldsymbol{\beta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]},
p(y_i, \boldsymbol{X}\vert\boldsymbol{\theta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]},
$$
<p>which reads as finding the likelihood of an event \( y_i \) with the input variables \( \boldsymbol{X} \) given the parameters (to be determined) \( \boldsymbol{\beta} \).</p>
<p>which reads as finding the likelihood of an event \( y_i \) with the input variables \( \boldsymbol{X} \) given the parameters (to be determined) \( \boldsymbol{\theta} \).</p>
<p>Since these events are assumed to be independent and identicall distributed we can build the probability distribution function (PDF) for all possible event \( \boldsymbol{y} \) as the product of the single events, that is we have</p>
$$
p(\boldsymbol{y},\boldsymbol{X}\vert\boldsymbol{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta}).
p(\boldsymbol{y},\boldsymbol{X}\vert\boldsymbol{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta}).
$$
<p>We will write this in a more compact form reserving \( \boldsymbol{D} \) for the domain of events, including the ouputs (targets) and the inputs. That is
@@ -488,10 +488,10 @@ $$
We can now rewrite the above probability as
</p>
$$
p(\boldsymbol{D}\vert\boldsymbol{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}.
p(\boldsymbol{D}\vert\boldsymbol{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}.
$$
<p>It is a conditional probability (see below) and reads as the likelihood of a domain of events \( \boldsymbol{D} \) given a set of parameters \( \boldsymbol{\beta} \).</p>
<p>It is a conditional probability (see below) and reads as the likelihood of a domain of events \( \boldsymbol{D} \) given a set of parameters \( \boldsymbol{\theta} \).</p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="maximum-likelihood-estimation-mle">Maximum Likelihood Estimation (MLE) </h2>
@@ -504,7 +504,7 @@ data is the most probable.
</p>
<p>We will assume here that our events are given by the above Gaussian
distribution and we will determine the optimal parameters \( \beta \) by
distribution and we will determine the optimal parameters \( \theta \) by
maximizing the above PDF. However, computing the derivatives of a
product function is cumbersome and can easily lead to overflow and/or
underflowproblems, with potentials for loss of numerical precision.
@@ -527,23 +527,23 @@ is equivalent to the maximization/minimization of the function itself.
<p>We could now define a new cost function to minimize, namely the negative logarithm of the above PDF</p>
$$
C(\boldsymbol{\beta}=-\log{\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta})},
C(\boldsymbol{\theta}=-\log{\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta})},
$$
<p>which becomes</p>
$$
C(\boldsymbol{\beta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\beta})\vert\vert_2^2}{2\sigma^2}.
C(\boldsymbol{\theta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\theta})\vert\vert_2^2}{2\sigma^2}.
$$
<p>Taking the derivative of the <em>new</em> cost function with respect to the parameters \( \beta \) we recognize our familiar OLS equation, namely</p>
<p>Taking the derivative of the <em>new</em> cost function with respect to the parameters \( \theta \) we recognize our familiar OLS equation, namely</p>
$$
\boldsymbol{X}^T\left(\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\beta}\right) =0,
\boldsymbol{X}^T\left(\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\theta}\right) =0,
$$
<p>which leads to the well-known OLS equation for the optimal paramters \( \beta \)</p>
<p>which leads to the well-known OLS equation for the optimal paramters \( \theta \)</p>
$$
\hat{\boldsymbol{\beta}}^{\mathrm{OLS}}=\left(\boldsymbol{X}^T\boldsymbol{X}\right)^{-1}\boldsymbol{X}^T\boldsymbol{y}!
\hat{\boldsymbol{\theta}}^{\mathrm{OLS}}=\left(\boldsymbol{X}^T\boldsymbol{X}\right)^{-1}\boldsymbol{X}^T\boldsymbol{y}!
$$
<p>Next week we will make a similar analysis for Ridge and Lasso regression</p>
@@ -838,15 +838,15 @@ finite \( m \), it is not always possible to find a closed form /analytic expres
<p>Confidence intervals are used in statistics and represent a type of estimate
computed from the observed data. This gives a range of values for an
unknown parameter such as the parameters \( \boldsymbol{\beta} \) from linear regression.
unknown parameter such as the parameters \( \boldsymbol{\theta} \) from linear regression.
</p>
<p>With the OLS expressions for the parameters \( \boldsymbol{\beta} \) we found
\( \mathbb{E}(\boldsymbol{\beta}) = \boldsymbol{\beta} \), which means that the estimator of the regression parameters is unbiased.
<p>With the OLS expressions for the parameters \( \boldsymbol{\theta} \) we found
\( \mathbb{E}(\boldsymbol{\theta}) = \boldsymbol{\theta} \), which means that the estimator of the regression parameters is unbiased.
</p>
<p>In the exercises this week we show that the variance of the estimate of the \( j \)-th regression coefficient is
\( \boldsymbol{\sigma}^2 (\boldsymbol{\beta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \).
\( \boldsymbol{\sigma}^2 (\boldsymbol{\theta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \).
</p>
<p>This quantity can be used to
@@ -856,14 +856,14 @@ construct a confidence interval for the estimates.
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="standard-approach-based-on-the-normal-distribution">Standard Approach based on the Normal Distribution </h2>
<p>We will assume that the parameters \( \beta \) follow a normal
<p>We will assume that the parameters \( \theta \) follow a normal
distribution. We can then define the confidence interval. Here we will be using as
shorthands \( \mu_{\beta} \) for the above mean value and \( \sigma_{\beta} \)
shorthands \( \mu_{\theta} \) for the above mean value and \( \sigma_{\theta} \)
for the standard deviation. We have then a confidence interval
</p>
$$
\left(\mu_{\beta}\pm \frac{z\sigma_{\beta}}{\sqrt{n}}\right),
\left(\mu_{\theta}\pm \frac{z\sigma_{\theta}}{\sqrt{n}}\right),
$$
<p>where \( z \) defines the level of certainty (or confidence). For a normal
@@ -883,11 +883,11 @@ Bootstrap method, why it works and various theorems related to it.
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="resampling-methods-bootstrap-background">Resampling methods: Bootstrap background </h2>
<p>Since \( \widehat{\beta} = \widehat{\beta}(\boldsymbol{X}) \) is a function of random variables,
\( \widehat{\beta} \) itself must be a random variable. Thus it has
<p>Since \( \widehat{\theta} = \widehat{\theta}(\boldsymbol{X}) \) is a function of random variables,
\( \widehat{\theta} \) itself must be a random variable. Thus it has
a pdf, call this function \( p(\boldsymbol{t}) \). The aim of the bootstrap is to
estimate \( p(\boldsymbol{t}) \) by the relative frequency of
\( \widehat{\beta} \). You can think of this as using a histogram
\( \widehat{\theta} \). You can think of this as using a histogram
in the place of \( p(\boldsymbol{t}) \). If the relative frequency closely
resembles \( p(\vec{t}) \), then using numerics, it is straight forward to
estimate all the interesting parameters of \( p(\boldsymbol{t}) \) using point
@@ -897,7 +897,7 @@ estimators.
