cleaning up typos

doc/pub/week38/html/._week38-bs012.html

@@ -457,7 +457,7 @@ If we assume that every column of \( \boldsymbol{X} \) is centered, which we can
 the sum \( \sum_{i=0}^{n-1} X_{ij} \)
 can be rewritten as
 $$
-\sum_{i=0}^{n-1} \left(X_{ij} - \frac{1}{n}\sum_{i=0}^{n-1} X_{ij}) = \sum_{i=0}^{n-1} X_{ij} - \sum_{i=0}^{n-1} \frac{1}{n} \sum_{i=0}^{n-1}X_{ij},
+\sum_{i=0}^{n-1} \left(X_{ij} - \frac{1}{n}\sum_{i=0}^{n-1} X_{ij}\right) = \sum_{i=0}^{n-1} X_{ij} - \sum_{i=0}^{n-1} \frac{1}{n} \sum_{i=0}^{n-1}X_{ij},
 $$
 
 resulting in
@@ -476,7 +476,7 @@ $$
 \beta_0 = \frac{1}{n}\sum_{i=0}^{n-1} y_i = \overline{\boldsymbol{y}},
 $$
 
-the average value of \( \boldsymbol{y] \).
+the average value of \( \boldsymbol{y} \).
 
 <p>
 Replacing \( y_i \) with \( y_i - \beta_0 = y_i - \overline{\boldsymbol{y}} \) in the cost function will give us (in vector-matrix disguise)

doc/pub/week38/html/._week38-bs013.html

@@ -443,7 +443,7 @@ y <span style="color: #666666">=</span> np<span style="color: #666666">.</span>e
 
 Maxpolydegree <span style="color: #666666">=</span> <span style="color: #666666">20</span>
 X <span style="color: #666666">=</span> np<span style="color: #666666">.</span>zeros((n,Maxpolydegree))
-We include explicitely the intercpt column
+<span style="color: #408080; font-style: italic">#We include explicitely the intercept column</span>
 X[:,<span style="color: #666666">0</span>] <span style="color: #666666">=</span> <span style="color: #666666">1.0</span>
 
 <span style="color: #008000; font-weight: bold">for</span> degree <span style="color: #AA22FF; font-weight: bold">in</span> <span style="color: #008000">range</span>(Maxpolydegree):

doc/pub/week38/html/week38-reveal.html

@@ -649,7 +649,7 @@ the sum \( \sum_{i=0}^{n-1} X_{ij} \)
 can be rewritten as
 <p>&nbsp;<br>
 $$
-\sum_{i=0}^{n-1} \left(X_{ij} - \frac{1}{n}\sum_{i=0}^{n-1} X_{ij}) = \sum_{i=0}^{n-1} X_{ij} - \sum_{i=0}^{n-1} \frac{1}{n} \sum_{i=0}^{n-1}X_{ij},
+\sum_{i=0}^{n-1} \left(X_{ij} - \frac{1}{n}\sum_{i=0}^{n-1} X_{ij}\right) = \sum_{i=0}^{n-1} X_{ij} - \sum_{i=0}^{n-1} \frac{1}{n} \sum_{i=0}^{n-1}X_{ij},
 $$
 <p>&nbsp;<br>
 
@@ -675,7 +675,7 @@ $$
 $$
 <p>&nbsp;<br>
 
-the average value of \( \boldsymbol{y] \).
+the average value of \( \boldsymbol{y} \).
 
