update of notes

This commit is contained in:
Morten Hjorth-Jensen
2022-12-11 22:07:05 +01:00
parent 8051880d95
commit 5473efe28f
70 changed files with 3777 additions and 1484 deletions
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@@ -2,12 +2,32 @@
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"id": "f63b8c1a",
"metadata": {
"editable": true
},
"source": [
"<!-- HTML file automatically generated from DocOnce source (https://github.com/doconce/doconce/)\n",
"doconce format html chapter4.do.txt -->"
]
},
{
"cell_type": "markdown",
"id": "9a284cf5",
"metadata": {
"editable": true
},
"source": [
"# Logistic Regression"
]
},
{
"cell_type": "markdown",
"id": "d78b73e2",
"metadata": {
"editable": true
},
"source": [
"# Logistic Regression\n",
"\n",
"\n",
"\n",
"## Logistic Regression\n",
"\n",
"In linear regression our main interest was centered on learning the\n",
@@ -22,7 +42,6 @@
"the product of the design matrices, linear regression gives then a\n",
"simple recipe for fitting our data.\n",
"\n",
"\n",
"Classification problems, however, are concerned with outcomes taking\n",
"the form of discrete variables (i.e. categories). We may for example,\n",
"on the basis of DNA sequencing for a number of patients, like to find\n",
@@ -39,7 +58,6 @@
"binary outcome, true or false, positive or negative, success or\n",
"failure etc.\n",
"\n",
"\n",
"Logistic regression will also serve as our stepping stone towards\n",
"neural network algorithms and supervised deep learning. For logistic\n",
"learning, the minimization of the cost function leads to a non-linear\n",
@@ -52,10 +70,16 @@
"\n",
"We note also that many of the topics discussed here on logistic \n",
"regression are also commonly used in modern supervised Deep Learning\n",
"models, as we will see later.\n",
"\n",
"\n",
"\n",
"models, as we will see later."
]
},
{
"cell_type": "markdown",
"id": "d0c829b4",
"metadata": {
"editable": true
},
"source": [
"## Basics\n",
"\n",
"We consider the case where the dependent variables, also called the\n",
@@ -76,7 +100,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "f1f4d5f2",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"y_i = \\begin{bmatrix} 0 & \\mathrm{no}\\\\ 1 & \\mathrm{yes} \\end{bmatrix}.\n",
@@ -85,7 +112,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "8e2f836b",
"metadata": {
"editable": true
},
"source": [
"Before moving to the logistic model, let us try to use our linear\n",
"regression model to classify these two outcomes. We could for example\n",
@@ -98,7 +128,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "6b58f1ba",
"metadata": {
"editable": true
},
"source": [
"<!-- Equation labels as ordinary links -->\n",
"<div id=\"_auto1\"></div>\n",
@@ -113,12 +146,14 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "54e3604b",
"metadata": {
"editable": true
},
"source": [
"where $\\boldsymbol{y}$ is a vector representing the possible outcomes, $\\boldsymbol{X}$ is our\n",
"$n\\times p$ design matrix and $\\boldsymbol{\\beta}$ represents our estimators/predictors.\n",
"\n",
"\n",
"The main problem with our function is that it takes values on the\n",
"entire real axis. In the case of logistic regression, however, the\n",
"labels $y_i$ are discrete variables. A typical example is the credit\n",
@@ -134,13 +169,13 @@
"favorable to use a ``soft\" classifier that outputs\n",
"the probability of a given category. This leads us to the logistic function.\n",
"\n",
"\n",
"The following example on data for coronary heart disease (CHD) as function of age may serve as an illustration. In the code here we read and plot whether a person has had CHD (output = 1) or not (output = 0). This ouput is plotted the person's against age. Clearly, the figure shows that attempting to make a standard linear regression fit may not be very meaningful."
]
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 1,
"id": "cd1dd1c5",
"metadata": {
"collapsed": false,
"editable": true
@@ -207,14 +242,18 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "2e06ee82",
"metadata": {
"editable": true
},
"source": [
"What we could attempt however is to plot the mean value for each group."
]
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 2,
"id": "a774f001",
"metadata": {
"collapsed": false,
"editable": true
@@ -233,7 +272,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "e102fa56",
"metadata": {
"editable": true
},
"source": [
"We are now trying to find a function $f(y\\vert x)$, that is a function which gives us an expected value for the output $y$ with a given input $x$.\n",
"In standard linear regression with a linear dependence on $x$, we would write this in terms of our model"
@@ -241,7 +283,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "75d995ba",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"f(y_i\\vert x_i)=\\beta_0+\\beta_1 x_i.\n",
@@ -250,7 +295,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "e2cacca5",
"metadata": {
"editable": true
},
"source": [
"This expression implies however that $f(y_i\\vert x_i)$ could take any\n",
"value from minus infinity to plus infinity. If we however let\n",
@@ -261,9 +309,16 @@
"us to a very popular model for the function $f$, namely the so-called\n",
"Sigmoid function or logistic model. We will consider this function as\n",
"representing the probability for finding a value of $y_i$ with a given\n",
"$x_i$.\n",
"\n",
"\n",
"$x_i$."
]
},
{
"cell_type": "markdown",
"id": "af9ac586",
"metadata": {
"editable": true
},
"source": [
"## The logistic function\n",
"\n",
"Another widely studied model, is the so-called \n",
@@ -281,7 +336,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "80aa3cbe",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"p(t) = \\frac{1}{1+\\mathrm \\exp{-t}}=\\frac{\\exp{t}}{1+\\mathrm \\exp{t}}.\n",
@@ -290,19 +348,30 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "28d49915",
"metadata": {
"editable": true
},
"source": [
"Note that $1-p(t)= p(-t)$.\n",
"\n",
"## Examples of likelihood functions used in logistic regression and nueral networks\n",
"\n",
"Note that $1-p(t)= p(-t)$."
]
},
{
"cell_type": "markdown",
"id": "eeff6cd9",
"metadata": {
"editable": true
},
"source": [
"## Examples of likelihood functions used in logistic regression and neural networks\n",
"\n",
"The following code plots the logistic function, the step function and other functions we will encounter from here and on."