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="resampling-methods-more-bootstrap-background">Resampling methods: More Bootstrap background </h2>
<p>In the case that \( \widehat{\beta} \) has
<p>In the case that \( \widehat{\theta} \) has
more than one component, and the components are independent, we use the
same estimator on each component separately. If the probability
density function of \( X_i \), \( p(x) \), had been known, then it would have
@@ -905,11 +905,11 @@ been straightforward to do this by:
</p>
<ol>
<li> Drawing lots of numbers from \( p(x) \), suppose we call one such set of numbers \( (X_1^*, X_2^*, \cdots, X_n^*) \).</li>
<li> Then using these numbers, we could compute a replica of \( \widehat{\beta} \) called \( \widehat{\beta}^* \).</li>
<li> Then using these numbers, we could compute a replica of \( \widehat{\theta} \) called \( \widehat{\theta}^* \).</li>
</ol>
<p>By repeated use of the above two points, many
estimates of \( \widehat{\beta} \) can be obtained. The
idea is to use the relative frequency of \( \widehat{\beta}^* \)
estimates of \( \widehat{\theta} \) can be obtained. The
idea is to use the relative frequency of \( \widehat{\theta}^* \)
(think of a histogram) as an estimate of \( p(\boldsymbol{t}) \).
</p>
@@ -937,18 +937,18 @@ result in some asymptotic sense? The answer is yes.
<ol>
<li> Draw with replacement \( n \) numbers for the observed variables \( \boldsymbol{x} = (x_1,x_2,\cdots,x_n) \).</li>
<li> Define a vector \( \boldsymbol{x}^* \) containing the values which were drawn from \( \boldsymbol{x} \).</li>
<li> Using the vector \( \boldsymbol{x}^* \) compute \( \widehat{\beta}^* \) by evaluating \( \widehat \beta \) under the observations \( \boldsymbol{x}^* \).</li>
<li> Using the vector \( \boldsymbol{x}^* \) compute \( \widehat{\theta}^* \) by evaluating \( \widehat \theta \) under the observations \( \boldsymbol{x}^* \).</li>
<li> Repeat this process \( k \) times.</li>
</ol>
<p>When you are done, you can draw a histogram of the relative frequency
of \( \widehat \beta^* \). This is your estimate of the probability
of \( \widehat \theta^* \). This is your estimate of the probability
distribution \( p(t) \). Using this probability distribution you can
estimate any statistics thereof. In principle you never draw the
histogram of the relative frequency of \( \widehat{\beta}^* \). Instead
histogram of the relative frequency of \( \widehat{\theta}^* \). Instead
you use the estimators corresponding to the statistic of interest. For
example, if you are interested in estimating the variance of \( \widehat
\beta \), apply the etsimator \( \widehat \sigma^2 \) to the values
\( \widehat \beta^* \).
\theta \), apply the etsimator \( \widehat \sigma^2 \) to the values
\( \widehat \theta^* \).
</p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
@@ -1072,13 +1072,13 @@ $$
<p>In our derivation of the ordinary least squares method we defined then
an approximation to the function \( f \) in terms of the parameters
\( \boldsymbol{\beta} \) and the design matrix \( \boldsymbol{X} \) which embody our model,
that is \( \boldsymbol{\tilde{y}}=\boldsymbol{X}\boldsymbol{\beta} \).
\( \boldsymbol{\theta} \) and the design matrix \( \boldsymbol{X} \) which embody our model,
that is \( \boldsymbol{\tilde{y}}=\boldsymbol{X}\boldsymbol{\theta} \).
</p>
<p>Thereafter we found the parameters \( \boldsymbol{\beta} \) by optimizing the means squared error via the so-called cost function</p>
<p>Thereafter we found the parameters \( \boldsymbol{\theta} \) by optimizing the means squared error via the so-called cost function</p>
$$
C(\boldsymbol{X},\boldsymbol{\beta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right].
C(\boldsymbol{X},\boldsymbol{\theta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right].
$$
<p>We can rewrite this as </p>
+76 -76
View File
@@ -155,10 +155,10 @@ div.toc p,a {
2,
None,
'expectation-value-and-variance'),
('Expectation value and variance for $\\boldsymbol{\\beta}$',
('Expectation value and variance for $\\boldsymbol{\\theta}$',
2,
None,
'expectation-value-and-variance-for-boldsymbol-beta'),
'expectation-value-and-variance-for-boldsymbol-theta'),
('Deriving OLS from a probability distribution',
2,
None,
@@ -347,7 +347,7 @@ move from a linear algebra analysis to a statistical analysis. In
particular, we will focus on what the regularization terms can result
in. We will amongst other things show that the regularization
parameter can reduce considerably the variance of the parameters
\( \beta \).
\( \theta \).
</p>
<p>On of the advantages of doing linear regression is that we actually end up with
@@ -372,7 +372,7 @@ $$
<p>The randomness of \( \varepsilon_i \) implies that
\( \mathbf{y}_i \) is also a random variable. In particular,
\( \mathbf{y}_i \) is normally distributed, because \( \varepsilon_i \sim
\mathcal{N}(0, \sigma^2) \) and \( \mathbf{X}_{i,\ast} \, \boldsymbol{\beta} \) is a
\mathcal{N}(0, \sigma^2) \) and \( \mathbf{X}_{i,\ast} \, \boldsymbol{\theta} \) is a
non-random scalar. To specify the parameters of the distribution of
\( \mathbf{y}_i \) we need to calculate its first two moments.
</p>
@@ -397,7 +397,7 @@ $$
function \( f \) is approximated by \( \boldsymbol{\tilde{y}} \) where we want to minimize \( (\boldsymbol{y}-\boldsymbol{\tilde{y}})^2 \), our MSE, with
</p>
$$
\boldsymbol{\tilde{y}} = \boldsymbol{X}\boldsymbol{\beta}.
\boldsymbol{\tilde{y}} = \boldsymbol{X}\boldsymbol{\theta}.
$$
@@ -408,8 +408,8 @@ $$
$$
\begin{align*}
\mathbb{E}(y_i) & =
\mathbb{E}(\mathbf{X}_{i, \ast} \, \boldsymbol{\beta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \beta,
\mathbb{E}(\mathbf{X}_{i, \ast} \, \boldsymbol{\theta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \theta,
\end{align*}
$$
@@ -420,97 +420,97 @@ $$
\begin{align*} \mbox{Var}(y_i) & = \mathbb{E} \{ [y_i
- \mathbb{E}(y_i)]^2 \} \, \, \, = \, \, \, \mathbb{E} ( y_i^2 ) -
[\mathbb{E}(y_i)]^2 \\ & = \mathbb{E} [ ( \mathbf{X}_{i, \ast} \,
\beta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 \\ &
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \boldsymbol{\beta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \beta)^2 \\ & = ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \boldsymbol{\beta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta})^2
\theta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 \\ &
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \boldsymbol{\theta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \theta)^2 \\ & = ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \boldsymbol{\theta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta})^2
\\ & = \mathbb{E}(\varepsilon_i^2 ) \, \, \, = \, \, \,
\mbox{Var}(\varepsilon_i) \, \, \, = \, \, \, \sigma^2.
