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<!-- navigation toc: --> <li><a href="#___sec17" style="font-size: 80%;"><b>Writing our own PCA code</b></a></li>
<!-- navigation toc: --> <li><a href="#___sec18" style="font-size: 80%;">&nbsp;&nbsp;&nbsp;Compute the sample mean and center the data</a></li>
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<h2 id="___sec17" class="anchor">Writing our own PCA code </h2>
<p>
We will use a simple example first with two-dimensional data
drawn from a multivariate normal distribution with the following mean and covariance matrix:
$$
\mu = (-1,2) \qquad \Sigma = \begin{bmatrix} 4 & 2 \\
2 & 2
\end{bmatrix}
$$
Note that the mean refers to each column of data.
We will generate \( n = 1000 \) points \( X = \{ x_1, \ldots, x_N \} \) from
this distribution, and store them in the \( 1000 \times 2 \) matrix \( \boldsymbol{X} \).
<p>
The following Python code aids in setting up the data
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">numpy</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">np</span>
<span style="color: #008000; font-weight: bold">import</span> <span style="color: #0000FF; font-weight: bold">pandas</span> <span style="color: #008000; font-weight: bold">as</span> <span style="color: #0000FF; font-weight: bold">pd</span>
<span style="color: #008000; font-weight: bold">from</span> <span style="color: #0000FF; font-weight: bold">IPython.display</span> <span style="color: #008000; font-weight: bold">import</span> display
n <span style="color: #666666">=</span> <span style="color: #666666">100</span>
mean <span style="color: #666666">=</span> (<span style="color: #666666">-1</span>, <span style="color: #666666">2</span>)
cov <span style="color: #666666">=</span> [[<span style="color: #666666">4</span>, <span style="color: #666666">2</span>], [<span style="color: #666666">2</span>, <span style="color: #666666">2</span>]]
X <span style="color: #666666">=</span> np<span style="color: #666666">.</span>random<span style="color: #666666">.</span>multivariate_normal(mean, cov, n)
<span style="color: #408080; font-style: italic"># Print the X-matrix</span>
<span style="color: #008000; font-weight: bold">print</span>(X)
</pre></div>
<p>
Make thereafter a small Python code which writes out the data. Note that the function <b>multivariate</b> returns also the covariance discussed above and that it is defined by dividing by \( n-1 \) instead of \( n \).
<p>
Now we are going to implement the PCA algorithm. We will break it down into various substeps.
<h3 id="___sec18" class="anchor">Compute the sample mean and center the data </h3>
<p>
The first step of PCA is to compute the sample mean of the data and use it to center the data. Recall that the sample mean is
$$
\mu_n = \frac{1}{n} \sum_{i=1}^n x_i
$$
and the mean-centered data \( \bar{X} = \{ \bar{x}_1, \ldots, \bar{x}_n \} \) takes the form
$$
\bar{x}_i = x_i - \mu_n.
$$
When you are done with these steps, print out \( \mu_n \) to verify it is
close to \( \mu \) and plot your mean centered data to verify it is
centered at the origin! Compare your code with the functionality from <b>Scikit-Learn</b> discussed above.
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span>df <span style="color: #666666">=</span> pd<span style="color: #666666">.</span>DataFrame(X)
<span style="color: #408080; font-style: italic"># Pandas does the centering for us</span>
df <span style="color: #666666">=</span> df <span style="color: #666666">-</span>df<span style="color: #666666">.</span>mean()
display(df)
<span style="color: #408080; font-style: italic"># we center it ourselves</span>
X_centered <span style="color: #666666">=</span> X <span style="color: #666666">-</span> X<span style="color: #666666">.</span>mean(axis<span style="color: #666666">=0</span>)
<span style="color: #408080; font-style: italic"># test that we get the same as Pandas</span>
<span style="color: #008000; font-weight: bold">print</span>(X_centered<span style="color: #666666">-</span>df)
</pre></div>
<h3 id="___sec19" class="anchor">Compute the sample covariance </h3>
<p>
Now we are going to use the mean centered data to compute the sample covariance of the data. Recall it is given by:
$$
\begin{equation*}
\Sigma_n = \frac{1}{n-1} \sum_{i=1}^n \bar{x}_i^T \bar{x}_i = \frac{1}{n-1} \sum_{i=1}^n (x_i - \mu_n)^T (x_i - \mu_n)
\end{equation*}
$$
where the data points \( x_i \in \mathbb{R}^p \) (here in this example \( p = 2 \)) are column vectors and \( x^T \) is the transpose of \( x \).