]
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 3,
"id": "5ecec05e",
"metadata": {
"collapsed": false,
"editable": true
@@ -367,14 +436,20 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "5802efe3",
"metadata": {
"editable": true
},
"source": [
"We assume now that we have two classes with $y_i$ either $0$ or $1$. Furthermore we assume also that we have only two parameters $\\beta$ in our fitting of the Sigmoid function, that is we define probabilities"
]
},
{
"cell_type": "markdown",
"metadata": {},
"id": "f85d14ea",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\begin{align*}\n",
@@ -386,7 +461,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "6c4e0334",
"metadata": {
"editable": true
},
"source": [
"where $\\boldsymbol{\\beta}$ are the weights we wish to extract from data, in our case $\\beta_0$ and $\\beta_1$. \n",
"\n",
@@ -395,7 +473,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "df7facc9",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"p(y_i=0\\vert x_i, \\boldsymbol{\\beta}) = 1-p(y_i=1\\vert x_i, \\boldsymbol{\\beta}).\n",
@@ -404,7 +485,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "a920e6d8",
"metadata": {
"editable": true
},
"source": [
"In order to define the total likelihood for all possible outcomes from a \n",
"dataset $\\mathcal{D}=\\{(y_i,x_i)\\}$, with the binary labels\n",
@@ -416,7 +500,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "a780bfe1",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\begin{align*}\n",
@@ -427,14 +514,20 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "9f810a44",
"metadata": {
"editable": true
},
"source": [
"from which we obtain the log-likelihood and our **cost/loss** function"
]
},
{
"cell_type": "markdown",
"metadata": {},
"id": "3fac4ef4",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\mathcal{C}(\\boldsymbol{\\beta}) = \\sum_{i=1}^n \\left( y_i\\log{p(y_i=1|x_i,\\boldsymbol{\\beta})} + (1-y_i)\\log\\left[1-p(y_i=1|x_i,\\boldsymbol{\\beta}))\\right]\\right).\n",
@@ -443,14 +536,20 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "75aa2c14",
"metadata": {
"editable": true
},
"source": [
"Reordering the logarithms, we can rewrite the **cost/loss** function as"
]
},
{
"cell_type": "markdown",
"metadata": {},
"id": "780f2038",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\mathcal{C}(\\boldsymbol{\\beta}) = \\sum_{i=1}^n \\left(y_i(\\beta_0+\\beta_1x_i) -\\log{(1+\\exp{(\\beta_0+\\beta_1x_i)})}\\right).\n",
@@ -459,7 +558,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "c8c940aa",
"metadata": {
"editable": true
},
"source": [
"The maximum likelihood estimator is defined as the set of parameters that maximize the log-likelihood where we maximize with respect to $\\beta$.\n",
"Since the cost (error) function is just the negative log-likelihood, for logistic regression we have that"
@@ -467,7 +569,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "9d4a527b",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\mathcal{C}(\\boldsymbol{\\beta})=-\\sum_{i=1}^n \\left(y_i(\\beta_0+\\beta_1x_i) -\\log{(1+\\exp{(\\beta_0+\\beta_1x_i)})}\\right).\n",
@@ -476,23 +581,27 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "c1706606",
"metadata": {
"editable": true
},
"source": [
"This equation is known in statistics as the **cross entropy**. Finally, we note that just as in linear regression, \n",
"in practice we often supplement the cross-entropy with additional regularization terms, usually $L_1$ and $L_2$ regularization as we did for Ridge and Lasso regression.\n",
"\n",
"\n",
"The cross entropy is a convex function of the weights $\\boldsymbol{\\beta}$ and,\n",
"therefore, any local minimizer is a global minimizer. \n",
"\n",
"\n",
"Minimizing this\n",
"cost function with respect to the two parameters $\\beta_0$ and $\\beta_1$ we obtain"
]
},
{
"cell_type": "markdown",
"metadata": {},
"id": "fe8fb387",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\frac{\\partial \\mathcal{C}(\\boldsymbol{\\beta})}{\\partial \\beta_0} = -\\sum_{i=1}^n \\left(y_i -\\frac{\\exp{(\\beta_0+\\beta_1x_i)}}{1+\\exp{(\\beta_0+\\beta_1x_i)}}\\right),\n",
@@ -501,14 +610,20 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "bb564e81",
"metadata": {
"editable": true
},
"source": [
"and"
]
},
{
"cell_type": "markdown",
"metadata": {},
"id": "700c5443",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\frac{\\partial \\mathcal{C}(\\boldsymbol{\\beta})}{\\partial \\beta_1} = -\\sum_{i=1}^n \\left(y_ix_i -x_i\\frac{\\exp{(\\beta_0+\\beta_1x_i)}}{1+\\exp{(\\beta_0+\\beta_1x_i)}}\\right).\n",
@@ -517,7 +632,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "f442c956",
"metadata": {
"editable": true
},
"source": [
"Let us now define a vector $\\boldsymbol{y}$ with $n$ elements $y_i$, an\n",
"$n\\times p$ matrix $\\boldsymbol{X}$ which contains the $x_i$ values and a\n",
@@ -527,7 +645,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "83937f6f",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\frac{\\partial \\mathcal{C}(\\boldsymbol{\\beta})}{\\partial \\boldsymbol{\\beta}} = -\\boldsymbol{X}^T\\left(\\boldsymbol{y}-\\boldsymbol{p}\\right).\n",
@@ -536,7 +657,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "71819c1d",
"metadata": {
"editable": true
},
"source": [
"If we in addition define a diagonal matrix $\\boldsymbol{W}$ with elements \n",
"$p(y_i\\vert x_i,\\boldsymbol{\\beta})(1-p(y_i\\vert x_i,\\boldsymbol{\\beta})$, we can obtain a compact expression of the second derivative as"
@@ -544,7 +668,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "23dfd975",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\frac{\\partial^2 \\mathcal{C}(\\boldsymbol{\\beta})}{\\partial \\boldsymbol{\\beta}\\partial \\boldsymbol{\\beta}^T} = \\boldsymbol{X}^T\\boldsymbol{W}\\boldsymbol{X}.\n",
@@ -553,14 +680,20 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "6ca9f74b",
"metadata": {
"editable": true
},
"source": [
