update week 35
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@@ -539,7 +539,32 @@ $1\times n$ matrix.
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!split
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===== Derivatives, example 1 =====
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Let now $\bm{y}=\bm{A}\bm{x}$, where $\bm{A}$ is an $m\times n$ matrix and the matrix does not depend on $\bm{x}$. If we write out the vector $\bm{y}$
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Let now $\bm{y}=\bm{A}\bm{x}$, where $\bm{A}$ is an $m\times n$ matrix and the matrix does not depend on $\bm{x}$. If we write out the vector $\bm{y}$ compoment by component we have
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!bt
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\[
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y_i = \sum_{j=0}^{n-1}a_{ij}x_j,
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\]
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!et
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with $\all i=0,1,2,\dots,m-1$. The individual matrix elements of $\bm{A}$ are given by the symbol $a_{ij}$.
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It follows that the partial derivatives of $y_i$ with respect to $x_k$
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!bt
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\[
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\frac{\partial y_i }{\partial x_k}= a_{ik} \all i=0,1,2,\dots,m-1.
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\]
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!et
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From this we have, using the definition of the Jacobian
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!bt
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\[
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\frac{\partial \bm{y} }{\partial \bm{x}}= \bm{A}.
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\]
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!et
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!bt
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