update on lin algebra

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mhjensen
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<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta name="generator" content="DocOnce: https://github.com/hplgit/doconce/" />
<meta name="description" content="Data analysis and Machine Learning Lectures: Linear Algebra methods">
<meta name="description" content="Data analysis and Machine Learning Lectures: Linear Algebra and Handling of Arrays">
<title>Data analysis and Machine Learning Lectures: Linear Algebra methods</title>
<title>Data analysis and Machine Learning Lectures: Linear Algebra and Handling of Arrays</title>
@@ -132,7 +132,7 @@ MathJax.Hub.Config({
<center><h1 style="text-align: center;">Data analysis and Machine Learning Lectures: Linear Algebra methods </h1></center> <!-- document title -->
<center><h1 style="text-align: center;">Data analysis and Machine Learning Lectures: Linear Algebra and Handling of Arrays</h1></center> <!-- document title -->
<p>
<!-- author(s): Morten Hjorth-Jensen -->
@@ -148,7 +148,7 @@ MathJax.Hub.Config({
<center>[2] <b>Department of Physics and Astronomy and National Superconducting Cyclotron Laboratory, Michigan State University</b></center>
<br>
<p>&nbsp;<br>
<center><h4>May 22, 2018</h4></center> <!-- date -->
<center><h4>May 24, 2018</h4></center> <!-- date -->
<br>
<p>
@@ -159,12 +159,19 @@ MathJax.Hub.Config({
<section>
<h2 id="___sec0">To do </h2>
<h2 id="___sec0">Introduction </h2>
The aim of this set of lectures is to review some central linear algebra algorithms that we will need in our
data analysis part and in the construction of Machine Learning algorithms (ML).
This will allow us to introduce some central programming features of high-level languages like Python and
compiled languages like C++ and/or Fortran.
<ul>
<p><li> add material on python handling of matrices and vectors</li>
<p><li> keep c++ material?</li>
</ul>
<p>
As discussed in the introductory notes, these series of lectures focuses both on using
central Python packages like <b>tensorflow</b> and <b>scikit-learn</b> as well
as writing your own codes for some central ML algorithms. The
latter can be written in a language of your choice, be it Python, Julia, R,
Rust, C++, Fortran etc. In order to avoid confusion however, in these lectures we will limit our
attention to Python, C++ and Fortran.
</section>
@@ -172,10 +179,10 @@ MathJax.Hub.Config({
<h2 id="___sec1">Important Matrix and vector handling packages </h2>
<p>
The Numerical Recipes codes have been rewritten in Fortran 90/95 and
C/C++ by us. The original source codes are taken from the widely used
There are several central software packages for linear algebra and eigenvalue problems. Several of the more
popular ones have been wrapped into ofter software packages like those from the widely used text <b>Numerical Recipes</b>. The original source codes in many of the available packages are often taken from the widely used
software package LAPACK, which follows two other popular packages
developed in the 1970s, namely EISPACK and LINPACK.
developed in the 1970s, namely EISPACK and LINPACK. We describe them shortly here.
<ul>
@@ -187,7 +194,22 @@ developed in the 1970s, namely EISPACK and LINPACK.
</ul>
<p>
<b>Add python material on linear algebra and array handling, text on numpy etc</b>
When dealing with matrices and vectors a central issue is memory
handling and allocation. If our code is written in Python the way we
declare these objects and the way they are handled, interpreted and
used by say a linear algebra library, requires codes that interface
our Python program with such libraries. For Python programmers,
<b>Numpy</b> is by now the standard Python package for numerical arrays in
Python as well as the source of functions which act on these
arrays. These functions span from eigenvalue solvers to functions that
compute the mean value, variance or the covariance matrix. If you are
not familiar with how arrays are handled in say Python or compiled
languages like C++ and Fortran, the sections in this chapter may be
useful. For C++ programmer, <b>Armadillo</b> is widely used library for
linear algebra and eigenvalue problems. In addition it offers a
convenient way to handle and organize arrays. We discuss this library
as well. Before we proceed we believe it may be convenient to repeat some basic features of
matrices and vectors.
</section>
@@ -311,7 +333,217 @@ For an \( N\times N \) matrix \( \mathbf{A} \) the following properties are all
<section>
<h2 id="___sec7">Matrix Handling in C/C++, Static and Dynamical allocation </h2>
<h2 id="___sec7">Numpy and arrays </h2>
<a href="http://www.numpy.org/" target="_blank">Numpy</a> provides an easy way to handle arrays in Python. The standard way to import this library is as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
n = <span style="color: #B452CD">10</span>
x = np.random.normal(size=n)
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
Here we have defined a vector \( x \) with \( n=10 \) elements with its values given by the Normal distribution \( N(0,1) \).
Another alternative is to declare a vector as follows
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
x = np.array([<span style="color: #B452CD">1</span>, <span style="color: #B452CD">2</span>, <span style="color: #B452CD">3</span>])
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
Here we have defined a vector with three elements, with \( x_0=1 \), \( x_1=2 \) and \( x_2=3 \). Note that both Python and C++
start numbering array elements from \( 0 \) and on. This means that a vector with \( n \) elements has a sequence of entities \( x_0, x_1, x_2, \dots, x_{n-1} \). We could also let (recommended) Numpy to compute the logarithms of a specific array as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
x = np.log(np.array([<span style="color: #B452CD">4</span>, <span style="color: #B452CD">7</span>, <span style="color: #B452CD">8</span>]))
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
Here we have used Numpy's unary function \( np.log \). This function is
highly tuned to compute array elements since the code is vectorized
and does not require looping. We normaly recommend that you use the
Numpy intrinsic functions instead of the corresponding <b>log</b> function
from Python's <b>math</b> module. The looping is done explicitely by the
<b>np.log</b> function. The alternative, and slower way to compute the
logarithms of a vector would be to write
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
<span style="color: #8B008B; font-weight: bold">from</span> <span style="color: #008b45; text-decoration: underline">math</span> <span style="color: #8B008B; font-weight: bold">import</span> log
x = np.array([<span style="color: #B452CD">4</span>, <span style="color: #B452CD">7</span>, <span style="color: #B452CD">8</span>])
<span style="color: #8B008B; font-weight: bold">for</span> i <span style="color: #8B008B">in</span> <span style="color: #658b00">range</span>(<span style="color: #B452CD">0</span>, <span style="color: #658b00">len</span>(x)):
x[i] = log(x[i])
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
We note that our code is much longer already and we need to import the <b>log</b> function from the <b>math</b> module.
The attentive reader will also notice that the output is \( [1, 1, 2] \). Python interprets automacally our numbers as integers (like the <b>automatic</b> keyword in C++). To change this we could define our array elements to be double precision numbers as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
x = np.log(np.array([<span style="color: #B452CD">4</span>, <span style="color: #B452CD">7</span>, <span style="color: #B452CD">8</span>], dtype = np.float64))
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
or simply write them as double precision numbers (Python uses 64 bits as default for floating point type variables), that is
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
x = np.log(np.array([<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">7.0</span>, <span style="color: #B452CD">8.0</span>])
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
To check the number of bytes (remember that one byte contains eight bits for double precision variables), you can use simple use the <b>itemsize</b> functionality (the array \( x \) is actually an object which inherits the functionalities defined in Numpy) as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
x = np.log(np.array([<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">7.0</span>, <span style="color: #B452CD">8.0</span>])
<span style="color: #8B008B; font-weight: bold">print</span>(x.itemsize)
</pre></div>
</section>
<section>
<h2 id="___sec8">Matrices in Python </h2>
Having defined vectors, we are now ready to try out matrices. We can define a \( 3 \times 3 \) real matrix \( \hat{A} \)
as (recall that we user lowercase letters for vectors and uppercase letters for matrices)
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
A = np.log(np.array([ [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">7.0</span>, <span style="color: #B452CD">8.0</span>], [<span style="color: #B452CD">3.0</span>, <span style="color: #B452CD">10.0</span>, <span style="color: #B452CD">11.0</span>], [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">5.0</span>, <span style="color: #B452CD">7.0</span>] ]))
<span style="color: #8B008B; font-weight: bold">print</span>(A)
</pre></div>
<p>
If we use the <b>shape</b> function we would get \( (3, 3) \) as output, that is verifying that our matrix is a \( 3\times 3 \) matrix. We can slice the matrix and print for example the first column (Python organized matrix elements in a row-major order, see below) as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
A = np.log(np.array([ [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">7.0</span>, <span style="color: #B452CD">8.0</span>], [<span style="color: #B452CD">3.0</span>, <span style="color: #B452CD">10.0</span>, <span style="color: #B452CD">11.0</span>], [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">5.0</span>, <span style="color: #B452CD">7.0</span>] ]))
<span style="color: #228B22"># print the first column, row-major order and elements start with 0</span>
<span style="color: #8B008B; font-weight: bold">print</span>(A[:,<span style="color: #B452CD">0</span>])
</pre></div>
<p>
We can continue this was by printing out other columns or rows. The example here prints out the second column
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
A = np.log(np.array([ [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">7.0</span>, <span style="color: #B452CD">8.0</span>], [<span style="color: #B452CD">3.0</span>, <span style="color: #B452CD">10.0</span>, <span style="color: #B452CD">11.0</span>], [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">5.0</span>, <span style="color: #B452CD">7.0</span>] ]))
<span style="color: #228B22"># print the first column, row-major order and elements start with 0</span>
<span style="color: #8B008B; font-weight: bold">print</span>(A[<span style="color: #B452CD">1</span>,:])
</pre></div>
<p>
Numpy contains many other functionalities that allow us to slice, subdivide etc etc arrays. We strongly recommend that you look up the <a href="http://www.numpy.org/" target="_blank">Numpy website for more details</a>. Useful functions when defining a matrix are the <b>np.zeros</b> function which declares a matrix of a given dimension and sets all elements to zero
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
n = <span style="color: #B452CD">10</span>
<span style="color: #228B22"># define a matrix of dimension 10 x 10 and set all elements to zero</span>
A = np.zeros( (n, n) )
<span style="color: #8B008B; font-weight: bold">print</span>(A)
</pre></div>
<p>
or initializing all elements to
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
n = <span style="color: #B452CD">10</span>
<span style="color: #228B22"># define a matrix of dimension 10 x 10 and set all elements to one</span>
A = np.ones( (n, n) )
<span style="color: #8B008B; font-weight: bold">print</span>(A)
</pre></div>
<p>
or as unitarily distributed random numbers (see the material on random number generators in the statistics part)
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
n = <span style="color: #B452CD">10</span>
<span style="color: #228B22"># define a matrix of dimension 10 x 10 and set all elements to random numbers with x \in [0, 1]</span>
A = np.random.rand(n, n)
<span style="color: #8B008B; font-weight: bold">print</span>(A)
</pre></div>
<p>
As we will see throughout these lectures, there are several extremely useful functionalities in Numpy.
As an example, consider the discussion of the covariance matrix. Suppose we have defined three vectors
\( \hat{x}, \hat{y}, \hat{z} \) with \( n \) elements each. The covariance matrix is defined as
<p>&nbsp;<br>
$$
\hat{\Sigma} = \begin{bmatrix} \sigma_{xx} & \sigma_{xy} & \sigma_{xz} \\
\sigma_{yx} & \sigma_{yy} & \sigma_{yz} \\
\sigma_{zx} & \sigma_{zy} & \sigma_{zz}
\end{bmatrix},
$$
<p>&nbsp;<br>
where for example
<p>&nbsp;<br>
$$
\sigma_{xy} =\frac{1}{n} \sum_{i=0}^{n-1}(x_i- \overline{x})(y_i- \overline{y}).
$$
<p>&nbsp;<br>
The Numpy function <b>np.cov</b> calculates the covariance elements using the factor \( 1/(n-1) \) instead of \( 1/n \) since it assumes we do not have the exact mean values. For a more in-depth discussion of the covariance and covariance matrix and its meaning, we refer you to the lectures on statistics.
The following simple function uses the <b>np.vstack</b> function which takes each vector of dimension \( 1\times n \) and produces a $ 3\times n$ matrix \( \hat{W} \)
<p>&nbsp;<br>
$$
\hat{W} = \begin{bmatrix} x_0 & y_0 & z_0 \\
x_1 & y_1 & z_1 \\
x_2 & y_2 & z_2 \\
\dots & \dots & \dots \\
x_{n-2} & y_{n-2} & z_{n-2} \\
x_{n-1} & y_{n-1} & z_{n-1}
\end{bmatrix},
$$
<p>&nbsp;<br>
<p>
which in turn is converted into into the \( 3 times 3 \) covariance matrix
\( \hat{\Sigma} \) via the Numpy function <b>np.cov()</b>. In our review of
statistical functions and quantities we will discuss more about the
meaning of the covariance matrix. Here we note that we can calculate
the mean value of each set of samples \( \hat{x} \) etc using the Numpy
function <b>np.mean(x)</b>. We can also extract the eigenvalues of the
covariance matrix through the <b>np.linalg.eig()</b> function.
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="font-size: 80%; line-height: 125%"><span></span><span style="color: #228B22"># Importing various packages</span>
<span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
n = <span style="color: #B452CD">100</span>
x = np.random.normal(size=n)
<span style="color: #8B008B; font-weight: bold">print</span>(np.mean(x))
y = <span style="color: #B452CD">4</span>+<span style="color: #B452CD">3</span>*x+np.random.normal(size=n)
<span style="color: #8B008B; font-weight: bold">print</span>(np.mean(y))
z = x**<span style="color: #B452CD">3</span>+np.random.normal(size=n)
<span style="color: #8B008B; font-weight: bold">print</span>(np.mean(z))
W = np.vstack((x, y, z))
Sigma = np.cov(W)
<span style="color: #8B008B; font-weight: bold">print</span>(Sigma)
Eigvals, Eigvecs = np.linalg.eig(Sigma)
<span style="color: #8B008B; font-weight: bold">print</span>(Eigvals)
</pre></div>
</section>
<section>
<h2 id="___sec9">Matrix Handling in C/C++, Static and Dynamical allocation </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -337,7 +569,7 @@ Note the way the matrix is organized, row-major order.
<section>
<h2 id="___sec8">Matrix Handling in C/C++ </h2>
<h2 id="___sec10">Matrix Handling in C/C++ </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -367,7 +599,7 @@ In C/C++ this would be coded like
<section>
<h2 id="___sec9">Matrix Handling in C/C++ </h2>
<h2 id="___sec11">Matrix Handling in C/C++ </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -398,7 +630,7 @@ In C/C++ this would be coded like
<section>
<h2 id="___sec10">Dynamic memory allocation in C/C++ </h2>
<h2 id="___sec12">Dynamic memory allocation in C/C++ </h2>
<p>
At least three possibilities in this course
@@ -415,7 +647,7 @@ At least three possibilities in this course
<section>
<h2 id="___sec11">Matrix Handling in C/C++, Dynamic Allocation </h2>
<h2 id="___sec13">Matrix Handling in C/C++, Dynamic Allocation </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -445,7 +677,7 @@ Always free space when you don't need an array anymore.
