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@@ -374,12 +374,9 @@ $$
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\begin{align}
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\gamma_{k+1}(h) &= cov\left( ({X}_{k+1})_{i}, ({X}_{k+1})_{j} \right) \nonumber \\
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&= \frac{1}{4}cov\left( ({X}_{k})_{2i-1} + ({X}_{k})_{2i}, ({X}_{k})_{2j-1} + ({X}_{k})_{2j} \right) \nonumber \\
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&=
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\begin{cases}
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\frac{1}{2}\gamma_{k}(2h) + \frac{1}{2}\gamma_k(2h+1) \qquad\qquad\quad \ \ \text{if $h = 0$}
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&= \frac{1}{2}\gamma_{k}(2h) + \frac{1}{2}\gamma_k(2h+1) \hspace{0.1cm} \mathrm{h = 0}
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\tag{22}\\
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\frac{1}{4}\gamma_k(2h-1) + \frac{1}{2}\gamma_k(2h) + \frac{1}{4}\gamma_k(2h+1) \quad \text{else}
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\end{cases}.
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&=\frac{1}{4}\gamma_k(2h-1) + \frac{1}{2}\gamma_k(2h) + \frac{1}{4}\gamma_k(2h+1) \quad \mathrm{else}
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\tag{23}
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\end{align}
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$$
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@@ -3011,19 +3011,18 @@ Using the
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definition of the blocking transformation and the distributive
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property of the covariance, it is clear that since \( h =|i-j| \)
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we can define
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<p> <br>
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$$
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\begin{align}
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\gamma_{k+1}(h) &= cov\left( ({X}_{k+1})_{i}, ({X}_{k+1})_{j} \right) \nonumber \\
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&= \frac{1}{4}cov\left( ({X}_{k})_{2i-1} + ({X}_{k})_{2i}, ({X}_{k})_{2j-1} + ({X}_{k})_{2j} \right) \nonumber \\
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&=
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\begin{cases}
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\frac{1}{2}\gamma_{k}(2h) + \frac{1}{2}\gamma_k(2h+1) \qquad\qquad\quad \ \ \text{if $h = 0$}
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&= \frac{1}{2}\gamma_{k}(2h) + \frac{1}{2}\gamma_k(2h+1) \hspace{0.1cm} \mathrm{h = 0}
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\tag{22}\\
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\frac{1}{4}\gamma_k(2h-1) + \frac{1}{2}\gamma_k(2h) + \frac{1}{4}\gamma_k(2h+1) \quad \text{else}
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\end{cases}.
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&=\frac{1}{4}\gamma_k(2h-1) + \frac{1}{2}\gamma_k(2h) + \frac{1}{4}\gamma_k(2h+1) \quad \mathrm{else}
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\tag{23}
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\end{align}
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$$
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<p> <br>
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<p>
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The quantity \( \vec{X} \) is asymptotic uncorrelated by assumption, \( \vec{X}_k \) is also asymptotic uncorrelated. Let's turn our attention to the variance of the sample mean \( V(\overline{X}) \).
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@@ -2969,12 +2969,9 @@ $$
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\begin{align}
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\gamma_{k+1}(h) &= cov\left( ({X}_{k+1})_{i}, ({X}_{k+1})_{j} \right) \nonumber \\
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&= \frac{1}{4}cov\left( ({X}_{k})_{2i-1} + ({X}_{k})_{2i}, ({X}_{k})_{2j-1} + ({X}_{k})_{2j} \right) \nonumber \\
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&=
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\begin{cases}
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\frac{1}{2}\gamma_{k}(2h) + \frac{1}{2}\gamma_k(2h+1) \qquad\qquad\quad \ \ \text{if $h = 0$}
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&= \frac{1}{2}\gamma_{k}(2h) + \frac{1}{2}\gamma_k(2h+1) \hspace{0.1cm} \mathrm{h = 0}
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\label{_auto12}\\
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\frac{1}{4}\gamma_k(2h-1) + \frac{1}{2}\gamma_k(2h) + \frac{1}{4}\gamma_k(2h+1) \quad \text{else}
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\end{cases}.
