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<h1>Exercises week 35</h1>
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<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#exercise-1-analytical-exercises">Exercise 1: Analytical exercises</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#exercise-2-making-your-own-data-and-exploring-scikit-learn">Exercise 2: making your own data and exploring scikit-learn</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#exercise-3-split-data-in-test-and-training-data">Exercise 3: Split data in test and training data</a></li>
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<!-- dom:TITLE: Exercises week 35 --><section class="tex2jax_ignore mathjax_ignore" id="exercises-week-35">
<h1>Exercises week 35<a class="headerlink" href="#exercises-week-35" title="Link to this heading">#</a></h1>
<p><strong>August 26-30, 2024</strong></p>
<p>Date: <strong>Deadline is Friday August 30 at midnight</strong></p>
<section id="exercise-1-analytical-exercises">
<h2>Exercise 1: Analytical exercises<a class="headerlink" href="#exercise-1-analytical-exercises" title="Link to this heading">#</a></h2>
<p>In this exercise we derive the expressions for various derivatives of
products of vectors and matrices. Such derivatives are central to the
optimization of various cost functions. Although we will often use
automatic differentiation in actual calculations, to be able to have
analytical expressions is extremely helpful in case we have simpler
derivatives as well as when we analyze various properties (like second
derivatives) of the chosen cost functions. Vectors are always written
as boldfaced lower case letters and matrices as upper case boldfaced
letters. You will find useful the notes from week 35 on derivatives of vectors and matrices.
See also the textbook of Faisal at al, chapter 5 and in particular sections 5.3-5.5 at <a class="github reference external" href="https://github.com/CompPhysics/MachineLearning/blob/master/doc/Textbooks/MathMLbook.pdf">CompPhysics/MachineLearning</a></p>
<p>Show that</p>
<div class="math notranslate nohighlight">
\[
\frac{\partial (\boldsymbol{a}^T\boldsymbol{x})}{\partial \boldsymbol{x}} = \boldsymbol{a}^T,
\]</div>
<p>and</p>
<div class="math notranslate nohighlight">
\[
\frac{\partial (\boldsymbol{a}^T\boldsymbol{A}\boldsymbol{a})}{\partial \boldsymbol{a}} = \boldsymbol{a}^T(\boldsymbol{A}+\boldsymbol{A}^T),
\]</div>
<p>and</p>
<div class="math notranslate nohighlight">
\[
\frac{\partial \left(\boldsymbol{x}-\boldsymbol{A}\boldsymbol{s}\right)^T\left(\boldsymbol{x}-\boldsymbol{A}\boldsymbol{s}\right)}{\partial \boldsymbol{s}} = -2\left(\boldsymbol{x}-\boldsymbol{A}\boldsymbol{s}\right)^T\boldsymbol{A},
\]</div>
<p>and finally find the second derivative of this function with respect to the vector <span class="math notranslate nohighlight">\(\boldsymbol{s}\)</span>. If we replace the vector <span class="math notranslate nohighlight">\(\boldsymbol{s}\)</span> with the unknown parameters <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span> used to define the ordinary least squares method, we end up with the equations that determine these parameters. The matrix <span class="math notranslate nohighlight">\(\boldsymbol{A}\)</span> is then the design matrix <span class="math notranslate nohighlight">\(\boldsymbol{X}\)</span> and <span class="math notranslate nohighlight">\(\boldsymbol{x}\)</span> here has to be replaced with the outputs <span class="math notranslate nohighlight">\(\boldsymbol{y}\)</span>.</p>
<p>The second derivative of the mean squared error is then proportional to the so-called Hessian matrix <span class="math notranslate nohighlight">\(\boldsymbol{H}=\boldsymbol{X}^T\boldsymbol{X}\)</span>.</p>
<p><strong>Hint</strong>: In these exercises it is always useful to write out with summation indices the various quantities. Take also a look at the weekly slides from week 35 and the various examples included there.</p>
<p>As an example, consider the function</p>
<div class="math notranslate nohighlight">
\[
f(\boldsymbol{x}) =\boldsymbol{A}\boldsymbol{x},
\]</div>
<p>which reads for a specific component <span class="math notranslate nohighlight">\(f_i\)</span> (we define the matrix <span class="math notranslate nohighlight">\(\boldsymbol{A}\)</span> to have dimension <span class="math notranslate nohighlight">\(n\times n\)</span> and the vector <span class="math notranslate nohighlight">\(\boldsymbol{x}\)</span> to have length <span class="math notranslate nohighlight">\(n\)</span>)</p>
<div class="math notranslate nohighlight">
\[
f_i =\sum_{j=0}^{n-1}a_{ij}x_j,
\]</div>
<p>which leads to</p>
<div class="math notranslate nohighlight">
\[
\frac{\partial f_i}{\partial x_j}= a_{ij},
\]</div>
<p>and written out in terms of the vector <span class="math notranslate nohighlight">\(\boldsymbol{x}\)</span> we have</p>
<div class="math notranslate nohighlight">
\[
\frac{\partial f(\boldsymbol{x})}{\partial \boldsymbol{x}}= \boldsymbol{A}.