"Within a binary classification problem, we can easily expand our model to include multiple predictors. Our ratio between likelihoods is then with $p$ predictors"
]
},
{
"cell_type": "markdown",
"metadata": {},
"id": "ddb3d93a",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\log{ \\frac{p(\\boldsymbol{\\beta}\\boldsymbol{x})}{1-p(\\boldsymbol{\\beta}\\boldsymbol{x})}} = \\beta_0+\\beta_1x_1+\\beta_2x_2+\\dots+\\beta_px_p.\n",
@@ -569,14 +702,20 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "0cfae560",
"metadata": {
"editable": true
},
"source": [
"Here we defined $\\boldsymbol{x}=[1,x_1,x_2,\\dots,x_p]$ and $\\boldsymbol{\\beta}=[\\beta_0, \\beta_1, \\dots, \\beta_p]$ leading to"
]
},
{
"cell_type": "markdown",
"metadata": {},
"id": "7c427fc3",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"p(\\boldsymbol{\\beta}\\boldsymbol{x})=\\frac{ \\exp{(\\beta_0+\\beta_1x_1+\\beta_2x_2+\\dots+\\beta_px_p)}}{1+\\exp{(\\beta_0+\\beta_1x_1+\\beta_2x_2+\\dots+\\beta_px_p)}}.\n",
@@ -585,7 +724,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "6a6814bf",
"metadata": {
"editable": true
},
"source": [
"Till now we have mainly focused on two classes, the so-called binary\n",
"system. Suppose we wish to extend to $K$ classes. Let us for the sake\n",
@@ -594,7 +736,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "85282137",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\log{\\frac{p(C=1\\vert x)}{p(K\\vert x)}} = \\beta_{10}+\\beta_{11}x_1,\n",
@@ -603,14 +748,20 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "4864f76d",
"metadata": {
"editable": true
},
"source": [
"and"
]
},
{
"cell_type": "markdown",
"metadata": {},
"id": "390e9a55",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\log{\\frac{p(C=2\\vert x)}{p(K\\vert x)}} = \\beta_{20}+\\beta_{21}x_1,\n",
@@ -619,14 +770,20 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "c3f39c44",
"metadata": {
"editable": true
},
"source": [
"and so on till the class $C=K-1$ class"
]
},
{
"cell_type": "markdown",
"metadata": {},
"id": "92f32a03",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\log{\\frac{p(C=K-1\\vert x)}{p(K\\vert x)}} = \\beta_{(K-1)0}+\\beta_{(K-1)1}x_1,\n",
@@ -635,13 +792,14 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "677a5c4d",
"metadata": {
"editable": true
},
"source": [
"and the model is specified in term of $K-1$ so-called log-odds or\n",
"**logit** transformations.\n",
"\n",
"\n",
"\n",
"In our discussion of neural networks we will encounter the above again\n",
"in terms of a slightly modified function, the so-called **Softmax** function.\n",
"\n",
@@ -658,7 +816,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "fa70e3bf",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"p(C=k\\vert \\mathbf {x} )=\\frac{\\exp{(\\beta_{k0}+\\beta_{k1}x_1)}}{1+\\sum_{l=1}^{K-1}\\exp{(\\beta_{l0}+\\beta_{l1}x_1)}}.\n",
@@ -667,14 +828,20 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "4c59400c",
"metadata": {
"editable": true
},
"source": [
"It is easy to extend to more predictors. The final class is"
]
},
{
"cell_type": "markdown",
"metadata": {},
"id": "f4073652",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"p(C=K\\vert \\mathbf {x} )=\\frac{1}{1+\\sum_{l=1}^{K-1}\\exp{(\\beta_{l0}+\\beta_{l1}x_1)}},\n",
@@ -683,7 +850,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "810e872a",
"metadata": {
"editable": true
},
"source": [
"and they sum to one. Our earlier discussions were all specialized to\n",
"the case with two classes only. It is easy to see from the above that\n",
@@ -692,8 +862,16 @@
"To find the optimal parameters we would typically use a gradient\n",
"descent method. Newton's method and gradient descent methods are\n",
"discussed in the material on [optimization\n",
"methods](https://compphysics.github.io/MachineLearning/doc/pub/Splines/html/Splines-bs.html).\n",
"\n",
"methods](https://compphysics.github.io/MachineLearning/doc/pub/Splines/html/Splines-bs.html)."
]
},
{
"cell_type": "markdown",
"id": "f4ebc1da",
"metadata": {
"editable": true
},
"source": [
"## Wisconsin Cancer Data\n",
"\n",
"We show here how we can use a simple regression case on the breast\n",
@@ -703,7 +881,8 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 4,
"id": "b7a8cbac",
"metadata": {
"collapsed": false,
"editable": true
@@ -739,7 +918,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "10f74b93",
"metadata": {
"editable": true
},
"source": [
"In addition to the above scores, we could also study the covariance (and the correlation matrix).\n",
"We use **Pandas** to compute the correlation matrix."
@@ -747,7 +929,8 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 5,
"id": "d0b8025d",
"metadata": {
"collapsed": false,
"editable": true
@@ -792,7 +975,10 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "9d84a2aa",
"metadata": {
"editable": true
},
"source": [
"In the above example we note two things. In the first plot we display\n",
"the overlap of benign and malignant tumors as functions of the various\n",
@@ -811,7 +997,8 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 6,
"id": "6144ea0a",
"metadata": {
"collapsed": false,
"editable": true
@@ -823,14 +1010,18 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "5627f5ae",
"metadata": {
"editable": true
},
"source": [
"and then"
]
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 7,
"id": "a7c8662a",
"metadata": {
"collapsed": false,
"editable": true
@@ -842,17 +1033,46 @@
},
{
"cell_type": "markdown",
"metadata": {},
"id": "d03ee2a7",
"metadata": {
"editable": true
},
"source": [
"Diagonalizing this matrix we can in turn say something about which\n",
"features are of relevance and which are not. This leads us to\n",
"the classical Principal Component Analysis (PCA) theorem with\n",
"applications. This will be discussed later this semester ([week 43](https://compphysics.github.io/MachineLearning/doc/pub/week43/html/week43-bs.html))."