\end{align*}
$$
<p>Hence, \( y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \boldsymbol{\beta}, \sigma^2) \), that is \( \boldsymbol{y} \) follows a normal distribution with
mean value \( \boldsymbol{X}\boldsymbol{\beta} \) and variance \( \sigma^2 \) (not be confused with the singular values of the SVD).
<p>Hence, \( y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \boldsymbol{\theta}, \sigma^2) \), that is \( \boldsymbol{y} \) follows a normal distribution with
mean value \( \boldsymbol{X}\boldsymbol{\theta} \) and variance \( \sigma^2 \) (not be confused with the singular values of the SVD).
</p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="expectation-value-and-variance-for-boldsymbol-beta">Expectation value and variance for \( \boldsymbol{\beta} \) </h2>
<h2 id="expectation-value-and-variance-for-boldsymbol-theta">Expectation value and variance for \( \boldsymbol{\theta} \) </h2>
<p>With the OLS expressions for the optimal parameters \( \boldsymbol{\hat{\beta}} \) we can evaluate the expectation value</p>
<p>With the OLS expressions for the optimal parameters \( \boldsymbol{\hat{\theta}} \) we can evaluate the expectation value</p>
$$
\mathbb{E}(\boldsymbol{\hat{\beta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\beta}=\boldsymbol{\beta}.
\mathbb{E}(\boldsymbol{\hat{\theta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\theta}=\boldsymbol{\theta}.
$$
<p>This means that the estimator of the regression parameters is unbiased.</p>
<p>We can also calculate the variance</p>
<p>The variance of the optimal value \( \boldsymbol{\hat{\beta}} \) is</p>
<p>The variance of the optimal value \( \boldsymbol{\hat{\theta}} \) is</p>
$$
\begin{eqnarray*}
\mbox{Var}(\boldsymbol{\hat{\beta}}) & = & \mathbb{E} \{ [\boldsymbol{\beta} - \mathbb{E}(\boldsymbol{\beta})] [\boldsymbol{\beta} - \mathbb{E}(\boldsymbol{\beta})]^{T} \}
\mbox{Var}(\boldsymbol{\hat{\theta}}) & = & \mathbb{E} \{ [\boldsymbol{\theta} - \mathbb{E}(\boldsymbol{\theta})] [\boldsymbol{\theta} - \mathbb{E}(\boldsymbol{\theta})]^{T} \}
\\
& = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\beta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\beta}]^{T} \}
& = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\theta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \boldsymbol{\theta}]^{T} \}
\\
% & = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
% & = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
% & = & \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
% & = & \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
\\
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
% \\
% & = & (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% & = & (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% \\
% & & + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \boldsymbol{\beta} \boldsymbol{\beta}^T
% & & + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \boldsymbol{\theta} \boldsymbol{\theta}^T
\\
& = & \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\beta} \, \boldsymbol{\beta}^{T}
& = & \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \boldsymbol{\theta} \, \boldsymbol{\theta}^{T}
\, \, \, = \, \, \, \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1},
\end{eqnarray*}
$$
<p>where we have used that \( \mathbb{E} (\mathbf{Y} \mathbf{Y}^{T}) =
\mathbf{X} \, \boldsymbol{\beta} \, \boldsymbol{\beta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn} \). From \( \mbox{Var}(\boldsymbol{\beta}) = \sigma^2
\mathbf{X} \, \boldsymbol{\theta} \, \boldsymbol{\theta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn} \). From \( \mbox{Var}(\boldsymbol{\theta}) = \sigma^2
\, (\mathbf{X}^{T} \mathbf{X})^{-1} \), one obtains an estimate of the
variance of the estimate of the \( j \)-th regression coefficient:
\( \boldsymbol{\sigma}^2 (\boldsymbol{\beta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \). This may be used to
\( \boldsymbol{\sigma}^2 (\boldsymbol{\theta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \). This may be used to
construct a confidence interval for the estimates.
</p>
<p>In a similar way, we can obtain analytical expressions for say the
expectation values of the parameters \( \boldsymbol{\beta} \) and their variance
expectation values of the parameters \( \boldsymbol{\theta} \) and their variance
when we employ Ridge regression, allowing us again to define a confidence interval.
</p>
<p>It is rather straightforward to show that</p>
$$
\mathbb{E} \big[ \boldsymbol{\beta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\boldsymbol{\beta}^{\mathrm{OLS}}.
\mathbb{E} \big[ \boldsymbol{\theta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\boldsymbol{\theta}^{\mathrm{OLS}}.
$$
<p>We see clearly that
\( \mathbb{E} \big[ \boldsymbol{\beta}^{\mathrm{Ridge}} \big] \not= \boldsymbol{\beta}^{\mathrm{OLS}} \) for any \( \lambda > 0 \). We say then that the ridge estimator is biased.
\( \mathbb{E} \big[ \boldsymbol{\theta}^{\mathrm{Ridge}} \big] \not= \boldsymbol{\theta}^{\mathrm{OLS}} \) for any \( \lambda > 0 \). We say then that the ridge estimator is biased.
</p>
<p>We can also compute the variance as </p>
$$
\mbox{Var}[\boldsymbol{\beta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
\mbox{Var}[\boldsymbol{\theta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
$$
<p>and it is easy to see that if the parameter \( \lambda \) goes to infinity then the variance of Ridge parameters \( \boldsymbol{\beta} \) goes to zero. </p>
<p>and it is easy to see that if the parameter \( \lambda \) goes to infinity then the variance of Ridge parameters \( \boldsymbol{\theta} \) goes to zero. </p>
<p>With this, we can compute the difference </p>
$$
\mbox{Var}[\boldsymbol{\beta}^{\mathrm{OLS}}]-\mbox{Var}(\boldsymbol{\beta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
\mbox{Var}[\boldsymbol{\theta}^{\mathrm{OLS}}]-\mbox{Var}(\boldsymbol{\theta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
$$
<p>The difference is non-negative definite since each component of the
matrix product is non-negative definite.
This means the variance we obtain with the standard OLS will always for \( \lambda > 0 \) be larger than the variance of \( \boldsymbol{\beta} \) obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.
This means the variance we obtain with the standard OLS will always for \( \lambda > 0 \) be larger than the variance of \( \boldsymbol{\theta} \) obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.