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&=\frac{1}{4}\gamma_k(2h-1) + \frac{1}{2}\gamma_k(2h) + \frac{1}{4}\gamma_k(2h+1) \quad \mathrm{else}
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\label{_auto13}
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\end{align}
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$$
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@@ -2974,12 +2974,9 @@ $$
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\begin{align}
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\gamma_{k+1}(h) &= cov\left( ({X}_{k+1})_{i}, ({X}_{k+1})_{j} \right) \nonumber \\
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&= \frac{1}{4}cov\left( ({X}_{k})_{2i-1} + ({X}_{k})_{2i}, ({X}_{k})_{2j-1} + ({X}_{k})_{2j} \right) \nonumber \\
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&=
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\begin{cases}
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\frac{1}{2}\gamma_{k}(2h) + \frac{1}{2}\gamma_k(2h+1) \qquad\qquad\quad \ \ \text{if $h = 0$}
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&= \frac{1}{2}\gamma_{k}(2h) + \frac{1}{2}\gamma_k(2h+1) \hspace{0.1cm} \mathrm{h = 0}
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\label{_auto12}\\
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\frac{1}{4}\gamma_k(2h-1) + \frac{1}{2}\gamma_k(2h) + \frac{1}{4}\gamma_k(2h+1) \quad \text{else}
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\end{cases}.
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&=\frac{1}{4}\gamma_k(2h-1) + \frac{1}{2}\gamma_k(2h) + \frac{1}{4}\gamma_k(2h+1) \quad \mathrm{else}
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\label{_auto13}
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\end{align}
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$$
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@@ -3837,9 +3837,7 @@
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"\n",
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"$$\n",
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"\\begin{equation} \n",
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"= \n",
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"\\begin{cases}\n",
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"\\frac{1}{2}\\gamma_{k}(2h) + \\frac{1}{2}\\gamma_k(2h+1) \\qquad\\qquad\\quad \\ \\ \\text{if $h = 0$} \n",
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"= \\frac{1}{2}\\gamma_{k}(2h) + \\frac{1}{2}\\gamma_k(2h+1) \\hspace{0.1cm} \\mathrm{h = 0} \n",
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"\\label{_auto12} \\tag{22}\n",
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"\\end{equation}\n",
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"$$"
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@@ -3854,8 +3852,7 @@
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"\n",
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"$$\n",
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"\\begin{equation} \n",
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"\\frac{1}{4}\\gamma_k(2h-1) + \\frac{1}{2}\\gamma_k(2h) + \\frac{1}{4}\\gamma_k(2h+1) \\quad \\text{else}\n",
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"\\end{cases}.\n",
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"=\\frac{1}{4}\\gamma_k(2h-1) + \\frac{1}{2}\\gamma_k(2h) + \\frac{1}{4}\\gamma_k(2h+1) \\quad \\mathrm{else}\n",
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"\\label{_auto13} \\tag{23}\n",
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"\\end{equation}\n",
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"$$"
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@@ -2420,11 +2420,8 @@ we can define
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\begin{align}
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\gamma_{k+1}(h) &= cov\left( ({X}_{k+1})_{i}, ({X}_{k+1})_{j} \right) \nonumber \\
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&= \frac{1}{4}cov\left( ({X}_{k})_{2i-1} + ({X}_{k})_{2i}, ({X}_{k})_{2j-1} + ({X}_{k})_{2j} \right) \nonumber \\
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&=
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\begin{cases}
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\frac{1}{2}\gamma_{k}(2h) + \frac{1}{2}\gamma_k(2h+1) \qquad\qquad\quad \ \ \text{if $h = 0$} \\
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\frac{1}{4}\gamma_k(2h-1) + \frac{1}{2}\gamma_k(2h) + \frac{1}{4}\gamma_k(2h+1) \quad \text{else}
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\end{cases}.
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&= \frac{1}{2}\gamma_{k}(2h) + \frac{1}{2}\gamma_k(2h+1) \hspace{0.1cm} \mathrm{h = 0} \\
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&=\frac{1}{4}\gamma_k(2h-1) + \frac{1}{2}\gamma_k(2h) + \frac{1}{4}\gamma_k(2h+1) \quad \mathrm{else}
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\end{align}
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!et
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