"applications. This will be discussed later this semester ([week 43](https://compphysics.github.io/MachineLearning/doc/pub/week43/html/week43-bs.html)).\n",
"\n",
"Here we present a further way to present our results in terms of a so-called **confusion matrix**, the cumulative gain and the **ROC** curve.\n",
"This way of displaying our data are based upon different ways to classify our possible outcomes. Before we proceed we need some definitions.\n",
"1. **TP**: true positive or in other words, something equivalent with a proper classification\n",
"\n",
"2. **TN**: true negative, which is equivalent with a correct rejection\n",
"\n",
"3. **FP**: false positive, or in simpler words something that is equivalent with a false alarm\n",
"\n",
"4. **FN**: false negative, which is mean to be equivalent with a miss.\n",
"\n",
"The total data set is then the sum of the true positive and true negative targets or outputs, labeled by $n$.\n",
"Based on this we can then define the accuracy score as the sum of correctly predicted **TP** and **TN** cases divided by the sum of true positive and treue negative events in our data set, or as"
]
},
{
"cell_type": "markdown",
"id": "44ce5095",
"metadata": {
"editable": true
},
"source": [
"$$\n",
"\\mathrm{Accuracy} = \\frac{\\sum_{i=0}^{n-1}I(y_i=\\tilde{y}_i)}{n}.\n",
"$$"
]
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 8,
"id": "24ff3dd3",
"metadata": {
"collapsed": false,
"editable": true
@@ -908,5 +1128,5 @@
],
"metadata": {},
"nbformat": 4,
"nbformat_minor": 4
"nbformat_minor": 5
}
+80 -88
View File
@@ -499,7 +499,8 @@ const thebe_selector_output = ".output, .cell_output"
<div>
<div class="tex2jax_ignore mathjax_ignore section" id="resampling-methods">
<!-- HTML file automatically generated from DocOnce source (https://github.com/doconce/doconce/)
doconce format html chapter3.do.txt --><div class="tex2jax_ignore mathjax_ignore section" id="resampling-methods">
<h1><span class="section-number">5. </span>Resampling Methods<a class="headerlink" href="#resampling-methods" title="Permalink to this headline"></a></h1>
<div class="section" id="introduction">
<h2><span class="section-number">5.1. </span>Introduction<a class="headerlink" href="#introduction" title="Permalink to this headline"></a></h2>
@@ -625,9 +626,8 @@ mean value <span class="math notranslate nohighlight">\(\boldsymbol{X}\boldsymbo
\[
\mathbb{E}(\boldsymbol{\beta}) = \mathbb{E}[ (\mathbf{X}^{\top} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1}\mathbf{X}^{T} \mathbb{E}[ \mathbf{Y}]=(\mathbf{X}^{T} \mathbf{X})^{-1} \mathbf{X}^{T}\mathbf{X}\boldsymbol{\beta}=\boldsymbol{\beta}.
\]</div>
<p>This means that the estimator of the regression parameters is unbiased.
v
We can also calculate the variance</p>
<p>This means that the estimator of the regression parameters is unbiased.</p>
<p>We can also calculate the variance</p>
<p>The variance of <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span> is</p>
<div class="math notranslate nohighlight">
\[\begin{split}
@@ -700,7 +700,7 @@ we discuss the</p>
<li><p>prediction error or simply the <strong>test error</strong> <span class="math notranslate nohighlight">\(\mathrm{Err_{Test}}\)</span>, where we have a fixed training set and the test error is the MSE arising from the data reserved for testing. We discuss also the</p></li>
<li><p>training error <span class="math notranslate nohighlight">\(\mathrm{Err_{Train}}\)</span>, which is the average loss over the training data.</p></li>
</ol>
<p>As our model becomes more and more complex, more of the training data tends to used. The training may thence adapt to more complicated structures in the data. This may lead to a decrease in the bias (see below for code example) and a slight increase of the variance for the test error.
<p>As our model becomes more and more complex, more of the training data tends to be used. The training may thence adapt to more complicated structures in the data. This may lead to a decrease in the bias (see below for code example) and a slight increase of the variance for the test error.
For a certain level of complexity the test error will reach minimum, before starting to increase again. The
training error reaches a saturation.</p>
<p>Two famous
@@ -760,10 +760,10 @@ number <span class="math notranslate nohighlight">\(i\)</span> is left out. Usin
</div>
</div>
<div class="cell_output docutils container">
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Runtime: 0.0903549 sec
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Runtime: 0.0893679 sec
Jackknife Statistics :
original bias std. error
100.107 100.097 0.150184
99.9524 99.9424 0.148854
</pre></div>
</div>
</div>
@@ -828,7 +828,7 @@ estimate any statistics thereof. In principle you never draw the
histogram of the relative frequency of <span class="math notranslate nohighlight">\(\widehat{\beta}^*\)</span>. Instead
you use the estimators corresponding to the statistic of interest. For
example, if you are interested in estimating the variance of <span class="math notranslate nohighlight">\(\widehat
\beta\)</span>, apply the etsimator <span class="math notranslate nohighlight">\(\widehat \sigma^2\)</span> to the values
\beta\)</span>, apply the estimator <span class="math notranslate nohighlight">\(\widehat \sigma^2\)</span> to the values
<span class="math notranslate nohighlight">\(\widehat \beta^*\)</span>.</p>
<p>Before we proceed however, we need to remind ourselves about a central
theorem in statistics, namely the so-called <strong>central limit theorem</strong>.