</p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
@@ -524,15 +524,15 @@ distribution with zero mean value and an undetermined variance
</p>
<p>We found above that the outputs \( \boldsymbol{y} \) have a mean value given by
\( \boldsymbol{X}\hat{\boldsymbol{\beta}} \) and variance \( \sigma^2 \). Since the entries to
\( \boldsymbol{X}\hat{\boldsymbol{\theta}} \) and variance \( \sigma^2 \). Since the entries to
the design matrix are not stochastic variables, we can assume that the
probability distribution of our targets is also a normal distribution
but now with mean value \( \boldsymbol{X}\hat{\boldsymbol{\beta}} \). This means that a
but now with mean value \( \boldsymbol{X}\hat{\boldsymbol{\theta}} \). This means that a
single output \( y_i \) is given by the Gaussian distribution
</p>
$$
y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\beta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}.
y_i\sim \mathcal{N}(\boldsymbol{X}_{i,*}\boldsymbol{\theta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}.
$$
@@ -543,15 +543,15 @@ $$
We define this distribution as
</p>
$$
p(y_i, \boldsymbol{X}\vert\boldsymbol{\beta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]},
p(y_i, \boldsymbol{X}\vert\boldsymbol{\theta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]},
$$
<p>which reads as finding the likelihood of an event \( y_i \) with the input variables \( \boldsymbol{X} \) given the parameters (to be determined) \( \boldsymbol{\beta} \).</p>
<p>which reads as finding the likelihood of an event \( y_i \) with the input variables \( \boldsymbol{X} \) given the parameters (to be determined) \( \boldsymbol{\theta} \).</p>
<p>Since these events are assumed to be independent and identicall distributed we can build the probability distribution function (PDF) for all possible event \( \boldsymbol{y} \) as the product of the single events, that is we have</p>
$$
p(\boldsymbol{y},\boldsymbol{X}\vert\boldsymbol{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta}).
p(\boldsymbol{y},\boldsymbol{X}\vert\boldsymbol{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta}).
$$
<p>We will write this in a more compact form reserving \( \boldsymbol{D} \) for the domain of events, including the ouputs (targets) and the inputs. That is
@@ -565,10 +565,10 @@ $$
We can now rewrite the above probability as
</p>
$$
p(\boldsymbol{D}\vert\boldsymbol{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\beta})^2}{2\sigma^2}\right]}.
p(\boldsymbol{D}\vert\boldsymbol{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\boldsymbol{X}_{i,*}\boldsymbol{\theta})^2}{2\sigma^2}\right]}.
$$
<p>It is a conditional probability (see below) and reads as the likelihood of a domain of events \( \boldsymbol{D} \) given a set of parameters \( \boldsymbol{\beta} \).</p>
<p>It is a conditional probability (see below) and reads as the likelihood of a domain of events \( \boldsymbol{D} \) given a set of parameters \( \boldsymbol{\theta} \).</p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="maximum-likelihood-estimation-mle">Maximum Likelihood Estimation (MLE) </h2>
@@ -581,7 +581,7 @@ data is the most probable.
</p>
<p>We will assume here that our events are given by the above Gaussian
distribution and we will determine the optimal parameters \( \beta \) by
distribution and we will determine the optimal parameters \( \theta \) by
maximizing the above PDF. However, computing the derivatives of a
product function is cumbersome and can easily lead to overflow and/or
underflowproblems, with potentials for loss of numerical precision.
@@ -604,23 +604,23 @@ is equivalent to the maximization/minimization of the function itself.
<p>We could now define a new cost function to minimize, namely the negative logarithm of the above PDF</p>
$$
C(\boldsymbol{\beta}=-\log{\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\boldsymbol{X}\vert\boldsymbol{\beta})},
C(\boldsymbol{\theta}=-\log{\prod_{i=0}^{n-1}p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\boldsymbol{X}\vert\boldsymbol{\theta})},
$$
<p>which becomes</p>
$$
C(\boldsymbol{\beta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\beta})\vert\vert_2^2}{2\sigma^2}.
C(\boldsymbol{\theta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\theta})\vert\vert_2^2}{2\sigma^2}.
$$
<p>Taking the derivative of the <em>new</em> cost function with respect to the parameters \( \beta \) we recognize our familiar OLS equation, namely</p>
<p>Taking the derivative of the <em>new</em> cost function with respect to the parameters \( \theta \) we recognize our familiar OLS equation, namely</p>
$$
\boldsymbol{X}^T\left(\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\beta}\right) =0,
\boldsymbol{X}^T\left(\boldsymbol{y}-\boldsymbol{X}\boldsymbol{\theta}\right) =0,
$$
<p>which leads to the well-known OLS equation for the optimal paramters \( \beta \)</p>
<p>which leads to the well-known OLS equation for the optimal paramters \( \theta \)</p>
$$
\hat{\boldsymbol{\beta}}^{\mathrm{OLS}}=\left(\boldsymbol{X}^T\boldsymbol{X}\right)^{-1}\boldsymbol{X}^T\boldsymbol{y}!
\hat{\boldsymbol{\theta}}^{\mathrm{OLS}}=\left(\boldsymbol{X}^T\boldsymbol{X}\right)^{-1}\boldsymbol{X}^T\boldsymbol{y}!
$$
<p>Next week we will make a similar analysis for Ridge and Lasso regression</p>
@@ -915,15 +915,15 @@ finite \( m \), it is not always possible to find a closed form /analytic expres
<p>Confidence intervals are used in statistics and represent a type of estimate
computed from the observed data. This gives a range of values for an
unknown parameter such as the parameters \( \boldsymbol{\beta} \) from linear regression.
unknown parameter such as the parameters \( \boldsymbol{\theta} \) from linear regression.
</p>
<p>With the OLS expressions for the parameters \( \boldsymbol{\beta} \) we found
\( \mathbb{E}(\boldsymbol{\beta}) = \boldsymbol{\beta} \), which means that the estimator of the regression parameters is unbiased.
<p>With the OLS expressions for the parameters \( \boldsymbol{\theta} \) we found
\( \mathbb{E}(\boldsymbol{\theta}) = \boldsymbol{\theta} \), which means that the estimator of the regression parameters is unbiased.
</p>
<p>In the exercises this week we show that the variance of the estimate of the \( j \)-th regression coefficient is
\( \boldsymbol{\sigma}^2 (\boldsymbol{\beta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \).
\( \boldsymbol{\sigma}^2 (\boldsymbol{\theta}_j ) = \boldsymbol{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} \).
</p>
<p>This quantity can be used to
@@ -933,14 +933,14 @@ construct a confidence interval for the estimates.
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="standard-approach-based-on-the-normal-distribution">Standard Approach based on the Normal Distribution </h2>
<p>We will assume that the parameters \( \beta \) follow a normal
<p>We will assume that the parameters \( \theta \) follow a normal
distribution. We can then define the confidence interval. Here we will be using as
shorthands \( \mu_{\beta} \) for the above mean value and \( \sigma_{\beta} \)
shorthands \( \mu_{\theta} \) for the above mean value and \( \sigma_{\theta} \)
for the standard deviation. We have then a confidence interval
</p>
$$
\left(\mu_{\beta}\pm \frac{z\sigma_{\beta}}{\sqrt{n}}\right),
\left(\mu_{\theta}\pm \frac{z\sigma_{\theta}}{\sqrt{n}}\right),
$$
<p>where \( z \) defines the level of certainty (or confidence). For a normal
@@ -960,11 +960,11 @@ Bootstrap method, why it works and various theorems related to it.
