typos and merge problems

This commit is contained in:
mhjensen
2020-11-27 14:09:28 +01:00
parent f4da3dd939
commit 9453f9ea93
72 changed files with 8550 additions and 8680 deletions
+11 -11
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@@ -57,19 +57,19 @@ space using other basis expansions such as higher-order polynomials,
wavelets, splines etc.
If our feature space is not easy to separate, as shown in the figure
<<<<<<< HEAD
here, we can achieve a better separation by introducing more complex
basis functions. The ideal would be, as shown in the next figure, to,
generated by the code below, we can achieve a better separation by introducing a more complex
basis functions. The ideal would be, as shown by the code example below, to,
via a specific transformation to obtain a separation between the
classes which is almost linear.
=======
here generated by the code below (see also Figures 12.2 and 12.3 of "Hastie et al.":"https://www.springer.com/gp/book/9780387848570"), we can achieve a better separation by introducing more complex
classes that is almost linear. See also Figures 12.2 and 12.3 of "Hastie et al.":"https://www.springer.com/gp/book/9780387848570".
We can achieve a better separation by introducing more complex
basis functions. The ideal would be (see Figures 12.2 and 12.3) to, via a specific transformation to
obtain a separation between the classes which is almost linear.
>>>>>>> origin/master
The change of basis, from $x\rightarrow z=\phi(x)$ leads to the same type of equations to be solved, except that
we need to introduce, for example, a polynomial transformation to a two-dimensional training set.
The change of basis, from $x\rightarrow z=\phi(x)$ leads to the same
type of equations to be solved, except that we need to introduce, for
example, a polynomial transformation to a two-dimensional training
set.
!bc pycod
import numpy as np
@@ -589,7 +589,7 @@ o To set up the matrix $\bm{G}$ we note that the inequalities $0\leq \lambda_i \
!split
===== Setting up $\bm{G}\bm{\lambda} \preceq \bm{h}$ =====
We have two constraints, $0\le \lambda_i$ and $\lambda_i \le C$. To do this we multiply the ones with the contraint
We have two constraints, $0\le \lambda_i$ and $\lambda_i \le C$. To do this we multiply the ones with the constraint
$\ge$ with $-1$ in order to get $\le$. It means that the problem $\bm{G}\bm{\lambda} \preceq \bm{h}$
can be written as
!bt
@@ -610,7 +610,7 @@ can be written as
\lambda_3 \\
\dots \\
\lambda_n \\
\end{bmatrix}\wedge
\end{bmatrix} \preceq
\begin{bmatrix} 0 \\
0 \\
0 \\