update
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@@ -2915,7 +2915,7 @@ Show that
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and
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!bt
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\[
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\frac{\partial (\bm{a}^T\bm{A}\bm{a})}{\partial \bm{a}} = (\bm{A}+\bm{A}^T)\bm{a},
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\frac{\partial (\bm{a}^T\bm{A}\bm{a})}{\partial \bm{a}} = \bm{a}^T(\bm{A}+\bm{A}^T),
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\]
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!et
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and
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@@ -2953,3 +2953,5 @@ and written out in terms of the vector $\bm{x}$ we have
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\frac{\partial f(\bm{x})}{\partial \bm{x}}= \bm{A}.
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\]
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!et
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