<section>
<h2 id="___sec12">Armadillo, recommended!! </h2>
<h2 id="___sec14">Armadillo, recommended!! </h2>
<ul>
@@ -463,7 +695,7 @@ Always free space when you don't need an array anymore.
<section>
<h2 id="___sec13">Armadillo, simple examples </h2>
<h2 id="___sec15">Armadillo, simple examples </h2>
<p>
@@ -487,7 +719,7 @@ Always free space when you don't need an array anymore.
<section>
<h2 id="___sec14">Armadillo, how to compile and install </h2>
<h2 id="___sec16">Armadillo, how to compile and install </h2>
<p>
For people using Ubuntu, Debian, Linux Mint, simply go to the synaptic package manager and install
@@ -516,7 +748,7 @@ For OS X users you may have to declare the paths to the include files and the li
<section>
<h2 id="___sec15">Armadillo, simple examples </h2>
<h2 id="___sec17">Armadillo, simple examples </h2>
<p>
@@ -550,7 +782,7 @@ For OS X users you may have to declare the paths to the include files and the li
<section>
<h2 id="___sec16">Armadillo, simple examples </h2>
<h2 id="___sec18">Armadillo, simple examples </h2>
<p>
@@ -582,7 +814,7 @@ For OS X users you may have to declare the paths to the include files and the li
<section>
<h2 id="___sec17">Armadillo, simple examples </h2>
<h2 id="___sec19">Armadillo, simple examples </h2>
<p>
@@ -616,7 +848,7 @@ For OS X users you may have to declare the paths to the include files and the li
<section>
<h2 id="___sec18">Armadillo, simple examples </h2>
<h2 id="___sec20">Armadillo, simple examples </h2>
<p>
@@ -645,7 +877,7 @@ For OS X users you may have to declare the paths to the include files and the li
<section>
<h2 id="___sec19">Armadillo, simple examples </h2>
<h2 id="___sec21">Armadillo, simple examples </h2>
<p>
@@ -678,7 +910,7 @@ For OS X users you may have to declare the paths to the include files and the li
<section>
<h2 id="___sec20">Armadillo, simple examples </h2>
<h2 id="___sec22">Armadillo, simple examples </h2>
<p>
@@ -709,7 +941,7 @@ For OS X users you may have to declare the paths to the include files and the li
<section>
<h2 id="___sec21">Armadillo, simple examples </h2>
<h2 id="___sec23">Armadillo, simple examples </h2>
<p>
@@ -742,7 +974,7 @@ For OS X users you may have to declare the paths to the include files and the li
<section>
<h2 id="___sec22">Gaussian Elimination </h2>
<h2 id="___sec24">Gaussian Elimination </h2>
<p>
We start with the linear set of equations
@@ -781,7 +1013,7 @@ $$
<section>
<h2 id="___sec23">Gaussian Elimination </h2>
<h2 id="___sec25">Gaussian Elimination </h2>
or
<p>&nbsp;<br>
@@ -798,7 +1030,7 @@ $$
<section>
<h2 id="___sec24">Gaussian Elimination </h2>
<h2 id="___sec26">Gaussian Elimination </h2>
<p>
The basic idea of Gaussian elimination is to use the first equation to eliminate the first unknown \( x_1 \)
@@ -824,7 +1056,7 @@ what is called a backward substitution.
<section>
<h2 id="___sec25">Gaussian Elimination </h2>
<h2 id="___sec27">Gaussian Elimination </h2>
This process can be expressed mathematically as
<p>&nbsp;<br>
@@ -844,7 +1076,7 @@ the result from the $j$th equation. We assume obviously that \( a_{11}\ne 0 \) a
<section>
<h2 id="___sec26">Gaussian Elimination </h2>
<h2 id="___sec28">Gaussian Elimination </h2>
<p>
Our actual \( 4\times 4 \) example reads after the first operation
@@ -888,7 +1120,7 @@ $$
<section>
<h2 id="___sec27">Gaussian Elimination </h2>
<h2 id="___sec29">Gaussian Elimination </h2>
<p>
The new coefficients are
@@ -930,7 +1162,7 @@ We see that the system of unknowns \( x_1,\dots,x_n \) is transformed into an \(
<section>
<h2 id="___sec28">Gaussian Elimination </h2>
<h2 id="___sec30">Gaussian Elimination </h2>
<p>
This step is called forward substitution.
@@ -972,7 +1204,7 @@ adding \( 10^7+1 \). With single precision this results in \( 10^7 \).
<section>
<h2 id="___sec29">Linear Algebra Methods </h2>
<h2 id="___sec31">Linear Algebra Methods </h2>
<ul>
@@ -992,7 +1224,7 @@ adding \( 10^7+1 \). With single precision this results in \( 10^7 \).
<section>
<h2 id="___sec30">LU Decomposition </h2>
<h2 id="___sec32">LU Decomposition </h2>
<p>
The LU decomposition method means that we can rewrite
@@ -1025,7 +1257,7 @@ $$
<section>
<h2 id="___sec31">LU Decomposition </h2>
<h2 id="___sec33">LU Decomposition </h2>
<p>
LU decomposition forms the backbone of other algorithms in linear algebra, such as the
@@ -1058,7 +1290,7 @@ $$
<section>
<h2 id="___sec32">LU Decomposition, why? </h2>
<h2 id="___sec34">LU Decomposition, why? </h2>
<p>
There are at least three main advantages with LU decomposition compared with standard Gaussian elimination:
@@ -1075,7 +1307,7 @@ There are at least three main advantages with LU decomposition compared with sta
<section>
<h2 id="___sec33">LU Decomposition, linear equations </h2>
<h2 id="___sec35">LU Decomposition, linear equations </h2>
<p>
With the LU decomposition it is rather
@@ -1110,7 +1342,7 @@ $$ \mathbf{A} \mathbf{x} \equiv \mathbf{L} \mathbf{U} \mathbf{x} =\mathbf{w}. $$
<section>
<h2 id="___sec34">LU Decomposition, linear equations </h2>
<h2 id="___sec36">LU Decomposition, linear equations </h2>
<p>
The previous equation can be calculated in two steps
@@ -1127,7 +1359,7 @@ to rewrite our system of linear equations as
$$ \mathbf{LUx}=\mathbf{w}, $$
<p>&nbsp;<br>
and since the determinat of \( \mathbf{L} \) is equal to 1 (by construction
and since the determinant of \( \mathbf{L} \) is equal to 1 (by construction
since the diagonals of \( \mathbf{L} \) equal 1) we can use the inverse of
\( \mathbf{L} \) to obtain
@@ -1151,7 +1383,7 @@ through \( \mathbf{Ux}=\mathbf{y} \).
<section>
<h2 id="___sec35">LU Decomposition, why? </h2>
<h2 id="___sec37">LU Decomposition, why? </h2>
<p>
For our four-dimentional example this takes the form
@@ -1188,7 +1420,7 @@ needed to solve the set of \( n \) linear equations.
<section>
<h2 id="___sec36">LU Decomposition, linear equations </h2>
<h2 id="___sec38">LU Decomposition, linear equations </h2>
<p>
The algorithm goes as follows
@@ -1205,7 +1437,7 @@ The algorithm goes as follows
<section>
<h2 id="___sec37">LU Decomposition, the inverse of a matrix </h2>
<h2 id="___sec39">LU Decomposition, the inverse of a matrix </h2>
<p>
If the inverse exists then
@@ -1227,7 +1459,7 @@ $$
<section>
<h2 id="___sec38">LU Decomposition, the inverse of a matrix </h2>
<h2 id="___sec40">LU Decomposition, the inverse of a matrix </h2>
<p>
If we assume that the first column (that is column 1) of the inverse matrix
@@ -1265,7 +1497,7 @@ $$
<section>
<h2 id="___sec39">LU Decomposition, the inverse </h2>
<h2 id="___sec41">LU Decomposition, the inverse </h2>
<p>
In a similar way we can compute the unknow entries of the second column,
@@ -1291,7 +1523,7 @@ and continue till we have solved all \( n \) sets of linear equations.
<section>
<h2 id="___sec40"><a href="https://github.com/CompPhysics/ComputationalPhysicsMSU/blob/master/doc/Programs/CppQtCodesLectures/MatrixTest/main.cpp" target="_blank">Using Armadillo to perform an LU decomposition</a> </h2>
<h2 id="___sec42"><a href="https://github.com/CompPhysics/ComputationalPhysicsMSU/blob/master/doc/Programs/CppQtCodesLectures/MatrixTest/main.cpp" target="_blank">Using Armadillo to perform an LU decomposition</a> </h2>
<p>
<!-- code=c++ (!bc cppcod) typeset with pygments style "perldoc" -->
@@ -1326,260 +1558,6 @@ and continue till we have solved all \( n \) sets of linear equations.
</section>
<section>
<h2 id="___sec41">Iterative methods, Chapter 6 </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<ul>
<p><li> Direct solvers such as Gauss elimination and LU decomposition discussed in connection with project 1.</li>
<p><li> Iterative solvers such as Basic iterative solvers, Jacobi, Gauss-Seidel, Successive over-relaxation. These methods are easy to parallelize, as we will se later. Much used in solutions of partial differential equations.</li>
<p><li> Other iterative methods such as Krylov subspace methods with Generalized minimum residual (GMRES) and Conjugate gradient etc will not be discussed.</li>
</ul>
</div>
</section>
<section>
<h2 id="___sec42">Iterative methods, Jacobi's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
It is a simple method for solving
<p>&nbsp;<br>
$$
\mathbf{A}\mathbf{x}=\mathbf{b},
$$
<p>&nbsp;<br>
where \( \mathbf{A} \) is a matrix and \( \mathbf{x} \) and \( \mathbf{b} \) are vectors. The vector \( \mathbf{x} \) is
the unknown.
<p>
It is an iterative scheme where we start with a guess for the unknown, and
after \( k+1 \) iterations we have
<p>&nbsp;<br>
$$
\mathbf{x}^{(k+1)}= \mathbf{D}^{-1}(\mathbf{b}-(\mathbf{L}+\mathbf{U})\mathbf{x}^{(k)}),
$$
<p>&nbsp;<br>
with \( \mathbf{A}=\mathbf{D}+\mathbf{U}+\mathbf{L} \) and
\( \mathbf{D} \) being a diagonal matrix, \( \mathbf{U} \) an upper triangular matrix and \( \mathbf{L} \) a lower triangular
matrix.
<p>
If the matrix \( \mathbf{A} \) is positive definite or diagonally dominant, one can show that this method will always converge to the exact solution.
</div>
</section>
<section>
<h2 id="___sec43">Iterative methods, Jacobi's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
We can demonstrate Jacobi's method by this \( 4\times 4 \) matrix problem. We assume a guess
for the vector elements \( x_i^{(0)} \), a guess which represents our first iteration. The new
values are obtained by substitution
<p>&nbsp;<br>
$$
\begin{align}
x_1^{(1)} =&(b_1-a_{12}x_2^{(0)} -a_{13}x_3^{(0)} - a_{14}x_4^{(0)})/a_{11} \nonumber \\
x_2^{(1)} =&(b_2-a_{21}x_1^{(0)} - a_{23}x_3^{(0)} - a_{24}x_4^{(0)})/a_{22} \nonumber \\
x_3^{(1)} =&(b_3- a_{31}x_1^{(0)} -a_{32}x_2^{(0)} -a_{34}x_4^{(0)})/a_{33} \nonumber \\
x_4^{(1)}=&(b_4-a_{41}x_1^{(0)} -a_{42}x_2^{(0)} - a_{43}x_3^{(0)})/a_{44}, \nonumber
\end{align}
$$
<p>&nbsp;<br>
which after \( k+1 \) iterations reads
<p>&nbsp;<br>
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k)} -a_{32}x_2^{(k)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k)} -a_{42}x_2^{(k)} - a_{43}x_3^{(k)})/a_{44}, \nonumber
\end{align}
$$
<p>&nbsp;<br>
</div>
</section>
<section>
<h2 id="___sec44">Iterative methods, Jacobi's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
We can generalize the above equations to
<p>&nbsp;<br>
$$
x_i^{(k+1)}=(b_i-\sum_{j=1, j\ne i}^{n}a_{ij}x_j^{(k)})/a_{ii}
$$
<p>&nbsp;<br>
or in an even more compact form as
<p>&nbsp;<br>
$$ \mathbf{x}^{(k+1)}= \mathbf{D}^{-1}(\mathbf{b}-(\mathbf{L}+\mathbf{U})\mathbf{x}^{(k)}),
$$
<p>&nbsp;<br>
with \( \mathbf{A}=\mathbf{D}+\mathbf{U}+\mathbf{L} \) and
\( \mathbf{D} \) being a diagonal matrix, \( \mathbf{U} \) an upper triangular matrix and \( \mathbf{L} \) a lower triangular
matrix.
</div>
</section>
<section>
<h2 id="___sec45">Iterative methods, Gauss-Seidel's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
Our \( 4\times 4 \) matrix problem
<p>&nbsp;<br>
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k)} -a_{32}x_2^{(k)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k)} -a_{42}x_2^{(k)} - a_{43}x_3^{(k)})/a_{44}, \nonumber
\end{align}
$$
<p>&nbsp;<br>
can be rewritten as
<p>&nbsp;<br>
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k+1)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k+1)} -a_{32}x_2^{(k+1)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k+1)} -a_{42}x_2^{(k+1)} - a_{43}x_3^{(k+1)})/a_{44}, \nonumber
\end{align}
$$
<p>&nbsp;<br>
which allows us to utilize the preceding solution (forward substitution). This improves normally the convergence
behavior and leads to the Gauss-Seidel method!
</div>
</section>
<section>
<h2 id="___sec46">Iterative methods, Gauss-Seidel's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
We can generalize
<p>&nbsp;<br>
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k+1)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k+1)} -a_{32}x_2^{(k+1)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k+1)} -a_{42}x_2^{(k+1)} - a_{43}x_3^{(k+1)})/a_{44}, \nonumber
\end{align}
$$
<p>&nbsp;<br>
to the following form
<p>&nbsp;<br>
$$
x^{(k+1)}_i = \frac{1}{a_{ii}} \left(b_i - \sum_{j > i}a_{ij}x^{(k)}_j - \sum_{j < i}a_{ij}x^{(k+1)}_j \right),\quad i=1,2,\ldots,n.
$$
<p>&nbsp;<br>
The procedure is generally continued until the changes made by an iteration are below some tolerance.
<p>
The convergence properties of the Jacobi method and the
Gauss-Seidel method are dependent on the matrix \( \mathbf{A} \). These methods converge when
the matrix is symmetric positive-definite, or is strictly or irreducibly diagonally dominant.
Both methods sometimes converge even if these conditions are not satisfied.