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="resampling-methods-bootstrap-background">Resampling methods: Bootstrap background </h2>
<p>Since \( \widehat{\beta} = \widehat{\beta}(\boldsymbol{X}) \) is a function of random variables,
\( \widehat{\beta} \) itself must be a random variable. Thus it has
<p>Since \( \widehat{\theta} = \widehat{\theta}(\boldsymbol{X}) \) is a function of random variables,
\( \widehat{\theta} \) itself must be a random variable. Thus it has
a pdf, call this function \( p(\boldsymbol{t}) \). The aim of the bootstrap is to
estimate \( p(\boldsymbol{t}) \) by the relative frequency of
\( \widehat{\beta} \). You can think of this as using a histogram
\( \widehat{\theta} \). You can think of this as using a histogram
in the place of \( p(\boldsymbol{t}) \). If the relative frequency closely
resembles \( p(\vec{t}) \), then using numerics, it is straight forward to
estimate all the interesting parameters of \( p(\boldsymbol{t}) \) using point
@@ -974,7 +974,7 @@ estimators.
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="resampling-methods-more-bootstrap-background">Resampling methods: More Bootstrap background </h2>
<p>In the case that \( \widehat{\beta} \) has
<p>In the case that \( \widehat{\theta} \) has
more than one component, and the components are independent, we use the
same estimator on each component separately. If the probability
density function of \( X_i \), \( p(x) \), had been known, then it would have
@@ -982,11 +982,11 @@ been straightforward to do this by:
</p>
<ol>
<li> Drawing lots of numbers from \( p(x) \), suppose we call one such set of numbers \( (X_1^*, X_2^*, \cdots, X_n^*) \).</li>
<li> Then using these numbers, we could compute a replica of \( \widehat{\beta} \) called \( \widehat{\beta}^* \).</li>
<li> Then using these numbers, we could compute a replica of \( \widehat{\theta} \) called \( \widehat{\theta}^* \).</li>
</ol>
<p>By repeated use of the above two points, many
estimates of \( \widehat{\beta} \) can be obtained. The
idea is to use the relative frequency of \( \widehat{\beta}^* \)
estimates of \( \widehat{\theta} \) can be obtained. The
idea is to use the relative frequency of \( \widehat{\theta}^* \)
(think of a histogram) as an estimate of \( p(\boldsymbol{t}) \).
</p>
@@ -1014,18 +1014,18 @@ result in some asymptotic sense? The answer is yes.
<ol>
<li> Draw with replacement \( n \) numbers for the observed variables \( \boldsymbol{x} = (x_1,x_2,\cdots,x_n) \).</li>
<li> Define a vector \( \boldsymbol{x}^* \) containing the values which were drawn from \( \boldsymbol{x} \).</li>
<li> Using the vector \( \boldsymbol{x}^* \) compute \( \widehat{\beta}^* \) by evaluating \( \widehat \beta \) under the observations \( \boldsymbol{x}^* \).</li>
<li> Using the vector \( \boldsymbol{x}^* \) compute \( \widehat{\theta}^* \) by evaluating \( \widehat \theta \) under the observations \( \boldsymbol{x}^* \).</li>
<li> Repeat this process \( k \) times.</li>
</ol>
<p>When you are done, you can draw a histogram of the relative frequency
of \( \widehat \beta^* \). This is your estimate of the probability
of \( \widehat \theta^* \). This is your estimate of the probability
distribution \( p(t) \). Using this probability distribution you can
estimate any statistics thereof. In principle you never draw the
histogram of the relative frequency of \( \widehat{\beta}^* \). Instead
histogram of the relative frequency of \( \widehat{\theta}^* \). Instead
you use the estimators corresponding to the statistic of interest. For
example, if you are interested in estimating the variance of \( \widehat
\beta \), apply the etsimator \( \widehat \sigma^2 \) to the values
\( \widehat \beta^* \).
\theta \), apply the etsimator \( \widehat \sigma^2 \) to the values
\( \widehat \theta^* \).
</p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
@@ -1149,13 +1149,13 @@ $$
<p>In our derivation of the ordinary least squares method we defined then
an approximation to the function \( f \) in terms of the parameters
\( \boldsymbol{\beta} \) and the design matrix \( \boldsymbol{X} \) which embody our model,
that is \( \boldsymbol{\tilde{y}}=\boldsymbol{X}\boldsymbol{\beta} \).
\( \boldsymbol{\theta} \) and the design matrix \( \boldsymbol{X} \) which embody our model,
that is \( \boldsymbol{\tilde{y}}=\boldsymbol{X}\boldsymbol{\theta} \).
</p>
<p>Thereafter we found the parameters \( \boldsymbol{\beta} \) by optimizing the means squared error via the so-called cost function</p>
<p>Thereafter we found the parameters \( \boldsymbol{\theta} \) by optimizing the means squared error via the so-called cost function</p>
$$
C(\boldsymbol{X},\boldsymbol{\beta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right].
C(\boldsymbol{X},\boldsymbol{\theta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right].
$$
<p>We can rewrite this as </p>
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+74 -74
View File
@@ -37,7 +37,7 @@ move from a linear algebra analysis to a statistical analysis. In
particular, we will focus on what the regularization terms can result
in. We will amongst other things show that the regularization
parameter can reduce considerably the variance of the parameters
$\beta$.
$\theta$.
On of the advantages of doing linear regression is that we actually end up with
@@ -60,7 +60,7 @@ independent, i.e.:
The randomness of $\varepsilon_i$ implies that
$\mathbf{y}_i$ is also a random variable. In particular,
$\mathbf{y}_i$ is normally distributed, because $\varepsilon_i \sim
\mathcal{N}(0, \sigma^2)$ and $\mathbf{X}_{i,\ast} \, \bm{\beta}$ is a
\mathcal{N}(0, \sigma^2)$ and $\mathbf{X}_{i,\ast} \, \bm{\theta}$ is a
non-random scalar. To specify the parameters of the distribution of
$\mathbf{y}_i$ we need to calculate its first two moments.
@@ -85,7 +85,7 @@ We approximate this function with our model from the solution of the linear regr
function $f$ is approximated by $\bm{\tilde{y}}$ where we want to minimize $(\bm{y}-\bm{\tilde{y}})^2$, our MSE, with
!bt
\[
\bm{\tilde{y}} = \bm{X}\bm{\beta}.
\bm{\tilde{y}} = \bm{X}\bm{\theta}.