@@ -982,7 +982,7 @@ theorem.</p>
<div class="cell_output docutils container">
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Bootstrap Statistics :
original bias std. error
99.9033 14.9678 99.904 0.151348
100.188 15.1133 100.19 0.149655
</pre></div>
</div>
</div>
@@ -1004,7 +1004,7 @@ original bias std. error
</div>
</div>
<div class="cell_output docutils container">
<img alt="_images/chapter3_47_0.png" src="_images/chapter3_47_0.png" />
<img alt="_images/chapter3_51_0.png" src="_images/chapter3_51_0.png" />
</div>
</div>
</div>
@@ -1036,12 +1036,12 @@ C(\boldsymbol{X},\boldsymbol{\beta}) =\frac{1}{n}\sum_{i=0}^{n-1}(y_i-\tilde{y}_
\[
\mathbb{E}\left[(\boldsymbol{y}-\boldsymbol{\tilde{y}})^2\right]=\frac{1}{n}\sum_i(f_i-\mathbb{E}\left[\boldsymbol{\tilde{y}}\right])^2+\frac{1}{n}\sum_i(\tilde{y}_i-\mathbb{E}\left[\boldsymbol{\tilde{y}}\right])^2+\sigma^2.
\]</div>
<p>The three terms represent the square of the bias of the learning
<p>The first term represents the square of the bias of the learning
method, which can be thought of as the error caused by the simplifying
assumptions built into the method. The second term represents the
variance of the chosen model and finally the last terms is variance of
the error <span class="math notranslate nohighlight">\(\boldsymbol{\epsilon}\)</span>.</p>
<p>To derive this equation, we need to recall that the variance of <span class="math notranslate nohighlight">\(\boldsymbol{y}\)</span> and <span class="math notranslate nohighlight">\(\boldsymbol{\epsilon}\)</span> are both equal to <span class="math notranslate nohighlight">\(\sigma^2\)</span>. The mean value of <span class="math notranslate nohighlight">\(\boldsymbol{\epsilon}\)</span> is by definition equal to zero. Furthermore, the function <span class="math notranslate nohighlight">\(f\)</span> is not a stochastics variable, idem for <span class="math notranslate nohighlight">\(\boldsymbol{\tilde{y}}\)</span>.
<p>To derive this equation, we need to recall that the variance of <span class="math notranslate nohighlight">\(\boldsymbol{y}\)</span> and <span class="math notranslate nohighlight">\(\boldsymbol{\epsilon}\)</span> are both equal to <span class="math notranslate nohighlight">\(\sigma^2\)</span>. The mean value of <span class="math notranslate nohighlight">\(\boldsymbol{\epsilon}\)</span> is by definition equal to zero. Furthermore, the function <span class="math notranslate nohighlight">\(f\)</span> is not a stochastic variable, idem for <span class="math notranslate nohighlight">\(\boldsymbol{\tilde{y}}\)</span>.
We use a more compact notation in terms of the expectation value</p>
<div class="math notranslate nohighlight">
\[
@@ -1124,7 +1124,7 @@ Var: 0.0010479245926411787
0.013121574062587286 &gt;= 0.012073649469946107 + 0.0010479245926411787 = 0.013121574062587286
</pre></div>
</div>
<img alt="_images/chapter3_61_1.png" src="_images/chapter3_61_1.png" />
<img alt="_images/chapter3_65_1.png" src="_images/chapter3_65_1.png" />
</div>
</div>
<div class="cell docutils container">
@@ -1216,7 +1216,9 @@ Error: 0.03781367141738902
Bias^2: 0.03365768507152769
Var: 0.0041559863458613296
0.03781367141738902 &gt;= 0.03365768507152769 + 0.0041559863458613296 = 0.03781367141738902
Polynomial degree: 7
</pre></div>
</div>
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Polynomial degree: 7
Error: 0.027609773491022394
Bias^2: 0.022999498260366198
Var: 0.004610275230656182
@@ -1253,7 +1255,7 @@ Var: 0.20867052175003364
0.2284246870217162 &gt;= 0.01975416527168255 + 0.20867052175003364 = 0.2284246870217162
</pre></div>
</div>
<img alt="_images/chapter3_62_2.png" src="_images/chapter3_62_2.png" />
<img alt="_images/chapter3_66_3.png" src="_images/chapter3_66_3.png" />
</div>
</div>
<p>The bias-variance tradeoff summarizes the fundamental tension in
@@ -1378,7 +1380,7 @@ set, the higher, the less likely the model generalizes correctly from the
training data.
</pre></div>
</div>
<img alt="_images/chapter3_64_1.png" src="_images/chapter3_64_1.png" />
<img alt="_images/chapter3_68_1.png" src="_images/chapter3_68_1.png" />
</div>
</div>
<div class="cell docutils container">
@@ -1466,9 +1468,7 @@ training data.