</div>
</section>
<section>
<h2 id="___sec47">Iterative methods, Successive over-relaxation </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
Given a square system of n linear equations with unknown \( \mathbf x \):
<p>&nbsp;<br>
$$
\mathbf{A}\mathbf x = \mathbf b
$$
<p>&nbsp;<br>
where
<p>&nbsp;<br>
$$
\mathbf{A}=\begin{bmatrix} a_{11} & a_{12} & \cdots & a_{1n} \\ a_{21} & a_{22} & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\a_{n1} & a_{n2} & \cdots & a_{nn} \end{bmatrix}, \qquad \mathbf{x} = \begin{bmatrix} x_{1} \\ x_2 \\ \vdots \\ x_n \end{bmatrix} , \qquad \mathbf{b} = \begin{bmatrix} b_{1} \\ b_2 \\ \vdots \\ b_n \end{bmatrix}.
$$
<p>&nbsp;<br>
</div>
</section>
<section>
<h2 id="___sec48">Iterative methods, Successive over-relaxation </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
Then A can be decomposed into a diagonal component D, and strictly lower and upper triangular components L and U:
<p>&nbsp;<br>
$$
\mathbf{A} =\mathbf{D} + \mathbf{L} + \mathbf{U},
$$
<p>&nbsp;<br>
where
<p>&nbsp;<br>
$$
D = \begin{bmatrix} a_{11} & 0 & \cdots & 0 \\ 0 & a_{22} & \cdots & 0 \\ \vdots & \vdots & \ddots & \vdots \\0 & 0 & \cdots & a_{nn} \end{bmatrix}, \quad L = \begin{bmatrix} 0 & 0 & \cdots & 0 \\ a_{21} & 0 & \cdots & 0 \\ \vdots & \vdots & \ddots & \vdots \\a_{n1} & a_{n2} & \cdots & 0 \end{bmatrix}, \quad U = \begin{bmatrix} 0 & a_{12} & \cdots & a_{1n} \\ 0 & 0 & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\0 & 0 & \cdots & 0 \end{bmatrix}.
$$
<p>&nbsp;<br>
The system of linear equations may be rewritten as:
<p>&nbsp;<br>
$$
(D+\omega L) \mathbf{x} = \omega \mathbf{b} - [\omega U + (\omega-1) D ] \mathbf{x}
$$
<p>&nbsp;<br>
for a constant \( \omega > 1 \).
</div>
</section>
<section>
<h2 id="___sec49">Iterative methods, Successive over-relaxation </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
The method of successive over-relaxation is an iterative technique that solves the left hand side of this expression for \( x \), using previous value for \( x \) on the right hand side. Analytically, this may be written as:
<p>&nbsp;<br>
$$
\mathbf{x}^{(k+1)} = (D+\omega L)^{-1} \big(\omega \mathbf{b} - [\omega U + (\omega-1) D ] \mathbf{x}^{(k)}\big).
$$
<p>&nbsp;<br>
However, by taking advantage of the triangular form of \( (D+\omega L) \), the elements of \( x^{(k+1)} \) can be computed sequentially using forward substitution:
<p>&nbsp;<br>
$$
x^{(k+1)}_i = (1-\omega)x^{(k)}_i + \frac{\omega}{a_{ii}} \left(b_i - \sum_{j > i} a_{ij}x^{(k)}_j - \sum_{j < i} a_{ij}x^{(k+1)}_j \right),\quad i=1,2,\ldots,n.
$$
<p>&nbsp;<br>
The choice of relaxation factor is not necessarily easy, and depends upon the properties of the coefficient matrix. For symmetric, positive-definite matrices it can be proven that \( 0 < \omega < 2 \) will lead to convergence, but we are generally interested in faster convergence rather than just convergence.
</div>
</section>
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@@ -163,7 +147,7 @@ MathJax.Hub.Config({
<center><h1>Data analysis and Machine Learning Lectures: Linear Algebra methods </h1></center> <!-- document title -->
<center><h1>Data analysis and Machine Learning Lectures: Linear Algebra and Handling of Arrays</h1></center> <!-- document title -->
<p>
<!-- author(s): Morten Hjorth-Jensen -->
@@ -179,27 +163,35 @@ MathJax.Hub.Config({
<center>[2] <b>Department of Physics and Astronomy and National Superconducting Cyclotron Laboratory, Michigan State University</b></center>
<br>
<p>
<center><h4>May 22, 2018</h4></center> <!-- date -->
<center><h4>May 24, 2018</h4></center> <!-- date -->
<br>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec0">To do </h2>
<h2 id="___sec0">Introduction </h2>
The aim of this set of lectures is to review some central linear algebra algorithms that we will need in our
data analysis part and in the construction of Machine Learning algorithms (ML).
This will allow us to introduce some central programming features of high-level languages like Python and
compiled languages like C++ and/or Fortran.
<ul>
<li> add material on python handling of matrices and vectors</li>
<li> keep c++ material?</li>
</ul>
<p>
As discussed in the introductory notes, these series of lectures focuses both on using
central Python packages like <b>tensorflow</b> and <b>scikit-learn</b> as well
as writing your own codes for some central ML algorithms. The
latter can be written in a language of your choice, be it Python, Julia, R,
Rust, C++, Fortran etc. In order to avoid confusion however, in these lectures we will limit our
attention to Python, C++ and Fortran.
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<p>
<!-- !split -->
<h2 id="___sec1">Important Matrix and vector handling packages </h2>
<p>
The Numerical Recipes codes have been rewritten in Fortran 90/95 and
C/C++ by us. The original source codes are taken from the widely used
There are several central software packages for linear algebra and eigenvalue problems. Several of the more
popular ones have been wrapped into ofter software packages like those from the widely used text <b>Numerical Recipes</b>. The original source codes in many of the available packages are often taken from the widely used
software package LAPACK, which follows two other popular packages
developed in the 1970s, namely EISPACK and LINPACK.
developed in the 1970s, namely EISPACK and LINPACK. We describe them shortly here.
<ul>
<li> LINPACK: package for linear equations and least square problems.</li>
@@ -207,10 +199,25 @@ developed in the 1970s, namely EISPACK and LINPACK.
<li> BLAS (I, II and III): (Basic Linear Algebra Subprograms) are routines that provide standard building blocks for performing basic vector and matrix operations. Blas I is vector operations, II vector-matrix operations and III matrix-matrix operations. Highly parallelized and efficient codes, all available for download from <a href="http://www.netlib.org" target="_blank"><tt>http://www.netlib.org</tt></a>.</li>
</ul>
<b>Add python material on linear algebra and array handling, text on numpy etc</b>
When dealing with matrices and vectors a central issue is memory
handling and allocation. If our code is written in Python the way we
declare these objects and the way they are handled, interpreted and
used by say a linear algebra library, requires codes that interface
our Python program with such libraries. For Python programmers,
<b>Numpy</b> is by now the standard Python package for numerical arrays in
Python as well as the source of functions which act on these
arrays. These functions span from eigenvalue solvers to functions that
compute the mean value, variance or the covariance matrix. If you are
not familiar with how arrays are handled in say Python or compiled
languages like C++ and Fortran, the sections in this chapter may be
useful. For C++ programmer, <b>Armadillo</b> is widely used library for
linear algebra and eigenvalue problems. In addition it offers a
convenient way to handle and organize arrays. We discuss this library
as well. Before we proceed we believe it may be convenient to repeat some basic features of
matrices and vectors.
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<!-- !split -->
<h2 id="___sec2">Basic Matrix Features </h2>
@@ -239,6 +246,8 @@ $$
<h2 id="___sec3">Basic Matrix Features </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
<p>
The inverse of a matrix is defined by
@@ -316,7 +325,209 @@ For an \( N\times N \) matrix \( \mathbf{A} \) the following properties are all
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec7">Matrix Handling in C/C++, Static and Dynamical allocation </h2>
<h2 id="___sec7">Numpy and arrays </h2>
<a href="http://www.numpy.org/" target="_blank">Numpy</a> provides an easy way to handle arrays in Python. The standard way to import this library is as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
n = <span style="color: #B452CD">10</span>
x = np.random.normal(size=n)
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
Here we have defined a vector \( x \) with \( n=10 \) elements with its values given by the Normal distribution \( N(0,1) \).
Another alternative is to declare a vector as follows
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
x = np.array([<span style="color: #B452CD">1</span>, <span style="color: #B452CD">2</span>, <span style="color: #B452CD">3</span>])
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
Here we have defined a vector with three elements, with \( x_0=1 \), \( x_1=2 \) and \( x_2=3 \). Note that both Python and C++
start numbering array elements from \( 0 \) and on. This means that a vector with \( n \) elements has a sequence of entities \( x_0, x_1, x_2, \dots, x_{n-1} \). We could also let (recommended) Numpy to compute the logarithms of a specific array as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
x = np.log(np.array([<span style="color: #B452CD">4</span>, <span style="color: #B452CD">7</span>, <span style="color: #B452CD">8</span>]))
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
Here we have used Numpy's unary function \( np.log \). This function is
highly tuned to compute array elements since the code is vectorized
and does not require looping. We normaly recommend that you use the
Numpy intrinsic functions instead of the corresponding <b>log</b> function
from Python's <b>math</b> module. The looping is done explicitely by the
<b>np.log</b> function. The alternative, and slower way to compute the
logarithms of a vector would be to write
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
<span style="color: #8B008B; font-weight: bold">from</span> <span style="color: #008b45; text-decoration: underline">math</span> <span style="color: #8B008B; font-weight: bold">import</span> log
x = np.array([<span style="color: #B452CD">4</span>, <span style="color: #B452CD">7</span>, <span style="color: #B452CD">8</span>])
<span style="color: #8B008B; font-weight: bold">for</span> i <span style="color: #8B008B">in</span> <span style="color: #658b00">range</span>(<span style="color: #B452CD">0</span>, <span style="color: #658b00">len</span>(x)):
x[i] = log(x[i])
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
We note that our code is much longer already and we need to import the <b>log</b> function from the <b>math</b> module.
The attentive reader will also notice that the output is \( [1, 1, 2] \). Python interprets automacally our numbers as integers (like the <b>automatic</b> keyword in C++). To change this we could define our array elements to be double precision numbers as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
x = np.log(np.array([<span style="color: #B452CD">4</span>, <span style="color: #B452CD">7</span>, <span style="color: #B452CD">8</span>], dtype = np.float64))
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
or simply write them as double precision numbers (Python uses 64 bits as default for floating point type variables), that is
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
x = np.log(np.array([<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">7.0</span>, <span style="color: #B452CD">8.0</span>])
<span style="color: #8B008B; font-weight: bold">print</span>(x)
</pre></div>
<p>
To check the number of bytes (remember that one byte contains eight bits for double precision variables), you can use simple use the <b>itemsize</b> functionality (the array \( x \) is actually an object which inherits the functionalities defined in Numpy) as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
x = np.log(np.array([<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">7.0</span>, <span style="color: #B452CD">8.0</span>])
<span style="color: #8B008B; font-weight: bold">print</span>(x.itemsize)
</pre></div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec8">Matrices in Python </h2>
Having defined vectors, we are now ready to try out matrices. We can define a \( 3 \times 3 \) real matrix \( \hat{A} \)
as (recall that we user lowercase letters for vectors and uppercase letters for matrices)
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
A = np.log(np.array([ [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">7.0</span>, <span style="color: #B452CD">8.0</span>], [<span style="color: #B452CD">3.0</span>, <span style="color: #B452CD">10.0</span>, <span style="color: #B452CD">11.0</span>], [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">5.0</span>, <span style="color: #B452CD">7.0</span>] ]))
<span style="color: #8B008B; font-weight: bold">print</span>(A)
</pre></div>
<p>
If we use the <b>shape</b> function we would get \( (3, 3) \) as output, that is verifying that our matrix is a \( 3\times 3 \) matrix. We can slice the matrix and print for example the first column (Python organized matrix elements in a row-major order, see below) as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
A = np.log(np.array([ [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">7.0</span>, <span style="color: #B452CD">8.0</span>], [<span style="color: #B452CD">3.0</span>, <span style="color: #B452CD">10.0</span>, <span style="color: #B452CD">11.0</span>], [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">5.0</span>, <span style="color: #B452CD">7.0</span>] ]))
<span style="color: #228B22"># print the first column, row-major order and elements start with 0</span>
<span style="color: #8B008B; font-weight: bold">print</span>(A[:,<span style="color: #B452CD">0</span>])
</pre></div>
<p>
We can continue this was by printing out other columns or rows. The example here prints out the second column
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
A = np.log(np.array([ [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">7.0</span>, <span style="color: #B452CD">8.0</span>], [<span style="color: #B452CD">3.0</span>, <span style="color: #B452CD">10.0</span>, <span style="color: #B452CD">11.0</span>], [<span style="color: #B452CD">4.0</span>, <span style="color: #B452CD">5.0</span>, <span style="color: #B452CD">7.0</span>] ]))
<span style="color: #228B22"># print the first column, row-major order and elements start with 0</span>
<span style="color: #8B008B; font-weight: bold">print</span>(A[<span style="color: #B452CD">1</span>,:])
</pre></div>
<p>
Numpy contains many other functionalities that allow us to slice, subdivide etc etc arrays. We strongly recommend that you look up the <a href="http://www.numpy.org/" target="_blank">Numpy website for more details</a>. Useful functions when defining a matrix are the <b>np.zeros</b> function which declares a matrix of a given dimension and sets all elements to zero
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
n = <span style="color: #B452CD">10</span>
<span style="color: #228B22"># define a matrix of dimension 10 x 10 and set all elements to zero</span>
A = np.zeros( (n, n) )
<span style="color: #8B008B; font-weight: bold">print</span>(A)
</pre></div>
<p>
or initializing all elements to
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
n = <span style="color: #B452CD">10</span>
<span style="color: #228B22"># define a matrix of dimension 10 x 10 and set all elements to one</span>
A = np.ones( (n, n) )
<span style="color: #8B008B; font-weight: bold">print</span>(A)
</pre></div>
<p>
or as unitarily distributed random numbers (see the material on random number generators in the statistics part)
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
n = <span style="color: #B452CD">10</span>
<span style="color: #228B22"># define a matrix of dimension 10 x 10 and set all elements to random numbers with x \in [0, 1]</span>
A = np.random.rand(n, n)
<span style="color: #8B008B; font-weight: bold">print</span>(A)
</pre></div>
<p>
As we will see throughout these lectures, there are several extremely useful functionalities in Numpy.
As an example, consider the discussion of the covariance matrix. Suppose we have defined three vectors
\( \hat{x}, \hat{y}, \hat{z} \) with \( n \) elements each. The covariance matrix is defined as
$$
\hat{\Sigma} = \begin{bmatrix} \sigma_{xx} & \sigma_{xy} & \sigma_{xz} \\
\sigma_{yx} & \sigma_{yy} & \sigma_{yz} \\
\sigma_{zx} & \sigma_{zy} & \sigma_{zz}
\end{bmatrix},
$$
where for example
$$
\sigma_{xy} =\frac{1}{n} \sum_{i=0}^{n-1}(x_i- \overline{x})(y_i- \overline{y}).
$$
The Numpy function <b>np.cov</b> calculates the covariance elements using the factor \( 1/(n-1) \) instead of \( 1/n \) since it assumes we do not have the exact mean values. For a more in-depth discussion of the covariance and covariance matrix and its meaning, we refer you to the lectures on statistics.