\]
!et
@@ -96,8 +96,8 @@ We can calculate the expectation value of $\bm{y}$ for a given element $i$
!bt
\begin{align*}
\mathbb{E}(y_i) & =
\mathbb{E}(\mathbf{X}_{i, \ast} \, \bm{\beta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \beta,
\mathbb{E}(\mathbf{X}_{i, \ast} \, \bm{\theta}) + \mathbb{E}(\varepsilon_i)
\, \, \, = \, \, \, \mathbf{X}_{i, \ast} \, \theta,
\end{align*}
!et
while
@@ -106,97 +106,97 @@ its variance is
\begin{align*} \mbox{Var}(y_i) & = \mathbb{E} \{ [y_i
- \mathbb{E}(y_i)]^2 \} \, \, \, = \, \, \, \mathbb{E} ( y_i^2 ) -
[\mathbb{E}(y_i)]^2 \\ & = \mathbb{E} [ ( \mathbf{X}_{i, \ast} \,
\beta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \bm{\beta})^2 \\ &
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \bm{\beta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \bm{\beta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \beta)^2 \\ & = ( \mathbf{X}_{i, \ast} \, \bm{\beta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \bm{\beta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \bm{\beta})^2
\theta + \varepsilon_i )^2] - ( \mathbf{X}_{i, \ast} \, \bm{\theta})^2 \\ &
= \mathbb{E} [ ( \mathbf{X}_{i, \ast} \, \bm{\theta})^2 + 2 \varepsilon_i
\mathbf{X}_{i, \ast} \, \bm{\theta} + \varepsilon_i^2 ] - ( \mathbf{X}_{i,
\ast} \, \theta)^2 \\ & = ( \mathbf{X}_{i, \ast} \, \bm{\theta})^2 + 2
\mathbb{E}(\varepsilon_i) \mathbf{X}_{i, \ast} \, \bm{\theta} +
\mathbb{E}(\varepsilon_i^2 ) - ( \mathbf{X}_{i, \ast} \, \bm{\theta})^2
\\ & = \mathbb{E}(\varepsilon_i^2 ) \, \, \, = \, \, \,
\mbox{Var}(\varepsilon_i) \, \, \, = \, \, \, \sigma^2.
\end{align*}
!et
Hence, $y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \bm{\beta}, \sigma^2)$, that is $\bm{y}$ follows a normal distribution with
mean value $\bm{X}\bm{\beta}$ and variance $\sigma^2$ (not be confused with the singular values of the SVD).
Hence, $y_i \sim \mathcal{N}( \mathbf{X}_{i, \ast} \, \bm{\theta}, \sigma^2)$, that is $\bm{y}$ follows a normal distribution with
mean value $\bm{X}\bm{\theta}$ and variance $\sigma^2$ (not be confused with the singular values of the SVD).
!split
===== Expectation value and variance for $\bm{\beta}$ =====
===== Expectation value and variance for $\bm{\theta}$ =====
With the OLS expressions for the optimal parameters $\bm{\hat{\beta}}$ we can evaluate the expectation value
With the OLS expressions for the optimal parameters $\bm{\hat{\theta}}$ we can evaluate the expectation value
!bt
\[
\mathbb{E}(\bm{\hat{\beta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\bm{\beta}=\bm{\beta}.
\mathbb{E}(\bm{\hat{\theta}}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\bm{\theta}=\bm{\theta}.
\]
!et
This means that the estimator of the regression parameters is unbiased.
We can also calculate the variance
The variance of the optimal value $\bm{\hat{\beta}}$ is
The variance of the optimal value $\bm{\hat{\theta}}$ is
!bt
\begin{eqnarray*}
\mbox{Var}(\bm{\hat{\beta}}) & = & \mathbb{E} \{ [\bm{\beta} - \mathbb{E}(\bm{\beta})] [\bm{\beta} - \mathbb{E}(\bm{\beta})]^{T} \}
\mbox{Var}(\bm{\hat{\theta}}) & = & \mathbb{E} \{ [\bm{\theta} - \mathbb{E}(\bm{\theta})] [\bm{\theta} - \mathbb{E}(\bm{\theta})]^{T} \}
\\
& = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \bm{\beta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \bm{\beta}]^{T} \}
& = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \bm{\theta}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} - \bm{\theta}]^{T} \}
\\
% & = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \bm{\beta} \, \bm{\beta}^{T}
% & = & \mathbb{E} \{ [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}] \, [(\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y}]^{T} \} - \bm{\theta} \, \bm{\theta}^{T}
% \\
% & = & \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \bm{\beta} \, \bm{\beta}^{T}
% & = & \mathbb{E} \{ (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \mathbf{Y} \, \mathbf{Y}^{T} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} \} - \bm{\theta} \, \bm{\theta}^{T}
% \\
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \bm{\beta} \, \bm{\beta}^{T}
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \mathbb{E} \{ \mathbf{Y} \, \mathbf{Y}^{T} \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \bm{\theta} \, \bm{\theta}^{T}
\\
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \bm{\beta} \, \bm{\beta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \bm{\beta} \, \bm{\beta}^{T}
& = & (\mathbf{X}^{T} \mathbf{X})^{-1} \, \mathbf{X}^{T} \, \{ \mathbf{X} \, \bm{\theta} \, \bm{\theta}^{T} \, \mathbf{X}^{T} + \sigma^2 \} \, \mathbf{X} \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \bm{\theta} \, \bm{\theta}^{T}
% \\
% & = & (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \bm{\beta} \, \bm{\beta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% & = & (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, \bm{\theta} \, \bm{\theta}^T \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T % \mathbf{X})^{-1}
% \\
% & & + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \bm{\beta} \bm{\beta}^T
% & & + \, \, \sigma^2 \, (\mathbf{X}^T \mathbf{X})^{-1} \, \mathbf{X}^T \, \mathbf{X} \, (\mathbf{X}^T \mathbf{X})^{-1} - \bm{\theta} \bm{\theta}^T
\\
& = & \bm{\beta} \, \bm{\beta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \bm{\beta} \, \bm{\beta}^{T}
& = & \bm{\theta} \, \bm{\theta}^{T} + \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1} - \bm{\theta} \, \bm{\theta}^{T}
\, \, \, = \, \, \, \sigma^2 \, (\mathbf{X}^{T} \mathbf{X})^{-1},
\end{eqnarray*}
!et
where we have used that $\mathbb{E} (\mathbf{Y} \mathbf{Y}^{T}) =
\mathbf{X} \, \bm{\beta} \, \bm{\beta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn}$. From $\mbox{Var}(\bm{\beta}) = \sigma^2
\mathbf{X} \, \bm{\theta} \, \bm{\theta}^{T} \, \mathbf{X}^{T} +
\sigma^2 \, \mathbf{I}_{nn}$. From $\mbox{Var}(\bm{\theta}) = \sigma^2
\, (\mathbf{X}^{T} \mathbf{X})^{-1}$, one obtains an estimate of the
variance of the estimate of the $j$-th regression coefficient:
$\bm{\sigma}^2 (\bm{\beta}_j ) = \bm{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} $. This may be used to
$\bm{\sigma}^2 (\bm{\theta}_j ) = \bm{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} $. This may be used to
construct a confidence interval for the estimates.
In a similar way, we can obtain analytical expressions for say the
expectation values of the parameters $\bm{\beta}$ and their variance
expectation values of the parameters $\bm{\theta}$ and their variance
when we employ Ridge regression, allowing us again to define a confidence interval.
It is rather straightforward to show that
!bt
\[
\mathbb{E} \big[ \bm{\beta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\bm{\beta}^{\mathrm{OLS}}.
\mathbb{E} \big[ \bm{\theta}^{\mathrm{Ridge}} \big]=(\mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I}_{pp})^{-1} (\mathbf{X}^{\top} \mathbf{X})\bm{\theta}^{\mathrm{OLS}}.