\]</div>
</section>
<section id="exercise-2-making-your-own-data-and-exploring-scikit-learn">
<h2>Exercise 2: making your own data and exploring scikit-learn<a class="headerlink" href="#exercise-2-making-your-own-data-and-exploring-scikit-learn" title="Link to this heading">#</a></h2>
<p>We will generate our own dataset for a function <span class="math notranslate nohighlight">\(y(x)\)</span> where <span class="math notranslate nohighlight">\(x \in
[0,1]\)</span> and defined by random numbers computed with the uniform
distribution. The function <span class="math notranslate nohighlight">\(y\)</span> is a quadratic polynomial in <span class="math notranslate nohighlight">\(x\)</span> with
added stochastic noise according to the normal distribution <span class="math notranslate nohighlight">\(\cal
{N}(0,1)\)</span>. The following simple Python instructions define our <span class="math notranslate nohighlight">\(x\)</span>
and <span class="math notranslate nohighlight">\(y\)</span> values (with 100 data points).</p>
<div class="cell docutils container">
<div class="cell_input docutils container">
<div class="highlight-ipython3 notranslate"><div class="highlight"><pre><span></span><span class="kn">import</span> <span class="nn">numpy</span> <span class="k">as</span> <span class="nn">np</span>
<span class="n">x</span> <span class="o">=</span> <span class="n">np</span><span class="o">.</span><span class="n">random</span><span class="o">.</span><span class="n">rand</span><span class="p">(</span><span class="mi">100</span><span class="p">,</span><span class="mi">1</span><span class="p">)</span>
<span class="n">y</span> <span class="o">=</span> <span class="mf">2.0</span><span class="o">+</span><span class="mi">5</span><span class="o">*</span><span class="n">x</span><span class="o">*</span><span class="n">x</span><span class="o">+</span><span class="mf">0.1</span><span class="o">*</span><span class="n">np</span><span class="o">.</span><span class="n">random</span><span class="o">.</span><span class="n">randn</span><span class="p">(</span><span class="mi">100</span><span class="p">,</span><span class="mi">1</span><span class="p">)</span>
</pre></div>
</div>
</div>
</div>
<ol class="arabic simple">
<li><p>Write your own code (following the examples under the <a class="reference external" href="https://compphysics.github.io/MachineLearning/doc/LectureNotes/_build/html/chapter1.html">regression notes</a>) for computing the parametrization of the data set fitting a second-order polynomial.</p></li>
<li><p>Use thereafter <strong>scikit-learn</strong> (see again the examples in the slides for week 35) and compare with your own code. Note here that <strong>scikit-learn</strong> does not include, by default, the intercept. See the discussions on scaling your data in the slides for this week. This type of problems appear in particular if we fit a polynomial with an intercept.</p></li>
<li><p>Using scikit-learn, compute also the mean squared error, a risk metric corresponding to the expected value of the squared (quadratic) error defined as</p></li>
</ol>
<div class="math notranslate nohighlight">
\[
MSE(\boldsymbol{y},\boldsymbol{\tilde{y}}) = \frac{1}{n}
\sum_{i=0}^{n-1}(y_i-\tilde{y}_i)^2,
\]</div>
<p>and the <span class="math notranslate nohighlight">\(R^2\)</span> score function.
If <span class="math notranslate nohighlight">\(\tilde{\boldsymbol{y}}_i\)</span> is the predicted value of the <span class="math notranslate nohighlight">\(i-th\)</span> sample and <span class="math notranslate nohighlight">\(y_i\)</span> is the corresponding true value, then the score <span class="math notranslate nohighlight">\(R^2\)</span> is defined as</p>
<div class="math notranslate nohighlight">
\[
R^2(\boldsymbol{y}, \tilde{\boldsymbol{y}}) = 1 - \frac{\sum_{i=0}^{n - 1} (y_i - \tilde{y}_i)^2}{\sum_{i=0}^{n - 1} (y_i - \bar{y})^2},
\]</div>
<p>where we have defined the mean value of <span class="math notranslate nohighlight">\(\boldsymbol{y}\)</span> as</p>
<div class="math notranslate nohighlight">
\[
\bar{y} = \frac{1}{n} \sum_{i=0}^{n - 1} y_i.