The following simple function uses the <b>np.vstack</b> function which takes each vector of dimension \( 1\times n \) and produces a $ 3\times n$ matrix \( \hat{W} \)
$$
\hat{W} = \begin{bmatrix} x_0 & y_0 & z_0 \\
x_1 & y_1 & z_1 \\
x_2 & y_2 & z_2 \\
\dots & \dots & \dots \\
x_{n-2} & y_{n-2} & z_{n-2} \\
x_{n-1} & y_{n-1} & z_{n-1}
\end{bmatrix},
$$
<p>
which in turn is converted into into the \( 3 times 3 \) covariance matrix
\( \hat{\Sigma} \) via the Numpy function <b>np.cov()</b>. In our review of
statistical functions and quantities we will discuss more about the
meaning of the covariance matrix. Here we note that we can calculate
the mean value of each set of samples \( \hat{x} \) etc using the Numpy
function <b>np.mean(x)</b>. We can also extract the eigenvalues of the
covariance matrix through the <b>np.linalg.eig()</b> function.
<p>
<!-- code=python (!bc pycod) typeset with pygments style "perldoc" -->
<div class="highlight" style="background: #eeeedd"><pre style="line-height: 125%"><span></span><span style="color: #228B22"># Importing various packages</span>
<span style="color: #8B008B; font-weight: bold">import</span> <span style="color: #008b45; text-decoration: underline">numpy</span> <span style="color: #8B008B; font-weight: bold">as</span> <span style="color: #008b45; text-decoration: underline">np</span>
n = <span style="color: #B452CD">100</span>
x = np.random.normal(size=n)
<span style="color: #8B008B; font-weight: bold">print</span>(np.mean(x))
y = <span style="color: #B452CD">4</span>+<span style="color: #B452CD">3</span>*x+np.random.normal(size=n)
<span style="color: #8B008B; font-weight: bold">print</span>(np.mean(y))
z = x**<span style="color: #B452CD">3</span>+np.random.normal(size=n)
<span style="color: #8B008B; font-weight: bold">print</span>(np.mean(z))
W = np.vstack((x, y, z))
Sigma = np.cov(W)
<span style="color: #8B008B; font-weight: bold">print</span>(Sigma)
Eigvals, Eigvecs = np.linalg.eig(Sigma)
<span style="color: #8B008B; font-weight: bold">print</span>(Eigvals)
</pre></div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec9">Matrix Handling in C/C++, Static and Dynamical allocation </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -343,7 +554,7 @@ Note the way the matrix is organized, row-major order.
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec8">Matrix Handling in C/C++ </h2>
<h2 id="___sec10">Matrix Handling in C/C++ </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -372,7 +583,7 @@ In C/C++ this would be coded like
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec9">Matrix Handling in C/C++ </h2>
<h2 id="___sec11">Matrix Handling in C/C++ </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -402,7 +613,7 @@ In C/C++ this would be coded like
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec10">Dynamic memory allocation in C/C++ </h2>
<h2 id="___sec12">Dynamic memory allocation in C/C++ </h2>
<p>
At least three possibilities in this course
@@ -415,7 +626,7 @@ At least three possibilities in this course
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec11">Matrix Handling in C/C++, Dynamic Allocation </h2>
<h2 id="___sec13">Matrix Handling in C/C++, Dynamic Allocation </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -447,7 +658,7 @@ Always free space when you don't need an array anymore.
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec12">Armadillo, recommended!! </h2>
<h2 id="___sec14">Armadillo, recommended!! </h2>
<ul>
<li> Armadillo is a C++ linear algebra library (matrix maths) aiming towards a good balance between speed and ease of use. The syntax is deliberately similar to Matlab.</li>
@@ -459,7 +670,7 @@ Always free space when you don't need an array anymore.
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec13">Armadillo, simple examples </h2>
<h2 id="___sec15">Armadillo, simple examples </h2>
<p>
@@ -482,7 +693,7 @@ Always free space when you don't need an array anymore.
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec14">Armadillo, how to compile and install </h2>
<h2 id="___sec16">Armadillo, how to compile and install </h2>
<p>
For people using Ubuntu, Debian, Linux Mint, simply go to the synaptic package manager and install
@@ -510,7 +721,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec15">Armadillo, simple examples </h2>
<h2 id="___sec17">Armadillo, simple examples </h2>
<p>
@@ -543,7 +754,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec16">Armadillo, simple examples </h2>
<h2 id="___sec18">Armadillo, simple examples </h2>
<p>
@@ -574,7 +785,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec17">Armadillo, simple examples </h2>
<h2 id="___sec19">Armadillo, simple examples </h2>
<p>
@@ -607,7 +818,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
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<h2 id="___sec18">Armadillo, simple examples </h2>
<h2 id="___sec20">Armadillo, simple examples </h2>
<p>
@@ -635,7 +846,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
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<h2 id="___sec19">Armadillo, simple examples </h2>
<h2 id="___sec21">Armadillo, simple examples </h2>
<p>
@@ -667,7 +878,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
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<h2 id="___sec20">Armadillo, simple examples </h2>
<h2 id="___sec22">Armadillo, simple examples </h2>
<p>
@@ -697,7 +908,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
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<h2 id="___sec21">Armadillo, simple examples </h2>
<h2 id="___sec23">Armadillo, simple examples </h2>
<p>
@@ -729,7 +940,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
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<h2 id="___sec22">Gaussian Elimination </h2>
<h2 id="___sec24">Gaussian Elimination </h2>
<p>
We start with the linear set of equations
@@ -764,7 +975,7 @@ $$
<p>
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<h2 id="___sec23">Gaussian Elimination </h2>
<h2 id="___sec25">Gaussian Elimination </h2>
or
$$
@@ -779,7 +990,7 @@ $$
<p>
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<h2 id="___sec24">Gaussian Elimination </h2>
<h2 id="___sec26">Gaussian Elimination </h2>
<p>
The basic idea of Gaussian elimination is to use the first equation to eliminate the first unknown \( x_1 \)
@@ -803,7 +1014,7 @@ what is called a backward substitution.
<p>
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<h2 id="___sec25">Gaussian Elimination </h2>
<h2 id="___sec27">Gaussian Elimination </h2>
This process can be expressed mathematically as
$$
@@ -821,7 +1032,7 @@ the result from the $j$th equation. We assume obviously that \( a_{11}\ne 0 \) a
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec26">Gaussian Elimination </h2>
<h2 id="___sec28">Gaussian Elimination </h2>
<p>
Our actual \( 4\times 4 \) example reads after the first operation
@@ -861,7 +1072,7 @@ $$
<p>
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<h2 id="___sec27">Gaussian Elimination </h2>
<h2 id="___sec29">Gaussian Elimination </h2>
<p>
The new coefficients are
@@ -897,7 +1108,7 @@ We see that the system of unknowns \( x_1,\dots,x_n \) is transformed into an \(
<p>
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<h2 id="___sec28">Gaussian Elimination </h2>
<h2 id="___sec30">Gaussian Elimination </h2>
<p>
This step is called forward substitution.
@@ -935,7 +1146,7 @@ adding \( 10^7+1 \). With single precision this results in \( 10^7 \).
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec29">Linear Algebra Methods </h2>
<h2 id="___sec31">Linear Algebra Methods </h2>
<ul>
<li> Gaussian elimination, \( O(2/3n^3) \) flops, general matrix</li>
@@ -948,7 +1159,7 @@ adding \( 10^7+1 \). With single precision this results in \( 10^7 \).
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<h2 id="___sec30">LU Decomposition </h2>
<h2 id="___sec32">LU Decomposition </h2>
<p>
The LU decomposition method means that we can rewrite
@@ -979,7 +1190,7 @@ $$
<p>
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<h2 id="___sec31">LU Decomposition </h2>
<h2 id="___sec33">LU Decomposition </h2>
<p>
LU decomposition forms the backbone of other algorithms in linear algebra, such as the
@@ -1008,7 +1219,7 @@ $$
<p>
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<h2 id="___sec32">LU Decomposition, why? </h2>
<h2 id="___sec34">LU Decomposition, why? </h2>
<p>
There are at least three main advantages with LU decomposition compared with standard Gaussian elimination:
@@ -1021,7 +1232,7 @@ There are at least three main advantages with LU decomposition compared with sta
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<h2 id="___sec33">LU Decomposition, linear equations </h2>
<h2 id="___sec35">LU Decomposition, linear equations </h2>
<p>
With the LU decomposition it is rather
@@ -1050,7 +1261,7 @@ $$ \mathbf{A} \mathbf{x} \equiv \mathbf{L} \mathbf{U} \mathbf{x} =\mathbf{w}. $$
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec34">LU Decomposition, linear equations </h2>
<h2 id="___sec36">LU Decomposition, linear equations </h2>
<p>
The previous equation can be calculated in two steps
@@ -1063,7 +1274,7 @@ to rewrite our system of linear equations as
$$ \mathbf{LUx}=\mathbf{w}, $$
and since the determinat of \( \mathbf{L} \) is equal to 1 (by construction
and since the determinant of \( \mathbf{L} \) is equal to 1 (by construction
since the diagonals of \( \mathbf{L} \) equal 1) we can use the inverse of
\( \mathbf{L} \) to obtain
@@ -1083,7 +1294,7 @@ through \( \mathbf{Ux}=\mathbf{y} \).
<p>
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<h2 id="___sec35">LU Decomposition, why? </h2>
<h2 id="___sec37">LU Decomposition, why? </h2>
<p>
For our four-dimentional example this takes the form
@@ -1116,7 +1327,7 @@ needed to solve the set of \( n \) linear equations.
<p>
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<h2 id="___sec36">LU Decomposition, linear equations </h2>
<h2 id="___sec38">LU Decomposition, linear equations </h2>
<p>
The algorithm goes as follows
@@ -1129,7 +1340,7 @@ The algorithm goes as follows
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<h2 id="___sec37">LU Decomposition, the inverse of a matrix </h2>
<h2 id="___sec39">LU Decomposition, the inverse of a matrix </h2>
<p>
If the inverse exists then
@@ -1147,7 +1358,7 @@ $$
<p>
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<h2 id="___sec38">LU Decomposition, the inverse of a matrix </h2>
<h2 id="___sec40">LU Decomposition, the inverse of a matrix </h2>
<p>
If we assume that the first column (that is column 1) of the inverse matrix
@@ -1181,7 +1392,7 @@ $$
<p>
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<h2 id="___sec39">LU Decomposition, the inverse </h2>
<h2 id="___sec41">LU Decomposition, the inverse </h2>
<p>
In a similar way we can compute the unknow entries of the second column,
@@ -1205,7 +1416,7 @@ and continue till we have solved all \( n \) sets of linear equations.
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec40"><a href="https://github.com/CompPhysics/ComputationalPhysicsMSU/blob/master/doc/Programs/CppQtCodesLectures/MatrixTest/main.cpp" target="_blank">Using Armadillo to perform an LU decomposition</a> </h2>
<h2 id="___sec42"><a href="https://github.com/CompPhysics/ComputationalPhysicsMSU/blob/master/doc/Programs/CppQtCodesLectures/MatrixTest/main.cpp" target="_blank">Using Armadillo to perform an LU decomposition</a> </h2>
<p>
<!-- code=c++ (!bc cppcod) typeset with pygments style "perldoc" -->
@@ -1237,236 +1448,6 @@ and continue till we have solved all \( n \) sets of linear equations.
<span style="color: #8B008B; font-weight: bold">return</span> <span style="color: #B452CD">0</span>;
}
</pre></div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec41">Iterative methods, Chapter 6 </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
<ul>
<li> Direct solvers such as Gauss elimination and LU decomposition discussed in connection with project 1.</li>
<li> Iterative solvers such as Basic iterative solvers, Jacobi, Gauss-Seidel, Successive over-relaxation. These methods are easy to parallelize, as we will se later. Much used in solutions of partial differential equations.</li>
<li> Other iterative methods such as Krylov subspace methods with Generalized minimum residual (GMRES) and Conjugate gradient etc will not be discussed.</li>
</ul>
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec42">Iterative methods, Jacobi's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
It is a simple method for solving
$$
\mathbf{A}\mathbf{x}=\mathbf{b},
$$
where \( \mathbf{A} \) is a matrix and \( \mathbf{x} \) and \( \mathbf{b} \) are vectors. The vector \( \mathbf{x} \) is
the unknown.
<p>
It is an iterative scheme where we start with a guess for the unknown, and
after \( k+1 \) iterations we have
$$
\mathbf{x}^{(k+1)}= \mathbf{D}^{-1}(\mathbf{b}-(\mathbf{L}+\mathbf{U})\mathbf{x}^{(k)}),
$$
with \( \mathbf{A}=\mathbf{D}+\mathbf{U}+\mathbf{L} \) and
\( \mathbf{D} \) being a diagonal matrix, \( \mathbf{U} \) an upper triangular matrix and \( \mathbf{L} \) a lower triangular
matrix.
<p>
If the matrix \( \mathbf{A} \) is positive definite or diagonally dominant, one can show that this method will always converge to the exact solution.
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec43">Iterative methods, Jacobi's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
We can demonstrate Jacobi's method by this \( 4\times 4 \) matrix problem. We assume a guess
for the vector elements \( x_i^{(0)} \), a guess which represents our first iteration. The new
values are obtained by substitution
$$
\begin{align}
x_1^{(1)} =&(b_1-a_{12}x_2^{(0)} -a_{13}x_3^{(0)} - a_{14}x_4^{(0)})/a_{11} \nonumber \\
x_2^{(1)} =&(b_2-a_{21}x_1^{(0)} - a_{23}x_3^{(0)} - a_{24}x_4^{(0)})/a_{22} \nonumber \\
x_3^{(1)} =&(b_3- a_{31}x_1^{(0)} -a_{32}x_2^{(0)} -a_{34}x_4^{(0)})/a_{33} \nonumber \\
x_4^{(1)}=&(b_4-a_{41}x_1^{(0)} -a_{42}x_2^{(0)} - a_{43}x_3^{(0)})/a_{44}, \nonumber
\end{align}
$$
which after \( k+1 \) iterations reads
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k)} -a_{32}x_2^{(k)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k)} -a_{42}x_2^{(k)} - a_{43}x_3^{(k)})/a_{44}, \nonumber
\end{align}
$$
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec44">Iterative methods, Jacobi's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
We can generalize the above equations to
$$
x_i^{(k+1)}=(b_i-\sum_{j=1, j\ne i}^{n}a_{ij}x_j^{(k)})/a_{ii}
$$
or in an even more compact form as
$$ \mathbf{x}^{(k+1)}= \mathbf{D}^{-1}(\mathbf{b}-(\mathbf{L}+\mathbf{U})\mathbf{x}^{(k)}),
$$
with \( \mathbf{A}=\mathbf{D}+\mathbf{U}+\mathbf{L} \) and
\( \mathbf{D} \) being a diagonal matrix, \( \mathbf{U} \) an upper triangular matrix and \( \mathbf{L} \) a lower triangular
matrix.