 <p>
 Replacing \( y_i \) with \( y_i - \beta_0 = y_i - \overline{\boldsymbol{y}} \) in the cost function will give us (in vector-matrix disguise)
@@ -725,7 +725,7 @@ y = np.exp(-x**<span style="color: #B452CD">2</span>) + <span style="color: #B45
 
 Maxpolydegree = <span style="color: #B452CD">20</span>
 X = np.zeros((n,Maxpolydegree))
-We include explicitely the intercpt column
+<span style="color: #228B22">#We include explicitely the intercept column</span>
 X[:,<span style="color: #B452CD">0</span>] = <span style="color: #B452CD">1.0</span>
 
 <span style="color: #8B008B; font-weight: bold">for</span> degree <span style="color: #8B008B">in</span> <span style="color: #658b00">range</span>(Maxpolydegree):

doc/pub/week38/html/week38-solarized.html

@@ -799,7 +799,7 @@ If we assume that every column of \( \boldsymbol{X} \) is centered, which we can
 the sum \( \sum_{i=0}^{n-1} X_{ij} \)
 can be rewritten as
 $$
-\sum_{i=0}^{n-1} \left(X_{ij} - \frac{1}{n}\sum_{i=0}^{n-1} X_{ij}) = \sum_{i=0}^{n-1} X_{ij} - \sum_{i=0}^{n-1} \frac{1}{n} \sum_{i=0}^{n-1}X_{ij},
+\sum_{i=0}^{n-1} \left(X_{ij} - \frac{1}{n}\sum_{i=0}^{n-1} X_{ij}\right) = \sum_{i=0}^{n-1} X_{ij} - \sum_{i=0}^{n-1} \frac{1}{n} \sum_{i=0}^{n-1}X_{ij},
 $$
 
 resulting in
@@ -818,7 +818,7 @@ $$
 \beta_0 = \frac{1}{n}\sum_{i=0}^{n-1} y_i = \overline{\boldsymbol{y}},
 $$
 
-the average value of \( \boldsymbol{y] \).
+the average value of \( \boldsymbol{y} \).
 
 <p>
 Replacing \( y_i \) with \( y_i - \beta_0 = y_i - \overline{\boldsymbol{y}} \) in the cost function will give us (in vector-matrix disguise)
@@ -866,7 +866,7 @@ y = np.exp(-x**<span style="color: #B452CD">2</span>) + <span style="color: #B45
 
 Maxpolydegree = <span style="color: #B452CD">20</span>
 X = np.zeros((n,Maxpolydegree))
-We include explicitely the intercpt column
+<span style="color: #228B22">#We include explicitely the intercept column</span>
 X[:,<span style="color: #B452CD">0</span>] = <span style="color: #B452CD">1.0</span>
 
 <span style="color: #8B008B; font-weight: bold">for</span> degree <span style="color: #8B008B">in</span> <span style="color: #658b00">range</span>(Maxpolydegree):

doc/pub/week38/html/week38.html

@@ -804,7 +804,7 @@ If we assume that every column of \( \boldsymbol{X} \) is centered, which we can
 the sum \( \sum_{i=0}^{n-1} X_{ij} \)
 can be rewritten as
 $$
-\sum_{i=0}^{n-1} \left(X_{ij} - \frac{1}{n}\sum_{i=0}^{n-1} X_{ij}) = \sum_{i=0}^{n-1} X_{ij} - \sum_{i=0}^{n-1} \frac{1}{n} \sum_{i=0}^{n-1}X_{ij},
+\sum_{i=0}^{n-1} \left(X_{ij} - \frac{1}{n}\sum_{i=0}^{n-1} X_{ij}\right) = \sum_{i=0}^{n-1} X_{ij} - \sum_{i=0}^{n-1} \frac{1}{n} \sum_{i=0}^{n-1}X_{ij},
 $$
 
 resulting in
@@ -823,7 +823,7 @@ $$
 \beta_0 = \frac{1}{n}\sum_{i=0}^{n-1} y_i = \overline{\boldsymbol{y}},
 $$
 
-the average value of \( \boldsymbol{y] \).
+the average value of \( \boldsymbol{y} \).
 