\]</div>
<p>You can use the functionality included in scikit-learn. If you feel for it, you can use your own program and define functions which compute the above two functions.
Discuss the meaning of these results. Try also to vary the coefficient in front of the added stochastic noise term and discuss the quality of the fits.</p>
</section>
<section id="exercise-3-split-data-in-test-and-training-data">
<h2>Exercise 3: Split data in test and training data<a class="headerlink" href="#exercise-3-split-data-in-test-and-training-data" title="Link to this heading">#</a></h2>
<p>In this exercise we want you to to compute the MSE for the training
data and the test data as function of the complexity of a polynomial,
that is the degree of a given polynomial.</p>
<p>The aim is to reproduce Figure 2.11 of <a class="reference external" href="https://github.com/CompPhysics/MLErasmus/blob/master/doc/Textbooks/elementsstat.pdf">Hastie et al</a>.
Feel free to read the discussions leading to figure 2.11 of Hastie et al.</p>
<p>Our data is defined by <span class="math notranslate nohighlight">\(x\in [-3,3]\)</span> with a total of for example <span class="math notranslate nohighlight">\(n=100\)</span> data points. You should try to vary the number of data points <span class="math notranslate nohighlight">\(n\)</span> in your analysis.</p>
<div class="cell docutils container">
<div class="cell_input docutils container">
<div class="highlight-ipython3 notranslate"><div class="highlight"><pre><span></span><span class="n">np</span><span class="o">.</span><span class="n">random</span><span class="o">.</span><span class="n">seed</span><span class="p">()</span>
<span class="n">n</span> <span class="o">=</span> <span class="mi">100</span>
<span class="c1"># Make data set.</span>
<span class="n">x</span> <span class="o">=</span> <span class="n">np</span><span class="o">.</span><span class="n">linspace</span><span class="p">(</span><span class="o">-</span><span class="mi">3</span><span class="p">,</span> <span class="mi">3</span><span class="p">,</span> <span class="n">n</span><span class="p">)</span><span class="o">.</span><span class="n">reshape</span><span class="p">(</span><span class="o">-</span><span class="mi">1</span><span class="p">,</span> <span class="mi">1</span><span class="p">)</span>
<span class="n">y</span> <span class="o">=</span> <span class="n">np</span><span class="o">.</span><span class="n">exp</span><span class="p">(</span><span class="o">-</span><span class="n">x</span><span class="o">**</span><span class="mi">2</span><span class="p">)</span> <span class="o">+</span> <span class="mf">1.5</span> <span class="o">*</span> <span class="n">np</span><span class="o">.</span><span class="n">exp</span><span class="p">(</span><span class="o">-</span><span class="p">(</span><span class="n">x</span><span class="o">-</span><span class="mi">2</span><span class="p">)</span><span class="o">**</span><span class="mi">2</span><span class="p">)</span><span class="o">+</span> <span class="n">np</span><span class="o">.</span><span class="n">random</span><span class="o">.</span><span class="n">normal</span><span class="p">(</span><span class="mi">0</span><span class="p">,</span> <span class="mf">0.1</span><span class="p">,</span> <span class="n">x</span><span class="o">.</span><span class="n">shape</span><span class="p">)</span>
</pre></div>
</div>
</div>
</div>
<p>where <span class="math notranslate nohighlight">\(y\)</span> is the function we want to fit with a given polynomial.</p>
<p><strong>a)</strong>
Write a first code which sets up a design matrix <span class="math notranslate nohighlight">\(X\)</span> defined by a fifth-order polynomial and split your data set in training and test data.</p>
<p><strong>b)</strong>
Write thereafter (using either <strong>scikit-learn</strong> or your matrix inversion code using for example <strong>numpy</strong>)
and perform an ordinary least squares fitting and compute the mean squared error for the training data and the test data. These calculations should apply to a model given by a fifth-order polynomial. If you compare your own code with <em>scikit_learn</em>, not that the latter does not include by default the intercept. See the discussions on scaling your data in the slides for this week.</p>
<p><strong>c)</strong>
Add now a model which allows you to make polynomials up to degree <span class="math notranslate nohighlight">\(15\)</span>. Perform a standard OLS fitting of the training data and compute the MSE for the training and test data and plot both test and training data MSE as functions of the polynomial degree. Compare what you see with Figure 2.11 of Hastie et al. Comment your results. For which polynomial degree do you find an optimal MSE (smallest value)?</p>
</section>
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<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#exercise-1-analytical-exercises">Exercise 1: Analytical exercises</a></li>
<li class="toc-h2 nav-item toc-entry"><a class="reference internal nav-link" href="#exercise-2-making-your-own-data-and-exploring-scikit-learn">Exercise 2: making your own data and exploring scikit-learn</a></li>
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