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec45">Iterative methods, Gauss-Seidel's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
Our \( 4\times 4 \) matrix problem
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k)} -a_{32}x_2^{(k)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k)} -a_{42}x_2^{(k)} - a_{43}x_3^{(k)})/a_{44}, \nonumber
\end{align}
$$
can be rewritten as
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k+1)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k+1)} -a_{32}x_2^{(k+1)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k+1)} -a_{42}x_2^{(k+1)} - a_{43}x_3^{(k+1)})/a_{44}, \nonumber
\end{align}
$$
which allows us to utilize the preceding solution (forward substitution). This improves normally the convergence
behavior and leads to the Gauss-Seidel method!
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec46">Iterative methods, Gauss-Seidel's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
We can generalize
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k+1)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k+1)} -a_{32}x_2^{(k+1)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k+1)} -a_{42}x_2^{(k+1)} - a_{43}x_3^{(k+1)})/a_{44}, \nonumber
\end{align}
$$
to the following form
$$
x^{(k+1)}_i = \frac{1}{a_{ii}} \left(b_i - \sum_{j > i}a_{ij}x^{(k)}_j - \sum_{j < i}a_{ij}x^{(k+1)}_j \right),\quad i=1,2,\ldots,n.
$$
The procedure is generally continued until the changes made by an iteration are below some tolerance.
<p>
The convergence properties of the Jacobi method and the
Gauss-Seidel method are dependent on the matrix \( \mathbf{A} \). These methods converge when
the matrix is symmetric positive-definite, or is strictly or irreducibly diagonally dominant.
Both methods sometimes converge even if these conditions are not satisfied.
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec47">Iterative methods, Successive over-relaxation </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
Given a square system of n linear equations with unknown \( \mathbf x \):
$$
\mathbf{A}\mathbf x = \mathbf b
$$
where
$$
\mathbf{A}=\begin{bmatrix} a_{11} & a_{12} & \cdots & a_{1n} \\ a_{21} & a_{22} & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\a_{n1} & a_{n2} & \cdots & a_{nn} \end{bmatrix}, \qquad \mathbf{x} = \begin{bmatrix} x_{1} \\ x_2 \\ \vdots \\ x_n \end{bmatrix} , \qquad \mathbf{b} = \begin{bmatrix} b_{1} \\ b_2 \\ \vdots \\ b_n \end{bmatrix}.
$$
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec48">Iterative methods, Successive over-relaxation </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
Then A can be decomposed into a diagonal component D, and strictly lower and upper triangular components L and U:
$$
\mathbf{A} =\mathbf{D} + \mathbf{L} + \mathbf{U},
$$
where
$$
D = \begin{bmatrix} a_{11} & 0 & \cdots & 0 \\ 0 & a_{22} & \cdots & 0 \\ \vdots & \vdots & \ddots & \vdots \\0 & 0 & \cdots & a_{nn} \end{bmatrix}, \quad L = \begin{bmatrix} 0 & 0 & \cdots & 0 \\ a_{21} & 0 & \cdots & 0 \\ \vdots & \vdots & \ddots & \vdots \\a_{n1} & a_{n2} & \cdots & 0 \end{bmatrix}, \quad U = \begin{bmatrix} 0 & a_{12} & \cdots & a_{1n} \\ 0 & 0 & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\0 & 0 & \cdots & 0 \end{bmatrix}.
$$
The system of linear equations may be rewritten as:
$$
(D+\omega L) \mathbf{x} = \omega \mathbf{b} - [\omega U + (\omega-1) D ] \mathbf{x}
$$
for a constant \( \omega > 1 \).
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec49">Iterative methods, Successive over-relaxation </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
The method of successive over-relaxation is an iterative technique that solves the left hand side of this expression for \( x \), using previous value for \( x \) on the right hand side. Analytically, this may be written as:
$$
\mathbf{x}^{(k+1)} = (D+\omega L)^{-1} \big(\omega \mathbf{b} - [\omega U + (\omega-1) D ] \mathbf{x}^{(k)}\big).
$$
However, by taking advantage of the triangular form of \( (D+\omega L) \), the elements of \( x^{(k+1)} \) can be computed sequentially using forward substitution:
$$
x^{(k+1)}_i = (1-\omega)x^{(k)}_i + \frac{\omega}{a_{ii}} \left(b_i - \sum_{j > i} a_{ij}x^{(k)}_j - \sum_{j < i} a_{ij}x^{(k+1)}_j \right),\quad i=1,2,\ldots,n.
$$
The choice of relaxation factor is not necessarily easy, and depends upon the properties of the coefficient matrix. For symmetric, positive-definite matrices it can be proven that \( 0 < \omega < 2 \) will lead to convergence, but we are generally interested in faster convergence rather than just convergence.
</div>
<p>
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('LU Decomposition, the inverse', 2, None, '___sec41'),
('"Using Armadillo to perform an LU '
'decomposition":"https://github.com/CompPhysics/ComputationalPhysicsMSU/blob/master/doc/Programs/CppQtCodesLectures/MatrixTest/main.cpp"',
2,
None,
'___sec40'),
('Iterative methods, Chapter 6', 2, None, '___sec41'),
("Iterative methods, Jacobi's method", 2, None, '___sec42'),
("Iterative methods, Jacobi's method", 2, None, '___sec43'),
("Iterative methods, Jacobi's method", 2, None, '___sec44'),
("Iterative methods, Gauss-Seidel's method", 2, None, '___sec45'),
("Iterative methods, Gauss-Seidel's method", 2, None, '___sec46'),
('Iterative methods, Successive over-relaxation',
2,
None,
'___sec47'),
('Iterative methods, Successive over-relaxation',
2,
None,
'___sec48'),
('Iterative methods, Successive over-relaxation',
2,
None,
'___sec49')]}
'___sec42')]}
end of tocinfo -->
<body>
@@ -168,7 +152,7 @@ MathJax.Hub.Config({
<center><h1>Data analysis and Machine Learning Lectures: Linear Algebra methods </h1></center> <!-- document title -->
<center><h1>Data analysis and Machine Learning Lectures: Linear Algebra and Handling of Arrays</h1></center> <!-- document title -->
<p>
<!-- author(s): Morten Hjorth-Jensen -->
@@ -184,27 +168,35 @@ MathJax.Hub.Config({
<center>[2] <b>Department of Physics and Astronomy and National Superconducting Cyclotron Laboratory, Michigan State University</b></center>
<br>
<p>
<center><h4>May 22, 2018</h4></center> <!-- date -->
<center><h4>May 24, 2018</h4></center> <!-- date -->
<br>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec0">To do </h2>
<h2 id="___sec0">Introduction </h2>
The aim of this set of lectures is to review some central linear algebra algorithms that we will need in our
data analysis part and in the construction of Machine Learning algorithms (ML).
This will allow us to introduce some central programming features of high-level languages like Python and
compiled languages like C++ and/or Fortran.
<ul>
<li> add material on python handling of matrices and vectors</li>
<li> keep c++ material?</li>
</ul>
<p>
As discussed in the introductory notes, these series of lectures focuses both on using
central Python packages like <b>tensorflow</b> and <b>scikit-learn</b> as well
as writing your own codes for some central ML algorithms. The
latter can be written in a language of your choice, be it Python, Julia, R,
Rust, C++, Fortran etc. In order to avoid confusion however, in these lectures we will limit our
attention to Python, C++ and Fortran.
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<p>
<!-- !split -->
<h2 id="___sec1">Important Matrix and vector handling packages </h2>
<p>
The Numerical Recipes codes have been rewritten in Fortran 90/95 and
C/C++ by us. The original source codes are taken from the widely used
There are several central software packages for linear algebra and eigenvalue problems. Several of the more
popular ones have been wrapped into ofter software packages like those from the widely used text <b>Numerical Recipes</b>. The original source codes in many of the available packages are often taken from the widely used
software package LAPACK, which follows two other popular packages
developed in the 1970s, namely EISPACK and LINPACK.
developed in the 1970s, namely EISPACK and LINPACK. We describe them shortly here.
<ul>
<li> LINPACK: package for linear equations and least square problems.</li>
@@ -212,10 +204,25 @@ developed in the 1970s, namely EISPACK and LINPACK.
<li> BLAS (I, II and III): (Basic Linear Algebra Subprograms) are routines that provide standard building blocks for performing basic vector and matrix operations. Blas I is vector operations, II vector-matrix operations and III matrix-matrix operations. Highly parallelized and efficient codes, all available for download from <a href="http://www.netlib.org" target="_blank"><tt>http://www.netlib.org</tt></a>.</li>
</ul>
<b>Add python material on linear algebra and array handling, text on numpy etc</b>
When dealing with matrices and vectors a central issue is memory
handling and allocation. If our code is written in Python the way we
declare these objects and the way they are handled, interpreted and
used by say a linear algebra library, requires codes that interface
our Python program with such libraries. For Python programmers,
<b>Numpy</b> is by now the standard Python package for numerical arrays in
Python as well as the source of functions which act on these
arrays. These functions span from eigenvalue solvers to functions that
compute the mean value, variance or the covariance matrix. If you are
not familiar with how arrays are handled in say Python or compiled
languages like C++ and Fortran, the sections in this chapter may be
useful. For C++ programmer, <b>Armadillo</b> is widely used library for
linear algebra and eigenvalue problems. In addition it offers a
convenient way to handle and organize arrays. We discuss this library
as well. Before we proceed we believe it may be convenient to repeat some basic features of
matrices and vectors.
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<!-- !split -->
<h2 id="___sec2">Basic Matrix Features </h2>
@@ -244,6 +251,8 @@ $$
<h2 id="___sec3">Basic Matrix Features </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
<p>
The inverse of a matrix is defined by
@@ -321,7 +330,209 @@ For an \( N\times N \) matrix \( \mathbf{A} \) the following properties are all
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec7">Matrix Handling in C/C++, Static and Dynamical allocation </h2>
<h2 id="___sec7">Numpy and arrays </h2>
<a href="http://www.numpy.org/" target="_blank">Numpy</a> provides an easy way to handle arrays in Python. The standard way to import this library is as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
n <span style="color: #666666">=</span> <span style="color: #666666">10</span>
x <span style="color: #666666">=</span> np<span style="color: #666666">.</span>random<span style="color: #666666">.</span>normal(size<span style="color: #666666">=</span>n)
<span style="color: #008000; font-weight: bold">print</span>(x)
</pre></div>
<p>
Here we have defined a vector \( x \) with \( n=10 \) elements with its values given by the Normal distribution \( N(0,1) \).
Another alternative is to declare a vector as follows
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
x <span style="color: #666666">=</span> np<span style="color: #666666">.</span>array([<span style="color: #666666">1</span>, <span style="color: #666666">2</span>, <span style="color: #666666">3</span>])
<span style="color: #008000; font-weight: bold">print</span>(x)
</pre></div>
<p>
Here we have defined a vector with three elements, with \( x_0=1 \), \( x_1=2 \) and \( x_2=3 \). Note that both Python and C++
start numbering array elements from \( 0 \) and on. This means that a vector with \( n \) elements has a sequence of entities \( x_0, x_1, x_2, \dots, x_{n-1} \). We could also let (recommended) Numpy to compute the logarithms of a specific array as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
x <span style="color: #666666">=</span> np<span style="color: #666666">.</span>log(np<span style="color: #666666">.</span>array([<span style="color: #666666">4</span>, <span style="color: #666666">7</span>, <span style="color: #666666">8</span>]))
<span style="color: #008000; font-weight: bold">print</span>(x)
</pre></div>
<p>
Here we have used Numpy's unary function \( np.log \). This function is
highly tuned to compute array elements since the code is vectorized
and does not require looping. We normaly recommend that you use the
Numpy intrinsic functions instead of the corresponding <b>log</b> function
from Python's <b>math</b> module. The looping is done explicitely by the
<b>np.log</b> function. The alternative, and slower way to compute the
logarithms of a vector would be to write
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
<span style="color: #008000; font-weight: bold">from</span> <span style="color: #0000FF; font-weight: bold">math</span> <span style="color: #008000; font-weight: bold">import</span> log
x <span style="color: #666666">=</span> np<span style="color: #666666">.</span>array([<span style="color: #666666">4</span>, <span style="color: #666666">7</span>, <span style="color: #666666">8</span>])
<span style="color: #008000; font-weight: bold">for</span> i <span style="color: #AA22FF; font-weight: bold">in</span> <span style="color: #008000">range</span>(<span style="color: #666666">0</span>, <span style="color: #008000">len</span>(x)):
x[i] <span style="color: #666666">=</span> log(x[i])
<span style="color: #008000; font-weight: bold">print</span>(x)
</pre></div>
<p>
We note that our code is much longer already and we need to import the <b>log</b> function from the <b>math</b> module.