\]
!et
We see clearly that
$\mathbb{E} \big[ \bm{\beta}^{\mathrm{Ridge}} \big] \not= \bm{\beta}^{\mathrm{OLS}}$ for any $\lambda > 0$. We say then that the ridge estimator is biased.
$\mathbb{E} \big[ \bm{\theta}^{\mathrm{Ridge}} \big] \not= \bm{\theta}^{\mathrm{OLS}}$ for any $\lambda > 0$. We say then that the ridge estimator is biased.
We can also compute the variance as
!bt
\[
\mbox{Var}[\bm{\beta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
\mbox{Var}[\bm{\theta}^{\mathrm{Ridge}}]=\sigma^2[ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1} \mathbf{X}^{T} \mathbf{X} \{ [ \mathbf{X}^{\top} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T},
\]
!et
and it is easy to see that if the parameter $\lambda$ goes to infinity then the variance of Ridge parameters $\bm{\beta}$ goes to zero.
and it is easy to see that if the parameter $\lambda$ goes to infinity then the variance of Ridge parameters $\bm{\theta}$ goes to zero.
With this, we can compute the difference
!bt
\[
\mbox{Var}[\bm{\beta}^{\mathrm{OLS}}]-\mbox{Var}(\bm{\beta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
\mbox{Var}[\bm{\theta}^{\mathrm{OLS}}]-\mbox{Var}(\bm{\theta}^{\mathrm{Ridge}})=\sigma^2 [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}[ 2\lambda\mathbf{I} + \lambda^2 (\mathbf{X}^{T} \mathbf{X})^{-1} ] \{ [ \mathbf{X}^{T} \mathbf{X} + \lambda \mathbf{I} ]^{-1}\}^{T}.
\]
!et
The difference is non-negative definite since each component of the
matrix product is non-negative definite.
This means the variance we obtain with the standard OLS will always for $\lambda > 0$ be larger than the variance of $\bm{\beta}$ obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.
This means the variance we obtain with the standard OLS will always for $\lambda > 0$ be larger than the variance of $\bm{\theta}$ obtained with the Ridge estimator. This has interesting consequences when we discuss the so-called bias-variance trade-off below.
!split
@@ -209,15 +209,15 @@ distribution with zero mean value and an undetermined variance
$\sigma^2$.
We found above that the outputs $\bm{y}$ have a mean value given by
$\bm{X}\hat{\bm{\beta}}$ and variance $\sigma^2$. Since the entries to
$\bm{X}\hat{\bm{\theta}}$ and variance $\sigma^2$. Since the entries to
the design matrix are not stochastic variables, we can assume that the
probability distribution of our targets is also a normal distribution
but now with mean value $\bm{X}\hat{\bm{\beta}}$. This means that a
but now with mean value $\bm{X}\hat{\bm{\theta}}$. This means that a
single output $y_i$ is given by the Gaussian distribution
!bt
\[
y_i\sim \mathcal{N}(\bm{X}_{i,*}\bm{\beta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\bm{X}_{i,*}\bm{\beta})^2}{2\sigma^2}\right]}.
y_i\sim \mathcal{N}(\bm{X}_{i,*}\bm{\theta}, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\bm{X}_{i,*}\bm{\theta})^2}{2\sigma^2}\right]}.
\]
!et
@@ -228,16 +228,16 @@ We assume now that the various $y_i$ values are stochastically distributed accor
We define this distribution as
!bt
\[
p(y_i, \bm{X}\vert\bm{\beta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\bm{X}_{i,*}\bm{\beta})^2}{2\sigma^2}\right]},
p(y_i, \bm{X}\vert\bm{\theta})=\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\bm{X}_{i,*}\bm{\theta})^2}{2\sigma^2}\right]},
\]
!et
which reads as finding the likelihood of an event $y_i$ with the input variables $\bm{X}$ given the parameters (to be determined) $\bm{\beta}$.
which reads as finding the likelihood of an event $y_i$ with the input variables $\bm{X}$ given the parameters (to be determined) $\bm{\theta}$.
Since these events are assumed to be independent and identicall distributed we can build the probability distribution function (PDF) for all possible event $\bm{y}$ as the product of the single events, that is we have
!bt
\[
p(\bm{y},\bm{X}\vert\bm{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\bm{X}_{i,*}\bm{\beta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\bm{X}\vert\bm{\beta}).
p(\bm{y},\bm{X}\vert\bm{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\bm{X}_{i,*}\bm{\theta})^2}{2\sigma^2}\right]}=\prod_{i=0}^{n-1}p(y_i,\bm{X}\vert\bm{\theta}).
\]
!et
@@ -252,11 +252,11 @@ In the more general case the various inputs should be replaced by the possible f
We can now rewrite the above probability as
!bt
\[
p(\bm{D}\vert\bm{\beta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\bm{X}_{i,*}\bm{\beta})^2}{2\sigma^2}\right]}.
p(\bm{D}\vert\bm{\theta})=\prod_{i=0}^{n-1}\frac{1}{\sqrt{2\pi\sigma^2}}\exp{\left[-\frac{(y_i-\bm{X}_{i,*}\bm{\theta})^2}{2\sigma^2}\right]}.
\]
!et
It is a conditional probability (see below) and reads as the likelihood of a domain of events $\bm{D}$ given a set of parameters $\bm{\beta}$.
It is a conditional probability (see below) and reads as the likelihood of a domain of events $\bm{D}$ given a set of parameters $\bm{\theta}$.
!split
===== Maximum Likelihood Estimation (MLE) =====
@@ -269,7 +269,7 @@ data is the most probable.
We will assume here that our events are given by the above Gaussian
distribution and we will determine the optimal parameters $\beta$ by
distribution and we will determine the optimal parameters $\theta$ by
maximizing the above PDF. However, computing the derivatives of a
product function is cumbersome and can easily lead to overflow and/or
underflowproblems, with potentials for loss of numerical precision.
@@ -293,27 +293,27 @@ We could now define a new cost function to minimize, namely the negative logarit
!bt
\[
C(\bm{\beta}=-\log{\prod_{i=0}^{n-1}p(y_i,\bm{X}\vert\bm{\beta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\bm{X}\vert\bm{\beta})},
C(\bm{\theta}=-\log{\prod_{i=0}^{n-1}p(y_i,\bm{X}\vert\bm{\theta})}=-\sum_{i=0}^{n-1}\log{p(y_i,\bm{X}\vert\bm{\theta})},
\]
!et
which becomes
!bt
\[
C(\bm{\beta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\bm{y}-\bm{X}\bm{\beta})\vert\vert_2^2}{2\sigma^2}.
C(\bm{\theta}=\frac{n}{2}\log{2\pi\sigma^2}+\frac{\vert\vert (\bm{y}-\bm{X}\bm{\theta})\vert\vert_2^2}{2\sigma^2}.