 <p>
 Replacing \( y_i \) with \( y_i - \beta_0 = y_i - \overline{\boldsymbol{y}} \) in the cost function will give us (in vector-matrix disguise)
@@ -871,7 +871,7 @@ y <span style="color: #666666">=</span> np<span style="color: #666666">.</span>e
 
 Maxpolydegree <span style="color: #666666">=</span> <span style="color: #666666">20</span>
 X <span style="color: #666666">=</span> np<span style="color: #666666">.</span>zeros((n,Maxpolydegree))
-We include explicitely the intercpt column
+<span style="color: #408080; font-style: italic">#We include explicitely the intercept column</span>
 X[:,<span style="color: #666666">0</span>] <span style="color: #666666">=</span> <span style="color: #666666">1.0</span>
 
 <span style="color: #008000; font-weight: bold">for</span> degree <span style="color: #AA22FF; font-weight: bold">in</span> <span style="color: #008000">range</span>(Maxpolydegree):

doc/pub/week38/ipynb/week38.ipynb

@@ -628,7 +628,7 @@
    "metadata": {},
    "source": [
     "$$\n",
-    "\\sum_{i=0}^{n-1} \\left(X_{ij} - \\frac{1}{n}\\sum_{i=0}^{n-1} X_{ij}) = \\sum_{i=0}^{n-1} X_{ij} - \\sum_{i=0}^{n-1} \\frac{1}{n} \\sum_{i=0}^{n-1}X_{ij},\n",
+    "\\sum_{i=0}^{n-1} \\left(X_{ij} - \\frac{1}{n}\\sum_{i=0}^{n-1} X_{ij}\\right) = \\sum_{i=0}^{n-1} X_{ij} - \\sum_{i=0}^{n-1} \\frac{1}{n} \\sum_{i=0}^{n-1}X_{ij},\n",
     "$$"
    ]
   },
@@ -684,7 +684,7 @@
    "cell_type": "markdown",
    "metadata": {},
    "source": [
-    "the average value of $\\boldsymbol{y]$.\n",
+    "the average value of $\\boldsymbol{y}$.\n",
     "\n",
     "Replacing $y_i$ with $y_i - \\beta_0 = y_i - \\overline{\\boldsymbol{y}}$ in the cost function will give us (in vector-matrix disguise)"
    ]
@@ -743,7 +743,7 @@
     "\n",
     "Maxpolydegree = 20\n",
     "X = np.zeros((n,Maxpolydegree))\n",
-    "We include explicitely the intercpt column\n",
+    "#We include explicitely the intercept column\n",
     "X[:,0] = 1.0\n",
     "\n",
     "for degree in range(Maxpolydegree):\n",

doc/src/week38/week38.do.txt

@@ -441,7 +441,7 @@ the sum $\sum_{i=0}^{n-1} X_{ij}$
 can be rewritten as
 !bt
 \[
-\sum_{i=0}^{n-1} \left(X_{ij} - \frac{1}{n}\sum_{i=0}^{n-1} X_{ij}) = \sum_{i=0}^{n-1} X_{ij} - \sum_{i=0}^{n-1} \frac{1}{n} \sum_{i=0}^{n-1}X_{ij},
+\sum_{i=0}^{n-1} \left(X_{ij} - \frac{1}{n}\sum_{i=0}^{n-1} X_{ij}\right) = \sum_{i=0}^{n-1} X_{ij} - \sum_{i=0}^{n-1} \frac{1}{n} \sum_{i=0}^{n-1}X_{ij},
 \]
 !et
 resulting in
@@ -464,7 +464,7 @@ or
 \beta_0 = \frac{1}{n}\sum_{i=0}^{n-1} y_i = \overline{\bm{y}},
 \]
 !et
-the average value of $\bm{y]$.
+the average value of $\bm{y}$.
 
 Replacing $y_i$ with $y_i - \beta_0 = y_i - \overline{\bm{y}}$ in the cost function will give us (in vector-matrix disguise)
 !bt
@@ -506,7 +506,7 @@ y = np.exp(-x**2) + 1.5 * np.exp(-(x-2)**2)
 
 Maxpolydegree = 20
 X = np.zeros((n,Maxpolydegree))
-We include explicitely the intercpt column
+#We include explicitely the intercept column
 X[:,0] = 1.0
 
 for degree in range(Maxpolydegree):