</div>
<div class="cell_output docutils container">
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Degree of polynomial: 1
</pre></div>
</div>
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Mean squared error on training data: 439230.69504801
Mean squared error on training data: 439230.69504801
Mean squared error on test data: 481979.17861098
Degree of polynomial: 2
Mean squared error on training data: 115822.95008046
@@ -1508,12 +1508,12 @@ Mean squared error on test data: 0.17446471
Degree of polynomial: 13
Mean squared error on training data: 0.00759119
Mean squared error on test data: 1.08131003
Degree of polynomial: 14
Mean squared error on training data: 0.00472199
Mean squared error on test data: 0.81333804
</pre></div>
</div>
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Degree of polynomial: 15
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Degree of polynomial: 14
Mean squared error on training data: 0.00472199
Mean squared error on test data: 0.81333804
Degree of polynomial: 15
Mean squared error on training data: 0.00410478
Mean squared error on test data: 92.09172409
Degree of polynomial: 16
@@ -1528,12 +1528,12 @@ Mean squared error on test data: 108.27092910
Degree of polynomial: 19
Mean squared error on training data: 0.00156376
Mean squared error on test data: 1371.99051150
Degree of polynomial: 20
Mean squared error on training data: 0.00137818
Mean squared error on test data: 1887.86252988
</pre></div>
</div>
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Degree of polynomial: 21
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Degree of polynomial: 20
Mean squared error on training data: 0.00137818
Mean squared error on test data: 1887.86252988
Degree of polynomial: 21
Mean squared error on training data: 0.00118508
Mean squared error on test data: 14859.69908626
Degree of polynomial: 22
@@ -1548,12 +1548,12 @@ Mean squared error on test data: 1277.61702282
Degree of polynomial: 25
Mean squared error on training data: 0.00079129
Mean squared error on test data: 128664.31650694
Degree of polynomial: 26
Mean squared error on training data: 0.00076905
Mean squared error on test data: 19003.94822514
</pre></div>
</div>
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Degree of polynomial: 27
<div class="output stream highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>Degree of polynomial: 26
Mean squared error on training data: 0.00076905
Mean squared error on test data: 19003.94822514
Degree of polynomial: 27
Mean squared error on training data: 0.00068946
Mean squared error on test data: 2379.66219404
Degree of polynomial: 28
@@ -1564,13 +1564,13 @@ Mean squared error on training data: 0.00060705
Mean squared error on test data: 3250.17647619
</pre></div>
</div>
<div class="output stderr highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_94529/626635268.py:73: RuntimeWarning: divide by zero encountered in log10
<div class="output stderr highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_41811/626635268.py:73: RuntimeWarning: divide by zero encountered in log10
plt.plot(polynomial, np.log10(trainingerror), label=&#39;Training Error&#39;)
/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_94529/626635268.py:74: RuntimeWarning: divide by zero encountered in log10
/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_41811/626635268.py:74: RuntimeWarning: divide by zero encountered in log10
plt.plot(polynomial, np.log10(testerror), label=&#39;Test Error&#39;)
</pre></div>
</div>
<img alt="_images/chapter3_65_7.png" src="_images/chapter3_65_7.png" />
<img alt="_images/chapter3_69_6.png" src="_images/chapter3_69_6.png" />
</div>
</div>
</div>
@@ -1723,7 +1723,7 @@ cross-validation (LOOCV).</p>
</div>
</div>
<div class="cell_output docutils container">
<img alt="_images/chapter3_71_0.png" src="_images/chapter3_71_0.png" />
<img alt="_images/chapter3_75_0.png" src="_images/chapter3_75_0.png" />
</div>
</div>
<p>More examples of the application of cross-validation follow here.</p>
@@ -1800,14 +1800,14 @@ cross-validation (LOOCV).</p>
</div>
</div>
<div class="cell_output docutils container">
<div class="output stderr highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_94529/3817475779.py:63: RuntimeWarning: divide by zero encountered in log10
<div class="output stderr highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_41811/3817475779.py:63: RuntimeWarning: divide by zero encountered in log10
plt.plot(polynomial, np.log10(estimated_mse_sklearn), label=&#39;Test Error&#39;)
</pre></div>
</div>
<img alt="_images/chapter3_73_1.png" src="_images/chapter3_73_1.png" />
<img alt="_images/chapter3_77_1.png" src="_images/chapter3_77_1.png" />
</div>
</div>
<p>Note that we have kept the intercept in the first column of design matrix <span class="math notranslate nohighlight">\(\boldsymbol{X}\)</span>. When we call the corresponding <strong>Scikit-Learn</strong> function we need thus to set the intercept to <strong>False</strong>. Libraries like <strong>Scikit-Learn</strong> normally scale the design matrix and does not fit intercept. See the discussions below.</p>
<p>Note that we have kept the intercept in the first column of design matrix <span class="math notranslate nohighlight">\(\boldsymbol{X}\)</span>. When we call the corresponding <strong>Scikit-Learn</strong> function we need thus to set the intercept to <strong>False</strong>. Libraries like <strong>Scikit-Learn</strong> normally scale the design matrix and do not fit intercept. See the discussions below.</p>
</div>
<div class="section" id="more-on-rescaling-data">
<h2><span class="section-number">5.6. </span>More on Rescaling data<a class="headerlink" href="#more-on-rescaling-data" title="Permalink to this headline"></a></h2>
@@ -2077,7 +2077,7 @@ MSE with Sklearn intercept
0.004113634617443131
</pre></div>
</div>
<img alt="_images/chapter3_107_1.png" src="_images/chapter3_107_1.png" />
<img alt="_images/chapter3_112_1.png" src="_images/chapter3_112_1.png" />
</div>
</div>
<p>The intercept is the value of our output/target variable
@@ -2088,7 +2088,7 @@ the way we treat the intercept may give a larger or smaller MSE,
meaning that the MSE can be penalized by the value of the
intercept. Not including the intercept in the fit, means that the
regularization term does not include <span class="math notranslate nohighlight">\(\beta_0\)</span>. For different values
of <span class="math notranslate nohighlight">\(\lambda\)</span>, this may lead to differeing MSE values.</p>
of <span class="math notranslate nohighlight">\(\lambda\)</span>, this may lead to different MSE values.</p>
<p>To remind the reader, the regularization term, with the intercept in Ridge regression, is given by</p>
<div class="math notranslate nohighlight">
\[
@@ -2272,7 +2272,7 @@ MSE values for Scikit-Learn Ridge implementation
0.26409315307910025
</pre></div>
</div>
<img alt="_images/chapter3_115_1.png" src="_images/chapter3_115_1.png" />
<img alt="_images/chapter3_120_1.png" src="_images/chapter3_120_1.png" />
</div>
</div>
<p>The results here agree when we force <strong>Scikit-Learn</strong>s Ridge function to include the first column in our design matrix.
@@ -2475,7 +2475,7 @@ MSE values for Scikit-Learn Ridge implementation
0.002381316302584886
</pre></div>
</div>
<img alt="_images/chapter3_117_1.png" src="_images/chapter3_117_1.png" />
<img alt="_images/chapter3_122_1.png" src="_images/chapter3_122_1.png" />
</div>
</div>
<p>We see here, when compared to the code which includes explicitely the
@@ -2689,13 +2689,13 @@ linear system as an equation would reduce this down to
</div>
</div>
<div class="cell_output docutils container">
<div class="output stderr highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_94529/4162706317.py:6: MatplotlibDeprecationWarning: Auto-removal of grids by pcolor() and pcolormesh() is deprecated since 3.5 and will be removed two minor releases later; please call grid(False) first.