\]
!et
Taking the derivative of the *new* cost function with respect to the parameters $\beta$ we recognize our familiar OLS equation, namely
Taking the derivative of the *new* cost function with respect to the parameters $\theta$ we recognize our familiar OLS equation, namely
!bt
\[
\bm{X}^T\left(\bm{y}-\bm{X}\bm{\beta}\right) =0,
\bm{X}^T\left(\bm{y}-\bm{X}\bm{\theta}\right) =0,
\]
!et
which leads to the well-known OLS equation for the optimal paramters $\beta$
which leads to the well-known OLS equation for the optimal paramters $\theta$
!bt
\[
\hat{\bm{\beta}}^{\mathrm{OLS}}=\left(\bm{X}^T\bm{X}\right)^{-1}\bm{X}^T\bm{y}!
\hat{\bm{\theta}}^{\mathrm{OLS}}=\left(\bm{X}^T\bm{X}\right)^{-1}\bm{X}^T\bm{y}!
\]
!et
@@ -601,13 +601,13 @@ $\tilde{p}(x)$.
Confidence intervals are used in statistics and represent a type of estimate
computed from the observed data. This gives a range of values for an
unknown parameter such as the parameters $\bm{\beta}$ from linear regression.
unknown parameter such as the parameters $\bm{\theta}$ from linear regression.
With the OLS expressions for the parameters $\bm{\beta}$ we found
$\mathbb{E}(\bm{\beta}) = \bm{\beta}$, which means that the estimator of the regression parameters is unbiased.
With the OLS expressions for the parameters $\bm{\theta}$ we found
$\mathbb{E}(\bm{\theta}) = \bm{\theta}$, which means that the estimator of the regression parameters is unbiased.
In the exercises this week we show that the variance of the estimate of the $j$-th regression coefficient is
$\bm{\sigma}^2 (\bm{\beta}_j ) = \bm{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} $.
$\bm{\sigma}^2 (\bm{\theta}_j ) = \bm{\sigma}^2 [(\mathbf{X}^{T} \mathbf{X})^{-1}]_{jj} $.
This quantity can be used to
construct a confidence interval for the estimates.
@@ -616,14 +616,14 @@ construct a confidence interval for the estimates.
!split
===== Standard Approach based on the Normal Distribution =====
We will assume that the parameters $\beta$ follow a normal
We will assume that the parameters $\theta$ follow a normal
distribution. We can then define the confidence interval. Here we will be using as
shorthands $\mu_{\beta}$ for the above mean value and $\sigma_{\beta}$
shorthands $\mu_{\theta}$ for the above mean value and $\sigma_{\theta}$
for the standard deviation. We have then a confidence interval
!bt
\[
\left(\mu_{\beta}\pm \frac{z\sigma_{\beta}}{\sqrt{n}}\right),
\left(\mu_{\theta}\pm \frac{z\sigma_{\theta}}{\sqrt{n}}\right),
\]
!et
@@ -642,11 +642,11 @@ Bootstrap method, why it works and various theorems related to it.
!split
===== Resampling methods: Bootstrap background =====
Since $\widehat{\beta} = \widehat{\beta}(\bm{X})$ is a function of random variables,
$\widehat{\beta}$ itself must be a random variable. Thus it has
Since $\widehat{\theta} = \widehat{\theta}(\bm{X})$ is a function of random variables,
$\widehat{\theta}$ itself must be a random variable. Thus it has
a pdf, call this function $p(\bm{t})$. The aim of the bootstrap is to
estimate $p(\bm{t})$ by the relative frequency of
$\widehat{\beta}$. You can think of this as using a histogram
$\widehat{\theta}$. You can think of this as using a histogram
in the place of $p(\bm{t})$. If the relative frequency closely
resembles $p(\vec{t})$, then using numerics, it is straight forward to
estimate all the interesting parameters of $p(\bm{t})$ using point
@@ -656,17 +656,17 @@ estimators.
!split
===== Resampling methods: More Bootstrap background =====
In the case that $\widehat{\beta}$ has
In the case that $\widehat{\theta}$ has
more than one component, and the components are independent, we use the
same estimator on each component separately. If the probability
density function of $X_i$, $p(x)$, had been known, then it would have
been straightforward to do this by:
o Drawing lots of numbers from $p(x)$, suppose we call one such set of numbers $(X_1^*, X_2^*, \cdots, X_n^*)$.
o Then using these numbers, we could compute a replica of $\widehat{\beta}$ called $\widehat{\beta}^*$.
o Then using these numbers, we could compute a replica of $\widehat{\theta}$ called $\widehat{\theta}^*$.
By repeated use of the above two points, many
estimates of $\widehat{\beta}$ can be obtained. The
idea is to use the relative frequency of $\widehat{\beta}^*$
estimates of $\widehat{\theta}$ can be obtained. The
idea is to use the relative frequency of $\widehat{\theta}^*$
(think of a histogram) as an estimate of $p(\bm{t})$.
!split
@@ -692,18 +692,18 @@ The independent bootstrap works like this:
o Draw with replacement $n$ numbers for the observed variables $\bm{x} = (x_1,x_2,\cdots,x_n)$.
o Define a vector $\bm{x}^*$ containing the values which were drawn from $\bm{x}$.
o Using the vector $\bm{x}^*$ compute $\widehat{\beta}^*$ by evaluating $\widehat \beta$ under the observations $\bm{x}^*$.
o Using the vector $\bm{x}^*$ compute $\widehat{\theta}^*$ by evaluating $\widehat \theta$ under the observations $\bm{x}^*$.
o Repeat this process $k$ times.
When you are done, you can draw a histogram of the relative frequency
of $\widehat \beta^*$. This is your estimate of the probability
of $\widehat \theta^*$. This is your estimate of the probability
distribution $p(t)$. Using this probability distribution you can
estimate any statistics thereof. In principle you never draw the
histogram of the relative frequency of $\widehat{\beta}^*$. Instead
histogram of the relative frequency of $\widehat{\theta}^*$. Instead
you use the estimators corresponding to the statistic of interest. For
example, if you are interested in estimating the variance of $\widehat
\beta$, apply the etsimator $\widehat \sigma^2$ to the values
$\widehat \beta^*$.
\theta$, apply the etsimator $\widehat \sigma^2$ to the values
$\widehat \theta^*$.
!split
@@ -791,13 +791,13 @@ where $\epsilon$ is normally distributed with mean zero and standard deviation $
In our derivation of the ordinary least squares method we defined then
an approximation to the function $f$ in terms of the parameters
$\bm{\beta}$ and the design matrix $\bm{X}$ which embody our model,
that is $\bm{\tilde{y}}=\bm{X}\bm{\beta}$.
$\bm{\theta}$ and the design matrix $\bm{X}$ which embody our model,
that is $\bm{\tilde{y}}=\bm{X}\bm{\theta}$.
Thereafter we found the parameters $\bm{\beta}$ by optimizing the means squared error via the so-called cost function
Thereafter we found the parameters $\bm{\theta}$ by optimizing the means squared error via the so-called cost function
!bt
\[
C(\bm{X},\bm{\beta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\bm{y}-\bm{\tilde{y}})^2\right].
C(\bm{X},\bm{\theta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2=\mathbb{E}\left[(\bm{y}-\bm{\tilde{y}})^2\right].
\]
!et