The attentive reader will also notice that the output is \( [1, 1, 2] \). Python interprets automacally our numbers as integers (like the <b>automatic</b> keyword in C++). To change this we could define our array elements to be double precision numbers as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
x <span style="color: #666666">=</span> np<span style="color: #666666">.</span>log(np<span style="color: #666666">.</span>array([<span style="color: #666666">4</span>, <span style="color: #666666">7</span>, <span style="color: #666666">8</span>], dtype <span style="color: #666666">=</span> np<span style="color: #666666">.</span>float64))
<span style="color: #008000; font-weight: bold">print</span>(x)
</pre></div>
<p>
or simply write them as double precision numbers (Python uses 64 bits as default for floating point type variables), that is
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
x <span style="color: #666666">=</span> np<span style="color: #666666">.</span>log(np<span style="color: #666666">.</span>array([<span style="color: #666666">4.0</span>, <span style="color: #666666">7.0</span>, <span style="color: #666666">8.0</span>])
<span style="color: #008000; font-weight: bold">print</span>(x)
</pre></div>
<p>
To check the number of bytes (remember that one byte contains eight bits for double precision variables), you can use simple use the <b>itemsize</b> functionality (the array \( x \) is actually an object which inherits the functionalities defined in Numpy) as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
x <span style="color: #666666">=</span> np<span style="color: #666666">.</span>log(np<span style="color: #666666">.</span>array([<span style="color: #666666">4.0</span>, <span style="color: #666666">7.0</span>, <span style="color: #666666">8.0</span>])
<span style="color: #008000; font-weight: bold">print</span>(x<span style="color: #666666">.</span>itemsize)
</pre></div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec8">Matrices in Python </h2>
Having defined vectors, we are now ready to try out matrices. We can define a \( 3 \times 3 \) real matrix \( \hat{A} \)
as (recall that we user lowercase letters for vectors and uppercase letters for matrices)
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
A <span style="color: #666666">=</span> np<span style="color: #666666">.</span>log(np<span style="color: #666666">.</span>array([ [<span style="color: #666666">4.0</span>, <span style="color: #666666">7.0</span>, <span style="color: #666666">8.0</span>], [<span style="color: #666666">3.0</span>, <span style="color: #666666">10.0</span>, <span style="color: #666666">11.0</span>], [<span style="color: #666666">4.0</span>, <span style="color: #666666">5.0</span>, <span style="color: #666666">7.0</span>] ]))
<span style="color: #008000; font-weight: bold">print</span>(A)
</pre></div>
<p>
If we use the <b>shape</b> function we would get \( (3, 3) \) as output, that is verifying that our matrix is a \( 3\times 3 \) matrix. We can slice the matrix and print for example the first column (Python organized matrix elements in a row-major order, see below) as
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
A <span style="color: #666666">=</span> np<span style="color: #666666">.</span>log(np<span style="color: #666666">.</span>array([ [<span style="color: #666666">4.0</span>, <span style="color: #666666">7.0</span>, <span style="color: #666666">8.0</span>], [<span style="color: #666666">3.0</span>, <span style="color: #666666">10.0</span>, <span style="color: #666666">11.0</span>], [<span style="color: #666666">4.0</span>, <span style="color: #666666">5.0</span>, <span style="color: #666666">7.0</span>] ]))
<span style="color: #408080; font-style: italic"># print the first column, row-major order and elements start with 0</span>
<span style="color: #008000; font-weight: bold">print</span>(A[:,<span style="color: #666666">0</span>])
</pre></div>
<p>
We can continue this was by printing out other columns or rows. The example here prints out the second column
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
A <span style="color: #666666">=</span> np<span style="color: #666666">.</span>log(np<span style="color: #666666">.</span>array([ [<span style="color: #666666">4.0</span>, <span style="color: #666666">7.0</span>, <span style="color: #666666">8.0</span>], [<span style="color: #666666">3.0</span>, <span style="color: #666666">10.0</span>, <span style="color: #666666">11.0</span>], [<span style="color: #666666">4.0</span>, <span style="color: #666666">5.0</span>, <span style="color: #666666">7.0</span>] ]))
<span style="color: #408080; font-style: italic"># print the first column, row-major order and elements start with 0</span>
<span style="color: #008000; font-weight: bold">print</span>(A[<span style="color: #666666">1</span>,:])
</pre></div>
<p>
Numpy contains many other functionalities that allow us to slice, subdivide etc etc arrays. We strongly recommend that you look up the <a href="http://www.numpy.org/" target="_blank">Numpy website for more details</a>. Useful functions when defining a matrix are the <b>np.zeros</b> function which declares a matrix of a given dimension and sets all elements to zero
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
n <span style="color: #666666">=</span> <span style="color: #666666">10</span>
<span style="color: #408080; font-style: italic"># define a matrix of dimension 10 x 10 and set all elements to zero</span>
A <span style="color: #666666">=</span> np<span style="color: #666666">.</span>zeros( (n, n) )
<span style="color: #008000; font-weight: bold">print</span>(A)
</pre></div>
<p>
or initializing all elements to
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
n <span style="color: #666666">=</span> <span style="color: #666666">10</span>
<span style="color: #408080; font-style: italic"># define a matrix of dimension 10 x 10 and set all elements to one</span>
A <span style="color: #666666">=</span> np<span style="color: #666666">.</span>ones( (n, n) )
<span style="color: #008000; font-weight: bold">print</span>(A)
</pre></div>
<p>
or as unitarily distributed random numbers (see the material on random number generators in the statistics part)
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
n <span style="color: #666666">=</span> <span style="color: #666666">10</span>
<span style="color: #408080; font-style: italic"># define a matrix of dimension 10 x 10 and set all elements to random numbers with x \in [0, 1]</span>
A <span style="color: #666666">=</span> np<span style="color: #666666">.</span>random<span style="color: #666666">.</span>rand(n, n)
<span style="color: #008000; font-weight: bold">print</span>(A)
</pre></div>
<p>
As we will see throughout these lectures, there are several extremely useful functionalities in Numpy.
As an example, consider the discussion of the covariance matrix. Suppose we have defined three vectors
\( \hat{x}, \hat{y}, \hat{z} \) with \( n \) elements each. The covariance matrix is defined as
$$
\hat{\Sigma} = \begin{bmatrix} \sigma_{xx} & \sigma_{xy} & \sigma_{xz} \\
\sigma_{yx} & \sigma_{yy} & \sigma_{yz} \\
\sigma_{zx} & \sigma_{zy} & \sigma_{zz}
\end{bmatrix},
$$
where for example
$$
\sigma_{xy} =\frac{1}{n} \sum_{i=0}^{n-1}(x_i- \overline{x})(y_i- \overline{y}).
$$
The Numpy function <b>np.cov</b> calculates the covariance elements using the factor \( 1/(n-1) \) instead of \( 1/n \) since it assumes we do not have the exact mean values. For a more in-depth discussion of the covariance and covariance matrix and its meaning, we refer you to the lectures on statistics.
The following simple function uses the <b>np.vstack</b> function which takes each vector of dimension \( 1\times n \) and produces a $ 3\times n$ matrix \( \hat{W} \)
$$
\hat{W} = \begin{bmatrix} x_0 & y_0 & z_0 \\
x_1 & y_1 & z_1 \\
x_2 & y_2 & z_2 \\
\dots & \dots & \dots \\
x_{n-2} & y_{n-2} & z_{n-2} \\
x_{n-1} & y_{n-1} & z_{n-1}
\end{bmatrix},
$$
<p>
which in turn is converted into into the \( 3 times 3 \) covariance matrix
\( \hat{\Sigma} \) via the Numpy function <b>np.cov()</b>. In our review of
statistical functions and quantities we will discuss more about the
meaning of the covariance matrix. Here we note that we can calculate
the mean value of each set of samples \( \hat{x} \) etc using the Numpy
function <b>np.mean(x)</b>. We can also extract the eigenvalues of the
covariance matrix through the <b>np.linalg.eig()</b> function.
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #408080; font-style: italic"># Importing various packages</span>
<span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
n <span style="color: #666666">=</span> <span style="color: #666666">100</span>
x <span style="color: #666666">=</span> np<span style="color: #666666">.</span>random<span style="color: #666666">.</span>normal(size<span style="color: #666666">=</span>n)
<span style="color: #008000; font-weight: bold">print</span>(np<span style="color: #666666">.</span>mean(x))
y <span style="color: #666666">=</span> <span style="color: #666666">4+3*</span>x<span style="color: #666666">+</span>np<span style="color: #666666">.</span>random<span style="color: #666666">.</span>normal(size<span style="color: #666666">=</span>n)
<span style="color: #008000; font-weight: bold">print</span>(np<span style="color: #666666">.</span>mean(y))
z <span style="color: #666666">=</span> x<span style="color: #666666">**3+</span>np<span style="color: #666666">.</span>random<span style="color: #666666">.</span>normal(size<span style="color: #666666">=</span>n)
<span style="color: #008000; font-weight: bold">print</span>(np<span style="color: #666666">.</span>mean(z))
W <span style="color: #666666">=</span> np<span style="color: #666666">.</span>vstack((x, y, z))
Sigma <span style="color: #666666">=</span> np<span style="color: #666666">.</span>cov(W)
<span style="color: #008000; font-weight: bold">print</span>(Sigma)
Eigvals, Eigvecs <span style="color: #666666">=</span> np<span style="color: #666666">.</span>linalg<span style="color: #666666">.</span>eig(Sigma)
<span style="color: #008000; font-weight: bold">print</span>(Eigvals)
</pre></div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec9">Matrix Handling in C/C++, Static and Dynamical allocation </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -348,7 +559,7 @@ Note the way the matrix is organized, row-major order.
<p>
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<h2 id="___sec8">Matrix Handling in C/C++ </h2>
<h2 id="___sec10">Matrix Handling in C/C++ </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -377,7 +588,7 @@ In C/C++ this would be coded like
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec9">Matrix Handling in C/C++ </h2>
<h2 id="___sec11">Matrix Handling in C/C++ </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -407,7 +618,7 @@ In C/C++ this would be coded like
<p>
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<h2 id="___sec10">Dynamic memory allocation in C/C++ </h2>
<h2 id="___sec12">Dynamic memory allocation in C/C++ </h2>
<p>
At least three possibilities in this course
@@ -420,7 +631,7 @@ At least three possibilities in this course
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec11">Matrix Handling in C/C++, Dynamic Allocation </h2>
<h2 id="___sec13">Matrix Handling in C/C++, Dynamic Allocation </h2>
<p>
<div class="alert alert-block alert-block alert-text-normal">
@@ -452,7 +663,7 @@ Always free space when you don't need an array anymore.
<p>
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<h2 id="___sec12">Armadillo, recommended!! </h2>
<h2 id="___sec14">Armadillo, recommended!! </h2>
<ul>
<li> Armadillo is a C++ linear algebra library (matrix maths) aiming towards a good balance between speed and ease of use. The syntax is deliberately similar to Matlab.</li>
@@ -464,7 +675,7 @@ Always free space when you don't need an array anymore.
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec13">Armadillo, simple examples </h2>
<h2 id="___sec15">Armadillo, simple examples </h2>
<p>
@@ -487,7 +698,7 @@ Always free space when you don't need an array anymore.
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec14">Armadillo, how to compile and install </h2>
<h2 id="___sec16">Armadillo, how to compile and install </h2>
<p>
For people using Ubuntu, Debian, Linux Mint, simply go to the synaptic package manager and install
@@ -515,7 +726,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
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<h2 id="___sec15">Armadillo, simple examples </h2>
<h2 id="___sec17">Armadillo, simple examples </h2>
<p>
@@ -548,7 +759,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
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<h2 id="___sec16">Armadillo, simple examples </h2>
<h2 id="___sec18">Armadillo, simple examples </h2>
<p>
@@ -579,7 +790,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
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<h2 id="___sec17">Armadillo, simple examples </h2>
<h2 id="___sec19">Armadillo, simple examples </h2>
<p>
@@ -612,7 +823,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec18">Armadillo, simple examples </h2>
<h2 id="___sec20">Armadillo, simple examples </h2>
<p>
@@ -640,7 +851,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec19">Armadillo, simple examples </h2>
<h2 id="___sec21">Armadillo, simple examples </h2>
<p>
@@ -672,7 +883,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec20">Armadillo, simple examples </h2>
<h2 id="___sec22">Armadillo, simple examples </h2>
<p>
@@ -702,7 +913,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec21">Armadillo, simple examples </h2>
<h2 id="___sec23">Armadillo, simple examples </h2>
<p>
@@ -734,7 +945,7 @@ For OS X users you may have to declare the paths to the include files and the li
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec22">Gaussian Elimination </h2>
<h2 id="___sec24">Gaussian Elimination </h2>
<p>
We start with the linear set of equations
@@ -769,7 +980,7 @@ $$
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec23">Gaussian Elimination </h2>
<h2 id="___sec25">Gaussian Elimination </h2>
or
$$
@@ -784,7 +995,7 @@ $$
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec24">Gaussian Elimination </h2>
<h2 id="___sec26">Gaussian Elimination </h2>
<p>
The basic idea of Gaussian elimination is to use the first equation to eliminate the first unknown \( x_1 \)
@@ -808,7 +1019,7 @@ what is called a backward substitution.
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec25">Gaussian Elimination </h2>
<h2 id="___sec27">Gaussian Elimination </h2>
This process can be expressed mathematically as
$$
@@ -826,7 +1037,7 @@ the result from the $j$th equation. We assume obviously that \( a_{11}\ne 0 \) a
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec26">Gaussian Elimination </h2>
<h2 id="___sec28">Gaussian Elimination </h2>
<p>
Our actual \( 4\times 4 \) example reads after the first operation
@@ -866,7 +1077,7 @@ $$
<p>
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<h2 id="___sec27">Gaussian Elimination </h2>
<h2 id="___sec29">Gaussian Elimination </h2>
<p>
The new coefficients are
@@ -902,7 +1113,7 @@ We see that the system of unknowns \( x_1,\dots,x_n \) is transformed into an \(
<p>
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<h2 id="___sec28">Gaussian Elimination </h2>
<h2 id="___sec30">Gaussian Elimination </h2>
<p>
This step is called forward substitution.
@@ -940,7 +1151,7 @@ adding \( 10^7+1 \). With single precision this results in \( 10^7 \).
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec29">Linear Algebra Methods </h2>
<h2 id="___sec31">Linear Algebra Methods </h2>
<ul>
<li> Gaussian elimination, \( O(2/3n^3) \) flops, general matrix</li>
@@ -953,7 +1164,7 @@ adding \( 10^7+1 \). With single precision this results in \( 10^7 \).
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<h2 id="___sec30">LU Decomposition </h2>
<h2 id="___sec32">LU Decomposition </h2>
<p>
The LU decomposition method means that we can rewrite
@@ -984,7 +1195,7 @@ $$
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec31">LU Decomposition </h2>
<h2 id="___sec33">LU Decomposition </h2>
<p>
LU decomposition forms the backbone of other algorithms in linear algebra, such as the
@@ -1013,7 +1224,7 @@ $$
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec32">LU Decomposition, why? </h2>
<h2 id="___sec34">LU Decomposition, why? </h2>
<p>
There are at least three main advantages with LU decomposition compared with standard Gaussian elimination:
@@ -1026,7 +1237,7 @@ There are at least three main advantages with LU decomposition compared with sta
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec33">LU Decomposition, linear equations </h2>
<h2 id="___sec35">LU Decomposition, linear equations </h2>
<p>
With the LU decomposition it is rather
@@ -1055,7 +1266,7 @@ $$ \mathbf{A} \mathbf{x} \equiv \mathbf{L} \mathbf{U} \mathbf{x} =\mathbf{w}. $$
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec34">LU Decomposition, linear equations </h2>
<h2 id="___sec36">LU Decomposition, linear equations </h2>
<p>
The previous equation can be calculated in two steps
@@ -1068,7 +1279,7 @@ to rewrite our system of linear equations as
$$ \mathbf{LUx}=\mathbf{w}, $$
and since the determinat of \( \mathbf{L} \) is equal to 1 (by construction
and since the determinant of \( \mathbf{L} \) is equal to 1 (by construction
since the diagonals of \( \mathbf{L} \) equal 1) we can use the inverse of
\( \mathbf{L} \) to obtain
@@ -1088,7 +1299,7 @@ through \( \mathbf{Ux}=\mathbf{y} \).
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec35">LU Decomposition, why? </h2>
<h2 id="___sec37">LU Decomposition, why? </h2>
<p>
For our four-dimentional example this takes the form
@@ -1121,7 +1332,7 @@ needed to solve the set of \( n \) linear equations.