<div class="output stderr highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_41811/4162706317.py:6: MatplotlibDeprecationWarning: Auto-removal of grids by pcolor() and pcolormesh() is deprecated since 3.5 and will be removed two minor releases later; please call grid(False) first.
cb = fig.colorbar(im)
/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_94529/4162706317.py:7: UserWarning: FixedFormatter should only be used together with FixedLocator
/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_41811/4162706317.py:7: UserWarning: FixedFormatter should only be used together with FixedLocator
cb.ax.set_yticklabels(cb.ax.get_yticklabels(), fontsize=18)
</pre></div>
</div>
<img alt="_images/chapter3_148_1.png" src="_images/chapter3_148_1.png" />
<img alt="_images/chapter3_154_1.png" src="_images/chapter3_154_1.png" />
</div>
</div>
<p>It is interesting to note that OLS
@@ -2835,13 +2835,13 @@ with the form utilized in linear regression, viz.</p>
</div>
</div>
<div class="cell_output docutils container">
<div class="output stderr highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_94529/3777801602.py:6: MatplotlibDeprecationWarning: Auto-removal of grids by pcolor() and pcolormesh() is deprecated since 3.5 and will be removed two minor releases later; please call grid(False) first.
<div class="output stderr highlight-myst-ansi notranslate"><div class="highlight"><pre><span></span>/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_41811/3777801602.py:6: MatplotlibDeprecationWarning: Auto-removal of grids by pcolor() and pcolormesh() is deprecated since 3.5 and will be removed two minor releases later; please call grid(False) first.
cb = fig.colorbar(im)
/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_94529/3777801602.py:7: UserWarning: FixedFormatter should only be used together with FixedLocator
/var/folders/td/3yk470mj5p931p9dtkk0y6jw0000gn/T/ipykernel_41811/3777801602.py:7: UserWarning: FixedFormatter should only be used together with FixedLocator
cb.ax.set_yticklabels(cb.ax.get_yticklabels(), fontsize=18)
</pre></div>
</div>
<img alt="_images/chapter3_166_1.png" src="_images/chapter3_166_1.png" />
<img alt="_images/chapter3_172_1.png" src="_images/chapter3_172_1.png" />
</div>
</div>
<p>The results agree perfectly with our previous discussion where we used our own code.</p>
@@ -2850,23 +2850,15 @@ regression. In ridge regression we include a <strong>regularizer</strong>. This
involves a new cost function which leads to a new estimate for the
weights <span class="math notranslate nohighlight">\(\boldsymbol{\beta}\)</span>. This results in a penalized regression problem. The
cost function is given by</p>
<p>6
0</p>
<p>&lt;
&lt;
&lt;
!
!
M
A
T
H
_
B
L
O
C
K</p>
<!-- Equation labels as ordinary links -->
<div id="_auto11"></div>
<div class="math notranslate nohighlight">
\[
\begin{equation}
C(\boldsymbol{X}, \boldsymbol{\beta}; \lambda) = (\boldsymbol{X}\boldsymbol{\beta} - \boldsymbol{y})^T(\boldsymbol{X}\boldsymbol{\beta} - \boldsymbol{y}) + \lambda \boldsymbol{\beta}^T\boldsymbol{\beta}.
\label{_auto11} \tag{11}
\end{equation}
\]</div>
<div class="cell docutils container">
<div class="cell_input docutils container">
<div class="highlight-ipython3 notranslate"><div class="highlight"><pre><span></span><span class="n">_lambda</span> <span class="o">=</span> <span class="mf">0.1</span>
@@ -2885,13 +2877,13 @@ K</p>
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<p>In the <strong>Least Absolute Shrinkage and Selection Operator</strong> (LASSO)-method we get a third cost function.</p>
@@ -2922,13 +2914,13 @@ K</p>
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<p>It is quite striking how LASSO breaks the symmetry of the coupling
@@ -2977,49 +2969,49 @@ constant as opposed to ridge and OLS. We get a sparse solution with
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<p>We see that LASSO reaches a good solution for low
@@ -3068,7 +3060,7 @@ testing set that is close to the accuracy of the training set.</p>
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<p>From the above figure we can see that LASSO with <span class="math notranslate nohighlight">\(\lambda = 10^{-2}\)</span>
@@ -3160,13 +3152,13 @@ which polynomial fits the data best.</p>
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ax = fig.gca(projection=&#39;3d&#39;)
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fig.colorbar(surf, shrink=0.5, aspect=5)
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</li>
<li class="toc-h2 nav-item toc-entry">
<a class="reference internal nav-link" href="#examples-of-likelihood-functions-used-in-logistic-regression-and-nueral-networks">
6.4. Examples of likelihood functions used in logistic regression and nueral networks
<a class="reference internal nav-link" href="#examples-of-likelihood-functions-used-in-logistic-regression-and-neural-networks">
6.4. Examples of likelihood functions used in logistic regression and neural networks
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<a class="reference internal nav-link" href="#examples-of-likelihood-functions-used-in-logistic-regression-and-nueral-networks">
6.4. Examples of likelihood functions used in logistic regression and nueral networks
<a class="reference internal nav-link" href="#examples-of-likelihood-functions-used-in-logistic-regression-and-neural-networks">
6.4. Examples of likelihood functions used in logistic regression and neural networks
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<!-- HTML file automatically generated from DocOnce source (https://github.com/doconce/doconce/)
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<h1><span class="section-number">6. </span>Logistic Regression<a class="headerlink" href="#logistic-regression" title="Permalink to this headline"></a></h1>
<div class="section" id="id1">
<h2><span class="section-number">6.1. </span>Logistic Regression<a class="headerlink" href="#id1" title="Permalink to this headline"></a></h2>
@@ -647,7 +648,7 @@ the probability of a given category. This leads us to the logistic function.</p>
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<p>100 rows × 4 columns</p>
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<p>What we could attempt however is to plot the mean value for each group.</p>
@@ -665,7 +666,7 @@ the probability of a given category. This leads us to the logistic function.</p>
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<p>We are now trying to find a function <span class="math notranslate nohighlight">\(f(y\vert x)\)</span>, that is a function which gives us an expected value for the output <span class="math notranslate nohighlight">\(y\)</span> with a given input <span class="math notranslate nohighlight">\(x\)</span>.