Compare the computed covariance with the answer given above.
<h3 id="___sec20" class="anchor">Diagonalize the sample covariance matrix to obtain the principal components </h3>
<p>
Now we are ready to solve for the principal components! To do so we
diagonalize the sample covariance matrix \( \Sigma_n \). We can use the
function <b>np.linalg.eig</b> to do so. It will return the eigenvalues and
eigenvectors of \( \Sigma_n \). Once you have these, carry out the
following tasks:
<ul>
<li> Compute the percentage of the total variance captured by the first principal component</li>
<li> Plot the mean centered data and lines along the first and second principal components</li>
<li> Project the mean centered data onto the first and second principal components, and plot the projected data. What do you observe?</li>
<li> Approximate the data as</li>
</ul>
$$
\begin{equation*}
x_i \approx \tilde{x}_i := \mu_n + \langle x_i, v_0 \rangle v_0
\end{equation*}
$$
where \( v_0 \) is the first principal component. What do you observe?
<p>
Finally, collect all these steps and write your own PCA function and
compare this with the functionality included in <b>Scikit-Learn</b>.
Have the input be the data and have the output be the principal components and their associated eigenvalues, sorted in descending order. Can you think of a way to make it more efficient than the algorithm outlined above?
<p>
<!-- code=python (!bc pycod) typeset with pygments style "default" -->
<div class="highlight" style="background: #f8f8f8"><pre style="line-height: 125%"><span></span><span style="color: #408080; font-style: italic">#Now we do an SVD</span>
U, s, V <span style="color: #666666">=</span> np<span style="color: #666666">.</span>linalg<span style="color: #666666">.</span>svd(X_centered)
c1 <span style="color: #666666">=</span> V<span style="color: #666666">.</span>T[:, <span style="color: #666666">0</span>]
c2 <span style="color: #666666">=</span> V<span style="color: #666666">.</span>T[:, <span style="color: #666666">1</span>]
W2 <span style="color: #666666">=</span> V<span style="color: #666666">.</span>T[:, :<span style="color: #666666">2</span>]
X2D <span style="color: #666666">=</span> X_centered<span style="color: #666666">.</span>dot(W2)
<span style="color: #008000; font-weight: bold">print</span>(X2D)
<span style="color: #408080; font-style: italic">#thereafter we do a PCA with Scikit-learn</span>
<span style="color: #008000; font-weight: bold">from</span> <span style="color: #0000FF; font-weight: bold">sklearn.decomposition</span> <span style="color: #008000; font-weight: bold">import</span> PCA
pca <span style="color: #666666">=</span> PCA(n_components <span style="color: #666666">=</span> <span style="color: #666666">2</span>)
X2Dsl <span style="color: #666666">=</span> pca<span style="color: #666666">.</span>fit_transform(X)
<span style="color: #008000; font-weight: bold">print</span>(<span style="color: #BA2121">&quot;Check that we get the same&quot;</span>)
<span style="color: #008000; font-weight: bold">print</span>(X2D<span style="color: #666666">-</span>X2Dsl)
<span style="color: #008000; font-weight: bold">print</span>(pca<span style="color: #666666">.</span>components_<span style="color: #666666">.</span>T[:, <span style="color: #666666">0</span>])
</pre></div>
<p>
Finally, try out your own PCA function with other data sets.
<p>
<p>
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