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec36">LU Decomposition, linear equations </h2>
<h2 id="___sec38">LU Decomposition, linear equations </h2>
<p>
The algorithm goes as follows
@@ -1134,7 +1345,7 @@ The algorithm goes as follows
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec37">LU Decomposition, the inverse of a matrix </h2>
<h2 id="___sec39">LU Decomposition, the inverse of a matrix </h2>
<p>
If the inverse exists then
@@ -1152,7 +1363,7 @@ $$
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec38">LU Decomposition, the inverse of a matrix </h2>
<h2 id="___sec40">LU Decomposition, the inverse of a matrix </h2>
<p>
If we assume that the first column (that is column 1) of the inverse matrix
@@ -1186,7 +1397,7 @@ $$
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec39">LU Decomposition, the inverse </h2>
<h2 id="___sec41">LU Decomposition, the inverse </h2>
<p>
In a similar way we can compute the unknow entries of the second column,
@@ -1210,7 +1421,7 @@ and continue till we have solved all \( n \) sets of linear equations.
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec40"><a href="https://github.com/CompPhysics/ComputationalPhysicsMSU/blob/master/doc/Programs/CppQtCodesLectures/MatrixTest/main.cpp" target="_blank">Using Armadillo to perform an LU decomposition</a> </h2>
<h2 id="___sec42"><a href="https://github.com/CompPhysics/ComputationalPhysicsMSU/blob/master/doc/Programs/CppQtCodesLectures/MatrixTest/main.cpp" target="_blank">Using Armadillo to perform an LU decomposition</a> </h2>
<p>
<!-- code=c++ (!bc cppcod) typeset with pygments style "default" -->
@@ -1242,236 +1453,6 @@ and continue till we have solved all \( n \) sets of linear equations.
<span style="color: #008000; font-weight: bold">return</span> <span style="color: #666666">0</span>;
}
</pre></div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec41">Iterative methods, Chapter 6 </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
<ul>
<li> Direct solvers such as Gauss elimination and LU decomposition discussed in connection with project 1.</li>
<li> Iterative solvers such as Basic iterative solvers, Jacobi, Gauss-Seidel, Successive over-relaxation. These methods are easy to parallelize, as we will se later. Much used in solutions of partial differential equations.</li>
<li> Other iterative methods such as Krylov subspace methods with Generalized minimum residual (GMRES) and Conjugate gradient etc will not be discussed.</li>
</ul>
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec42">Iterative methods, Jacobi's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
It is a simple method for solving
$$
\mathbf{A}\mathbf{x}=\mathbf{b},
$$
where \( \mathbf{A} \) is a matrix and \( \mathbf{x} \) and \( \mathbf{b} \) are vectors. The vector \( \mathbf{x} \) is
the unknown.
<p>
It is an iterative scheme where we start with a guess for the unknown, and
after \( k+1 \) iterations we have
$$
\mathbf{x}^{(k+1)}= \mathbf{D}^{-1}(\mathbf{b}-(\mathbf{L}+\mathbf{U})\mathbf{x}^{(k)}),
$$
with \( \mathbf{A}=\mathbf{D}+\mathbf{U}+\mathbf{L} \) and
\( \mathbf{D} \) being a diagonal matrix, \( \mathbf{U} \) an upper triangular matrix and \( \mathbf{L} \) a lower triangular
matrix.
<p>
If the matrix \( \mathbf{A} \) is positive definite or diagonally dominant, one can show that this method will always converge to the exact solution.
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec43">Iterative methods, Jacobi's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
We can demonstrate Jacobi's method by this \( 4\times 4 \) matrix problem. We assume a guess
for the vector elements \( x_i^{(0)} \), a guess which represents our first iteration. The new
values are obtained by substitution
$$
\begin{align}
x_1^{(1)} =&(b_1-a_{12}x_2^{(0)} -a_{13}x_3^{(0)} - a_{14}x_4^{(0)})/a_{11} \nonumber \\
x_2^{(1)} =&(b_2-a_{21}x_1^{(0)} - a_{23}x_3^{(0)} - a_{24}x_4^{(0)})/a_{22} \nonumber \\
x_3^{(1)} =&(b_3- a_{31}x_1^{(0)} -a_{32}x_2^{(0)} -a_{34}x_4^{(0)})/a_{33} \nonumber \\
x_4^{(1)}=&(b_4-a_{41}x_1^{(0)} -a_{42}x_2^{(0)} - a_{43}x_3^{(0)})/a_{44}, \nonumber
\end{align}
$$
which after \( k+1 \) iterations reads
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k)} -a_{32}x_2^{(k)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k)} -a_{42}x_2^{(k)} - a_{43}x_3^{(k)})/a_{44}, \nonumber
\end{align}
$$
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec44">Iterative methods, Jacobi's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
We can generalize the above equations to
$$
x_i^{(k+1)}=(b_i-\sum_{j=1, j\ne i}^{n}a_{ij}x_j^{(k)})/a_{ii}
$$
or in an even more compact form as
$$ \mathbf{x}^{(k+1)}= \mathbf{D}^{-1}(\mathbf{b}-(\mathbf{L}+\mathbf{U})\mathbf{x}^{(k)}),
$$
with \( \mathbf{A}=\mathbf{D}+\mathbf{U}+\mathbf{L} \) and
\( \mathbf{D} \) being a diagonal matrix, \( \mathbf{U} \) an upper triangular matrix and \( \mathbf{L} \) a lower triangular
matrix.
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec45">Iterative methods, Gauss-Seidel's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
Our \( 4\times 4 \) matrix problem
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k)} -a_{32}x_2^{(k)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k)} -a_{42}x_2^{(k)} - a_{43}x_3^{(k)})/a_{44}, \nonumber
\end{align}
$$
can be rewritten as
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k+1)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k+1)} -a_{32}x_2^{(k+1)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k+1)} -a_{42}x_2^{(k+1)} - a_{43}x_3^{(k+1)})/a_{44}, \nonumber
\end{align}
$$
which allows us to utilize the preceding solution (forward substitution). This improves normally the convergence
behavior and leads to the Gauss-Seidel method!
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec46">Iterative methods, Gauss-Seidel's method </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
We can generalize
$$
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k+1)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k+1)} -a_{32}x_2^{(k+1)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k+1)} -a_{42}x_2^{(k+1)} - a_{43}x_3^{(k+1)})/a_{44}, \nonumber
\end{align}
$$
to the following form
$$
x^{(k+1)}_i = \frac{1}{a_{ii}} \left(b_i - \sum_{j > i}a_{ij}x^{(k)}_j - \sum_{j < i}a_{ij}x^{(k+1)}_j \right),\quad i=1,2,\ldots,n.
$$
The procedure is generally continued until the changes made by an iteration are below some tolerance.
<p>
The convergence properties of the Jacobi method and the
Gauss-Seidel method are dependent on the matrix \( \mathbf{A} \). These methods converge when
the matrix is symmetric positive-definite, or is strictly or irreducibly diagonally dominant.
Both methods sometimes converge even if these conditions are not satisfied.
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec47">Iterative methods, Successive over-relaxation </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
Given a square system of n linear equations with unknown \( \mathbf x \):
$$
\mathbf{A}\mathbf x = \mathbf b
$$
where
$$
\mathbf{A}=\begin{bmatrix} a_{11} & a_{12} & \cdots & a_{1n} \\ a_{21} & a_{22} & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\a_{n1} & a_{n2} & \cdots & a_{nn} \end{bmatrix}, \qquad \mathbf{x} = \begin{bmatrix} x_{1} \\ x_2 \\ \vdots \\ x_n \end{bmatrix} , \qquad \mathbf{b} = \begin{bmatrix} b_{1} \\ b_2 \\ \vdots \\ b_n \end{bmatrix}.
$$
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec48">Iterative methods, Successive over-relaxation </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
Then A can be decomposed into a diagonal component D, and strictly lower and upper triangular components L and U:
$$
\mathbf{A} =\mathbf{D} + \mathbf{L} + \mathbf{U},
$$
where
$$
D = \begin{bmatrix} a_{11} & 0 & \cdots & 0 \\ 0 & a_{22} & \cdots & 0 \\ \vdots & \vdots & \ddots & \vdots \\0 & 0 & \cdots & a_{nn} \end{bmatrix}, \quad L = \begin{bmatrix} 0 & 0 & \cdots & 0 \\ a_{21} & 0 & \cdots & 0 \\ \vdots & \vdots & \ddots & \vdots \\a_{n1} & a_{n2} & \cdots & 0 \end{bmatrix}, \quad U = \begin{bmatrix} 0 & a_{12} & \cdots & a_{1n} \\ 0 & 0 & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\0 & 0 & \cdots & 0 \end{bmatrix}.
$$
The system of linear equations may be rewritten as:
$$
(D+\omega L) \mathbf{x} = \omega \mathbf{b} - [\omega U + (\omega-1) D ] \mathbf{x}
$$
for a constant \( \omega > 1 \).
</div>
<p>
<!-- !split --><br><br><br><br><br><br><br><br><br><br>
<h2 id="___sec49">Iterative methods, Successive over-relaxation </h2>
<div class="alert alert-block alert-block alert-text-normal">
<b></b>
<p>
The method of successive over-relaxation is an iterative technique that solves the left hand side of this expression for \( x \), using previous value for \( x \) on the right hand side. Analytically, this may be written as:
$$
\mathbf{x}^{(k+1)} = (D+\omega L)^{-1} \big(\omega \mathbf{b} - [\omega U + (\omega-1) D ] \mathbf{x}^{(k)}\big).
$$
However, by taking advantage of the triangular form of \( (D+\omega L) \), the elements of \( x^{(k+1)} \) can be computed sequentially using forward substitution:
$$
x^{(k+1)}_i = (1-\omega)x^{(k)}_i + \frac{\omega}{a_{ii}} \left(b_i - \sum_{j > i} a_{ij}x^{(k)}_j - \sum_{j < i} a_{ij}x^{(k+1)}_j \right),\quad i=1,2,\ldots,n.
$$
The choice of relaxation factor is not necessarily easy, and depends upon the properties of the coefficient matrix. For symmetric, positive-definite matrices it can be proven that \( 0 < \omega < 2 \) will lead to convergence, but we are generally interested in faster convergence rather than just convergence.
</div>
<p>
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@@ -1,30 +1,53 @@
TITLE: Data analysis and Machine Learning Lectures: Linear Algebra methods
TITLE: Data analysis and Machine Learning Lectures: Linear Algebra and Handling of Arrays
AUTHOR: Morten Hjorth-Jensen {copyright, 1999-present|CC BY-NC} at Department of Physics, University of Oslo & Department of Physics and Astronomy and National Superconducting Cyclotron Laboratory, Michigan State University
DATE: today
!split
===== To do =====
===== Introduction =====
The aim of this set of lectures is to review some central linear algebra algorithms that we will need in our
data analysis part and in the construction of Machine Learning algorithms (ML).
This will allow us to introduce some central programming features of high-level languages like Python and
compiled languages like C++ and/or Fortran.
* add material on python handling of matrices and vectors
* keep c++ material?
As discussed in the introductory notes, these series of lectures focuses both on using
central Python packages like _tensorflow_ and _scikit-learn_ as well
as writing your own codes for some central ML algorithms. The
latter can be written in a language of your choice, be it Python, Julia, R,
Rust, C++, Fortran etc. In order to avoid confusion however, in these lectures we will limit our
attention to Python, C++ and Fortran.
!split
!split
===== Important Matrix and vector handling packages =====
The Numerical Recipes codes have been rewritten in Fortran 90/95 and
C/C++ by us. The original source codes are taken from the widely used
There are several central software packages for linear algebra and eigenvalue problems. Several of the more
popular ones have been wrapped into ofter software packages like those from the widely used text _Numerical Recipes_. The original source codes in many of the available packages are often taken from the widely used
software package LAPACK, which follows two other popular packages
developed in the 1970s, namely EISPACK and LINPACK.
developed in the 1970s, namely EISPACK and LINPACK. We describe them shortly here.
* LINPACK: package for linear equations and least square problems.
* LAPACK:package for solving symmetric, unsymmetric and generalized eigenvalue problems. From LAPACK's website URL: "http://www.netlib.org" it is possible to download for free all source codes from this library. Both C/C++ and Fortran versions are available.
* BLAS (I, II and III): (Basic Linear Algebra Subprograms) are routines that provide standard building blocks for performing basic vector and matrix operations. Blas I is vector operations, II vector-matrix operations and III matrix-matrix operations. Highly parallelized and efficient codes, all available for download from URL: "http://www.netlib.org".
_Add python material on linear algebra and array handling, text on numpy etc_
When dealing with matrices and vectors a central issue is memory
handling and allocation. If our code is written in Python the way we
declare these objects and the way they are handled, interpreted and
used by say a linear algebra library, requires codes that interface
our Python program with such libraries. For Python programmers,
_Numpy_ is by now the standard Python package for numerical arrays in
Python as well as the source of functions which act on these
arrays. These functions span from eigenvalue solvers to functions that
compute the mean value, variance or the covariance matrix. If you are
not familiar with how arrays are handled in say Python or compiled
languages like C++ and Fortran, the sections in this chapter may be
useful. For C++ programmer, _Armadillo_ is widely used library for
linear algebra and eigenvalue problems. In addition it offers a
convenient way to handle and organize arrays. We discuss this library
as well. Before we proceed we believe it may be convenient to repeat some basic features of
matrices and vectors.
!split
!split
===== Basic Matrix Features =====
!bblock Matrix properties reminder
@@ -48,6 +71,7 @@ _Add python material on linear algebra and array handling, text on numpy etc_
!split
===== Basic Matrix Features =====
!bblock
The inverse of a matrix is defined by
!bt
@@ -101,6 +125,171 @@ For an $N\times N$ matrix $\mathbf{A}$ the following properties are all equival
* $0$ is not eigenvalue of $\mathbf{A}$.
!eblock
!split
===== Numpy and arrays =====
"Numpy":"http://www.numpy.org/" provides an easy way to handle arrays in Python. The standard way to import this library is as
!bc pycod
import numpy as np
n = 10
x = np.random.normal(size=n)
print(x)
!ec
Here we have defined a vector $x$ with $n=10$ elements with its values given by the Normal distribution $N(0,1)$.
Another alternative is to declare a vector as follows
!bc pycod
import numpy as np
x = np.array([1, 2, 3])
print(x)
!ec
Here we have defined a vector with three elements, with $x_0=1$, $x_1=2$ and $x_2=3$. Note that both Python and C++
start numbering array elements from $0$ and on. This means that a vector with $n$ elements has a sequence of entities $x_0, x_1, x_2, \dots, x_{n-1}$. We could also let (recommended) Numpy to compute the logarithms of a specific array as
!bc pycod
import numpy as np
x = np.log(np.array([4, 7, 8]))
print(x)
!ec
Here we have used Numpy's unary function $np.log$. This function is
highly tuned to compute array elements since the code is vectorized
and does not require looping. We normaly recommend that you use the
Numpy intrinsic functions instead of the corresponding _log_ function
from Python's _math_ module. The looping is done explicitely by the
_np.log_ function. The alternative, and slower way to compute the
logarithms of a vector would be to write
!bc pycod
import numpy as np
from math import log
x = np.array([4, 7, 8])
for i in range(0, len(x)):
x[i] = log(x[i])
print(x)
!ec
We note that our code is much longer already and we need to import the _log_ function from the _math_ module.