@@ -704,8 +705,8 @@ p(t) = \frac{1}{1+\mathrm \exp{-t}}=\frac{\exp{t}}{1+\mathrm \exp{t}}.
\]</div>
<p>Note that <span class="math notranslate nohighlight">\(1-p(t)= p(-t)\)</span>.</p>
</div>
<div class="section" id="examples-of-likelihood-functions-used-in-logistic-regression-and-nueral-networks">
<h2><span class="section-number">6.4. </span>Examples of likelihood functions used in logistic regression and nueral networks<a class="headerlink" href="#examples-of-likelihood-functions-used-in-logistic-regression-and-nueral-networks" title="Permalink to this headline"></a></h2>
<div class="section" id="examples-of-likelihood-functions-used-in-logistic-regression-and-neural-networks">
<h2><span class="section-number">6.4. </span>Examples of likelihood functions used in logistic regression and neural networks<a class="headerlink" href="#examples-of-likelihood-functions-used-in-logistic-regression-and-neural-networks" title="Permalink to this headline"></a></h2>
<p>The following code plots the logistic function, the step function and other functions we will encounter from here and on.</p>
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@@ -767,9 +768,9 @@ p(t) = \frac{1}{1+\mathrm \exp{-t}}=\frac{\exp{t}}{1+\mathrm \exp{t}}.
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<p>We assume now that we have two classes with <span class="math notranslate nohighlight">\(y_i\)</span> either <span class="math notranslate nohighlight">\(0\)</span> or <span class="math notranslate nohighlight">\(1\)</span>. Furthermore we assume also that we have only two parameters <span class="math notranslate nohighlight">\(\beta\)</span> in our fitting of the Sigmoid function, that is we define probabilities</p>
@@ -996,8 +997,8 @@ We use <strong>Pandas</strong> to compute the correlation matrix.</p>
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<p>In the above example we note two things. In the first plot we display
@@ -1030,6 +1031,20 @@ matrix.</p>
features are of relevance and which are not. This leads us to
the classical Principal Component Analysis (PCA) theorem with
applications. This will be discussed later this semester (<a class="reference external" href="https://compphysics.github.io/MachineLearning/doc/pub/week43/html/week43-bs.html">week 43</a>).</p>
<p>Here we present a further way to present our results in terms of a so-called <strong>confusion matrix</strong>, the cumulative gain and the <strong>ROC</strong> curve.
This way of displaying our data are based upon different ways to classify our possible outcomes. Before we proceed we need some definitions.</p>
<ol class="simple">
<li><p><strong>TP</strong>: true positive or in other words, something equivalent with a proper classification</p></li>
<li><p><strong>TN</strong>: true negative, which is equivalent with a correct rejection</p></li>
<li><p><strong>FP</strong>: false positive, or in simpler words something that is equivalent with a false alarm</p></li>
<li><p><strong>FN</strong>: false negative, which is mean to be equivalent with a miss.</p></li>
</ol>
<p>The total data set is then the sum of the true positive and true negative targets or outputs, labeled by <span class="math notranslate nohighlight">\(n\)</span>.
Based on this we can then define the accuracy score as the sum of correctly predicted <strong>TP</strong> and <strong>TN</strong> cases divided by the sum of true positive and treue negative events in our data set, or as</p>
<div class="math notranslate nohighlight">
\[
\mathrm{Accuracy} = \frac{\sum_{i=0}^{n-1}I(y_i=\tilde{y}_i)}{n}.
\]</div>
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@@ -1099,18 +1114,9 @@ Please also refer to the documentation for alternative solver options:
n_iter_i = _check_optimize_result(
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<span class="ne">ModuleNotFoundError</span><span class="g g-Whitespace"> </span>Traceback (most recent call last)
<span class="nn">Input In [8],</span> in <span class="ni">&lt;cell line: 36&gt;</span><span class="nt">()</span>
<span class="g g-Whitespace"> </span><span class="mi">32</span> <span class="nb">print</span><span class="p">(</span><span class="n">accuracy</span><span class="p">)</span>
<span class="g g-Whitespace"> </span><span class="mi">33</span> <span class="nb">print</span><span class="p">(</span><span class="s2">&quot;Test set accuracy with Logistic Regression and scaled data: </span><span class="si">{:.2f}</span><span class="s2">&quot;</span><span class="o">.</span><span class="n">format</span><span class="p">(</span><span class="n">logreg</span><span class="o">.</span><span class="n">score</span><span class="p">(</span><span class="n">X_test_scaled</span><span class="p">,</span><span class="n">y_test</span><span class="p">)))</span>
<span class="ne">---&gt; </span><span class="mi">36</span> <span class="kn">import</span> <span class="nn">scikitplot</span> <span class="k">as</span> <span class="nn">skplt</span>
<span class="g g-Whitespace"> </span><span class="mi">37</span> <span class="n">y_pred</span> <span class="o">=</span> <span class="n">logreg</span><span class="o">.</span><span class="n">predict</span><span class="p">(</span><span class="n">X_test_scaled</span><span class="p">)</span>
<span class="g g-Whitespace"> </span><span class="mi">38</span> <span class="n">skplt</span><span class="o">.</span><span class="n">metrics</span><span class="o">.</span><span class="n">plot_confusion_matrix</span><span class="p">(</span><span class="n">y_test</span><span class="p">,</span> <span class="n">y_pred</span><span class="p">,</span> <span class="n">normalize</span><span class="o">=</span><span class="kc">True</span><span class="p">)</span>
<span class="ne">ModuleNotFoundError</span>: No module named &#39;scikitplot&#39;
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