The attentive reader will also notice that the output is $[1, 1, 2]$. Python interprets automacally our numbers as integers (like the _automatic_ keyword in C++). To change this we could define our array elements to be double precision numbers as
!bc pycod
import numpy as np
x = np.log(np.array([4, 7, 8], dtype = np.float64))
print(x)
!ec
or simply write them as double precision numbers (Python uses 64 bits as default for floating point type variables), that is
!bc pycod
import numpy as np
x = np.log(np.array([4.0, 7.0, 8.0])
print(x)
!ec
To check the number of bytes (remember that one byte contains eight bits for double precision variables), you can use simple use the _itemsize_ functionality (the array $x$ is actually an object which inherits the functionalities defined in Numpy) as
!bc pycod
import numpy as np
x = np.log(np.array([4.0, 7.0, 8.0])
print(x.itemsize)
!ec
!split
===== Matrices in Python =====
Having defined vectors, we are now ready to try out matrices. We can define a $3 \times 3 $ real matrix $\hat{A}$
as (recall that we user lowercase letters for vectors and uppercase letters for matrices)
!bc pycod
import numpy as np
A = np.log(np.array([ [4.0, 7.0, 8.0], [3.0, 10.0, 11.0], [4.0, 5.0, 7.0] ]))
print(A)
!ec
If we use the _shape_ function we would get $(3, 3)$ as output, that is verifying that our matrix is a $3\times 3$ matrix. We can slice the matrix and print for example the first column (Python organized matrix elements in a row-major order, see below) as
!bc pycod
import numpy as np
A = np.log(np.array([ [4.0, 7.0, 8.0], [3.0, 10.0, 11.0], [4.0, 5.0, 7.0] ]))
# print the first column, row-major order and elements start with 0
print(A[:,0])
!ec
We can continue this was by printing out other columns or rows. The example here prints out the second column
!bc pycod
import numpy as np
A = np.log(np.array([ [4.0, 7.0, 8.0], [3.0, 10.0, 11.0], [4.0, 5.0, 7.0] ]))
# print the first column, row-major order and elements start with 0
print(A[1,:])
!ec
Numpy contains many other functionalities that allow us to slice, subdivide etc etc arrays. We strongly recommend that you look up the "Numpy website for more details":"http://www.numpy.org/". Useful functions when defining a matrix are the _np.zeros_ function which declares a matrix of a given dimension and sets all elements to zero
!bc pycod
import numpy as np
n = 10
# define a matrix of dimension 10 x 10 and set all elements to zero
A = np.zeros( (n, n) )
print(A)
!ec
or initializing all elements to
!bc pycod
import numpy as np
n = 10
# define a matrix of dimension 10 x 10 and set all elements to one
A = np.ones( (n, n) )
print(A)
!ec
or as unitarily distributed random numbers (see the material on random number generators in the statistics part)
!bc pycod
import numpy as np
n = 10
# define a matrix of dimension 10 x 10 and set all elements to random numbers with x \in [0, 1]
A = np.random.rand(n, n)
print(A)
!ec
As we will see throughout these lectures, there are several extremely useful functionalities in Numpy.
As an example, consider the discussion of the covariance matrix. Suppose we have defined three vectors
$\hat{x}, \hat{y}, \hat{z}$ with $n$ elements each. The covariance matrix is defined as
!bt
\[
\hat{\Sigma} = \begin{bmatrix} \sigma_{xx} & \sigma_{xy} & \sigma_{xz} \\
\sigma_{yx} & \sigma_{yy} & \sigma_{yz} \\
\sigma_{zx} & \sigma_{zy} & \sigma_{zz}
\end{bmatrix},
\]
!et
where for example
!bt
\[
\sigma_{xy} =\frac{1}{n} \sum_{i=0}^{n-1}(x_i- \overline{x})(y_i- \overline{y}).
\]
!et
The Numpy function _np.cov_ calculates the covariance elements using the factor $1/(n-1)$ instead of $1/n$ since it assumes we do not have the exact mean values. For a more in-depth discussion of the covariance and covariance matrix and its meaning, we refer you to the lectures on statistics.
The following simple function uses the _np.vstack_ function which takes each vector of dimension $1\times n$ and produces a $ 3\times n$ matrix $\hat{W}$
!bt
\[
\hat{W} = \begin{bmatrix} x_0 & y_0 & z_0 \\
x_1 & y_1 & z_1 \\
x_2 & y_2 & z_2 \\
\dots & \dots & \dots \\
x_{n-2} & y_{n-2} & z_{n-2} \\
x_{n-1} & y_{n-1} & z_{n-1}
\end{bmatrix},
\]
!et
which in turn is converted into into the $3 times 3$ covariance matrix
$\hat{\Sigma}$ via the Numpy function _np.cov()_. In our review of
statistical functions and quantities we will discuss more about the
meaning of the covariance matrix. Here we note that we can calculate
the mean value of each set of samples $\hat{x}$ etc using the Numpy
function _np.mean(x)_. We can also extract the eigenvalues of the
covariance matrix through the _np.linalg.eig()_ function.
!bc pycod
# Importing various packages
import numpy as np
n = 100
x = np.random.normal(size=n)
print(np.mean(x))
y = 4+3*x+np.random.normal(size=n)
print(np.mean(y))
z = x**3+np.random.normal(size=n)
print(np.mean(z))
W = np.vstack((x, y, z))
Sigma = np.cov(W)
print(Sigma)
Eigvals, Eigvecs = np.linalg.eig(Sigma)
print(Eigvals)
!ec
!split
===== Matrix Handling in C/C++, Static and Dynamical allocation =====
@@ -744,7 +933,7 @@ to rewrite our system of linear equations as
!bt
\[ \mathbf{LUx}=\mathbf{w}, \]
!et
and since the determinat of $\mathbf{L}$ is equal to 1 (by construction
and since the determinant of $\mathbf{L}$ is equal to 1 (by construction
since the diagonals of $\mathbf{L}$ equal 1) we can use the inverse of
$\mathbf{L}$ to obtain
@@ -910,198 +1099,6 @@ int main()
}
!ec
!split
===== Iterative methods, Chapter 6 =====
!bblock
* Direct solvers such as Gauss elimination and LU decomposition discussed in connection with project 1.
* Iterative solvers such as Basic iterative solvers, Jacobi, Gauss-Seidel, Successive over-relaxation. These methods are easy to parallelize, as we will se later. Much used in solutions of partial differential equations.
* Other iterative methods such as Krylov subspace methods with Generalized minimum residual (GMRES) and Conjugate gradient etc will not be discussed.
!eblock
!split
===== Iterative methods, Jacobi's method =====
!bblock
It is a simple method for solving
!bt
\[
\mathbf{A}\mathbf{x}=\mathbf{b},
\]
!et
where $\mathbf{A}$ is a matrix and $\mathbf{x}$ and $\mathbf{b}$ are vectors. The vector $\mathbf{x}$ is
the unknown.
It is an iterative scheme where we start with a guess for the unknown, and
after $k+1$ iterations we have
!bt
\[
\mathbf{x}^{(k+1)}= \mathbf{D}^{-1}(\mathbf{b}-(\mathbf{L}+\mathbf{U})\mathbf{x}^{(k)}),
\]
!et
with $\mathbf{A}=\mathbf{D}+\mathbf{U}+\mathbf{L}$ and
$\mathbf{D}$ being a diagonal matrix, $\mathbf{U}$ an upper triangular matrix and $\mathbf{L}$ a lower triangular
matrix.
If the matrix $\mathbf{A}$ is positive definite or diagonally dominant, one can show that this method will always converge to the exact solution.
!eblock
!split
===== Iterative methods, Jacobi's method =====
!bblock
We can demonstrate Jacobi's method by this $4\times 4$ matrix problem. We assume a guess
for the vector elements $x_i^{(0)}$, a guess which represents our first iteration. The new
values are obtained by substitution
!bt
\begin{align}
x_1^{(1)} =&(b_1-a_{12}x_2^{(0)} -a_{13}x_3^{(0)} - a_{14}x_4^{(0)})/a_{11} \nonumber \\
x_2^{(1)} =&(b_2-a_{21}x_1^{(0)} - a_{23}x_3^{(0)} - a_{24}x_4^{(0)})/a_{22} \nonumber \\
x_3^{(1)} =&(b_3- a_{31}x_1^{(0)} -a_{32}x_2^{(0)} -a_{34}x_4^{(0)})/a_{33} \nonumber \\
x_4^{(1)}=&(b_4-a_{41}x_1^{(0)} -a_{42}x_2^{(0)} - a_{43}x_3^{(0)})/a_{44}, \nonumber
\end{align}
!et
which after $k+1$ iterations reads
!bt
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k)} -a_{32}x_2^{(k)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k)} -a_{42}x_2^{(k)} - a_{43}x_3^{(k)})/a_{44}, \nonumber
\end{align}
!et
!eblock
!split
===== Iterative methods, Jacobi's method =====
!bblock
We can generalize the above equations to
!bt
\[
x_i^{(k+1)}=(b_i-\sum_{j=1, j\ne i}^{n}a_{ij}x_j^{(k)})/a_{ii}
\]
!et
or in an even more compact form as
!bt
\[ \mathbf{x}^{(k+1)}= \mathbf{D}^{-1}(\mathbf{b}-(\mathbf{L}+\mathbf{U})\mathbf{x}^{(k)}),
\]
!et
with $\mathbf{A}=\mathbf{D}+\mathbf{U}+\mathbf{L}$ and
$\mathbf{D}$ being a diagonal matrix, $\mathbf{U}$ an upper triangular matrix and $\mathbf{L}$ a lower triangular
matrix.
!eblock
!split
===== Iterative methods, Gauss-Seidel's method =====
!bblock
Our $4\times 4$ matrix problem
!bt
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k)} -a_{32}x_2^{(k)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k)} -a_{42}x_2^{(k)} - a_{43}x_3^{(k)})/a_{44}, \nonumber
\end{align}
!et
can be rewritten as
!bt
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k+1)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k+1)} -a_{32}x_2^{(k+1)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k+1)} -a_{42}x_2^{(k+1)} - a_{43}x_3^{(k+1)})/a_{44}, \nonumber
\end{align}
!et
which allows us to utilize the preceding solution (forward substitution). This improves normally the convergence
behavior and leads to the Gauss-Seidel method!
!eblock
!split
===== Iterative methods, Gauss-Seidel's method =====
!bblock
We can generalize
!bt
\begin{align}
x_1^{(k+1)} =&(b_1-a_{12}x_2^{(k)} -a_{13}x_3^{(k)} - a_{14}x_4^{(k)})/a_{11} \nonumber \\
x_2^{(k+1)} =&(b_2-a_{21}x_1^{(k+1)} - a_{23}x_3^{(k)} - a_{24}x_4^{(k)})/a_{22} \nonumber \\
x_3^{(k+1)} =&(b_3- a_{31}x_1^{(k+1)} -a_{32}x_2^{(k+1)} -a_{34}x_4^{(k)})/a_{33} \nonumber \\
x_4^{(k+1)}=&(b_4-a_{41}x_1^{(k+1)} -a_{42}x_2^{(k+1)} - a_{43}x_3^{(k+1)})/a_{44}, \nonumber
\end{align}
!et
to the following form
!bt
\[
x^{(k+1)}_i = \frac{1}{a_{ii}} \left(b_i - \sum_{j > i}a_{ij}x^{(k)}_j - \sum_{j < i}a_{ij}x^{(k+1)}_j \right),\quad i=1,2,\ldots,n.
\]
!et
The procedure is generally continued until the changes made by an iteration are below some tolerance.
The convergence properties of the Jacobi method and the
Gauss-Seidel method are dependent on the matrix $\mathbf{A}$. These methods converge when
the matrix is symmetric positive-definite, or is strictly or irreducibly diagonally dominant.
Both methods sometimes converge even if these conditions are not satisfied.
!eblock
!split
===== Iterative methods, Successive over-relaxation =====
!bblock
Given a square system of n linear equations with unknown $\mathbf x$:
!bt
\[
\mathbf{A}\mathbf x = \mathbf b
\]
!et
where
!bt
\[
\mathbf{A}=\begin{bmatrix} a_{11} & a_{12} & \cdots & a_{1n} \\ a_{21} & a_{22} & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\a_{n1} & a_{n2} & \cdots & a_{nn} \end{bmatrix}, \qquad \mathbf{x} = \begin{bmatrix} x_{1} \\ x_2 \\ \vdots \\ x_n \end{bmatrix} , \qquad \mathbf{b} = \begin{bmatrix} b_{1} \\ b_2 \\ \vdots \\ b_n \end{bmatrix}.
\]
!et
!eblock
!split
===== Iterative methods, Successive over-relaxation =====
!bblock
Then A can be decomposed into a diagonal component D, and strictly lower and upper triangular components L and U:
!bt
\[
\mathbf{A} =\mathbf{D} + \mathbf{L} + \mathbf{U},
\]
!et
where
!bt
\[
D = \begin{bmatrix} a_{11} & 0 & \cdots & 0 \\ 0 & a_{22} & \cdots & 0 \\ \vdots & \vdots & \ddots & \vdots \\0 & 0 & \cdots & a_{nn} \end{bmatrix}, \quad L = \begin{bmatrix} 0 & 0 & \cdots & 0 \\ a_{21} & 0 & \cdots & 0 \\ \vdots & \vdots & \ddots & \vdots \\a_{n1} & a_{n2} & \cdots & 0 \end{bmatrix}, \quad U = \begin{bmatrix} 0 & a_{12} & \cdots & a_{1n} \\ 0 & 0 & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\0 & 0 & \cdots & 0 \end{bmatrix}.
\]
!et
The system of linear equations may be rewritten as:
!bt
\[
(D+\omega L) \mathbf{x} = \omega \mathbf{b} - [\omega U + (\omega-1) D ] \mathbf{x}
\]
!et
for a constant $\omega > 1$.
!eblock
!split
===== Iterative methods, Successive over-relaxation =====
!bblock
The method of successive over-relaxation is an iterative technique that solves the left hand side of this expression for $x$, using previous value for $x$ on the right hand side. Analytically, this may be written as:
!bt
\[
\mathbf{x}^{(k+1)} = (D+\omega L)^{-1} \big(\omega \mathbf{b} - [\omega U + (\omega-1) D ] \mathbf{x}^{(k)}\big).
\]
!et
However, by taking advantage of the triangular form of $(D+\omega L)$, the elements of $x^{(k+1)}$ can be computed sequentially using forward substitution:
!bt
\[
x^{(k+1)}_i = (1-\omega)x^{(k)}_i + \frac{\omega}{a_{ii}} \left(b_i - \sum_{j > i} a_{ij}x^{(k)}_j - \sum_{j < i} a_{ij}x^{(k+1)}_j \right),\quad i=1,2,\ldots,n.
\]
!et
The choice of relaxation factor is not necessarily easy, and depends upon the properties of the coefficient matrix. For symmetric, positive-definite matrices it can be proven that $0 < \omega < 2$ will lead to convergence, but we are generally interested in faster convergence rather than just convergence.
!eblock